結果

問題 No.796 well known
ユーザー kusirakusira
提出日時 2022-07-22 16:26:09
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 96 ms / 2,000 ms
コード長 5,806 bytes
コンパイル時間 351 ms
コンパイル使用メモリ 82,028 KB
実行使用メモリ 86,496 KB
最終ジャッジ日時 2024-07-04 00:00:23
合計ジャッジ時間 2,729 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 15
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#Python3/Pypy3
#-------------------------------------------------------------------
import bisect
import heapq
import collections
from itertools import groupby
import itertools
import math
import array
import string
import copy
#import numpy as np #Python3
#from scipy.sparse.csgraph import *
#from scipy.sparse import csr_matrix
#------------------------------------------------------------------
INF=10**18
MOD=10**9+7
mod=998244353
def YesNo(b): print("Yes") if b else print("No")
def YESNO(b): print("YES") if b else print("NO")
#---------------------------------------------------------------------
import sys
sys.setrecursionlimit(10 ** 5 + 10000)
input = sys.stdin.readline ####
def int1(x): return int(x) - 1
def II(): return int(input())
def MI(): return map(int, input().split())
def MI1(): return map(int1, input().split())
def LI(): return list(map(int, input().split()))
def LI1(): return list(map(int1, input().split()))
def LIS(): return list(map(int, SI()))
def LA(f): return list(map(f, input().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def SI(): return input().strip('\n')
def MS(): return input().split()
def LS(): return list(input().strip('\n'))
def LLS(rows_number): return [LS() for _ in range(rows_number)]
#------------------------------------------------------------------------
def CSL(A): #A
return [0] + list(itertools.accumulate(A))
def nF(n, m=0):
if(n==0):
return 0
P = 1
for i in range(1,n+1):
P *= i
if(m==0):
continue
P %= m
return P
def nPr(n, r, m=0): #nPr
if(n-r<0):
return 0
P = 1
for i in range(r,n+1):
P *= i
if(m==0):
continue
P %= m
return P
def nCr(n, r, m=0): #nCr
if(n-r<0):
return 0
N = 1
for i in range(r):
N *= n-i
if(m==0):
continue
N %= m
R = nF(r)
return N//R
def DL(n): #n
lower_divisors , upper_divisors = [], []
i = 1
while i*i <= n:
if n % i == 0:
lower_divisors.append(i)
if i != n // i:
upper_divisors.append(n//i)
i += 1
return lower_divisors + upper_divisors[::-1]
def PL(n): #n
prime_list = []
num_list=[]
for i in range(2, n+1):
if i not in num_list:
prime_list.append(i)
for j in range(i*i, n+1, i):
num_list.append(j)
return prime_list
def F2L(n): #2n => [[, ], ...]2
arr = []
temp = n
for i in range(2, int(-(-n**0.5//1))+1):
if temp%i==0:
cnt=0
while temp%i==0:
cnt+=1
temp //= i
arr.append([i, cnt])
if temp!=1:
arr.append([temp, 1])
if arr==[]:
arr.append([n, 1])
return arr
def DtoN(num_10,n): #10n(n<=10)
str_n = ''
while num_10:
if num_10%n>=10:
return -1
str_n += str(num_10%n)
num_10 //= n
return int(str_n[::-1])
def StoR(S: str):
grouped = groupby(S)
res = []
for k, v in grouped:
res.append((k, int(len(list(v)))))
return res
def RtoS(L: "list[tuple]"):
res = ""
for c, n in L:
res += c * int(n)
return res
def RtoSc(S: str) :
grouped = groupby(S)
res = ""
for k, v in grouped:
res += k + str(len(list(v)))
return res
def ED(dx,dy): #
return abs(dx + dy * 1j)
def dsin(d): #sin
return math.sin(math.radians(d))
def dcos(d): #cos
return math.cos(math.radians(d))
def RM(x,y,d,cx=0,cy=0): #P(x,y)A(cx,cy) => x, y
nx = (x-cx)*dcos(d)-(y-cy)*dsin(d)
ny = (x-cx)*dsin(d)+(y-cy)*dcos(d)
return [int(nx+cx+500),int(ny+cy+500)]
def engL(): return list(string.ascii_lowercase)
def ENGL(): return list(string.ascii_uppercase)
def TS(_str): #/
print('{}: {}'.format(_str, eval(_str)))
def BR(): #
print("---")
#----------------------------------------------------------------------
#-----------------------------------------------------------
'''
CSL(A) #A
nF(n, m) #n | m:mod()
nPr(n, r, m) #nPr | m:mod()
nCr(n, r, m) #,nCr | m:mod()
DL(n) #n
PL(n) #n
F2L(n) #2n => [[, ], ...]2
ED(dx,dy) # #
DtoN(num_10,n) #10n(n<=10)
StoR #/
RtoS #/
RtoSc #/
dsin(d): #sin
dcos(d): #cos
RM(x,y,d,cx,cy): #P(x,y)A(cx,cy)() => x, y
engL() #
ENGL() #
TS(_str) #/ => :××
BR() #
'''
#----------------------------------------------------------------------------
#AtCoder Easy Test v2numpy
n = II()
A = []
A.append(3)
s = 3*math.ceil((n-1)/3)+1-(n-2)
A.append(s)
for i in range(n-2):
A.append(1)
print(*A)
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