結果

問題 No.793 うし数列 2
ユーザー 👑 CleyLCleyL
提出日時 2022-08-18 17:23:35
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 2,155 bytes
コンパイル時間 808 ms
コンパイル使用メモリ 68,428 KB
最終ジャッジ日時 2025-01-30 23:52:51
ジャッジサーバーID
(参考情報)
judge4 / judge3
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ファイルパターン 結果
sample AC * 2
other AC * 21
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
using namespace std;
const long long MOD = 1000000007;
template <int mod>
struct ModInt{
int n;
ModInt():n(0){}
ModInt(int n_):n(n_ >= 0 ? n_%mod : mod - ((-n_)%mod) ){}
ModInt &operator+=(const ModInt &p){
if((n+=p.n) >= mod)n-=mod;
return *this;
}
ModInt &operator-=(const ModInt &p){
n+=mod-p.n;
if(n >= mod)n-=mod;
return *this;
}
ModInt &operator*=(const ModInt &p){
n = (int) ((1LL*n*p.n)%mod);
return *this;
}
ModInt &operator/=(const ModInt &p){
*this *= p.inverse();
return *this;
}
ModInt operator-() const {return ModInt(-n);}
ModInt operator+(const ModInt &p) const {return ModInt(*this) += p;}
ModInt operator-(const ModInt &p) const {return ModInt(*this) -= p;}
ModInt operator*(const ModInt &p) const {return ModInt(*this) *= p;}
ModInt operator/(const ModInt &p) const {return ModInt(*this) /= p;}
bool operator==(const ModInt &p) const {return n==p.n;}
bool operator<(const ModInt &p) const {return n<p.n;}
bool operator>(const ModInt &p) const {return n>p.n;}
bool operator>=(const ModInt &p) const {return n>=p.n;}
bool operator<=(const ModInt &p) const {return n<=p.n;}
bool operator!=(const ModInt &p) const {return n!=p.n;}
ModInt inverse() const {
int a = n,b = mod,u = 1,v = 0;
while(b){
int t = a/b;
a -= t*b; swap(a,b);
u -= t*v; swap(u,v);
}
return ModInt(u);
}
ModInt pow(int64_t z) const {
ModInt ret(1),mul(n);
while(z > 0){
if(z & 1) ret *= mul;
mul *= mul;
z >>= 1;
}
return ret;
}
friend ostream &operator<<(ostream &os, const ModInt &p){
return os << p.n;
}
friend istream &operator>>(istream &is, ModInt &a){
int64_t t;
is >> t;
a = ModInt<mod> (t);
return (is);
}
};
using mint = ModInt<MOD>;
template <typename T>
T uPow(T z,T n, T mod){
T ans = 1;
while(n != 0){
if(n%2){
ans*=z;
if(mod)ans%=mod;
}
n >>= 1;
z*=z;
if(mod)z%=mod;
}
return ans;
}
int main(){
long long n;cin>>n;
mint x = (((mint)uPow(10LL,n,MOD)*(mint)4)-(mint)1)/(mint)3;
cout << x << endl;
}
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