結果

問題 No.1904 Never giving up!
ユーザー akuaakua
提出日時 2022-09-18 11:36:35
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 301 ms / 2,000 ms
コード長 6,738 bytes
コンパイル時間 3,685 ms
コンパイル使用メモリ 191,860 KB
最終ジャッジ日時 2025-02-07 11:37:58
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 9
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <atcoder/all>
#include <iostream> // cout, endl, cin
#include <string> // string, to_string, stoi
#include <vector> // vector
#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound
#include <utility> // pair, make_pair
#include <tuple> // tuple, make_tuple
#include <cstdint> // int64_t, int*_t
#include <cstdio> // printf
#include <map> // map
#include <queue> // queue, priority_queue
#include <set> // set
#include <stack> // stack
#include <deque> // deque
#include <unordered_map> // unordered_map
#include <unordered_set> // unordered_set
#include <bitset> // bitset
#include <cctype> // isupper, islower, isdigit, toupper, tolower
#include <math.h>
#include <iomanip>
using namespace std;
using namespace atcoder;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repi(i, a, b) for (int i = (int)(a); i < (int)(b); i++)
typedef long long ll;
typedef unsigned long long ull;
const ll inf=1e18;
using graph = vector<vector<int> > ;
using P= pair<ll,ll>;
using vi=vector<int>;
using vvi=vector<vi>;
using vll=vector<ll>;
using vvll=vector<vll>;
using vp=vector<P>;
using vpp=vector<vp>;
//string T="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
//string S="abcdefghijklmnopqrstuvwxyz";
//g++ main.cpp -std=c++14 -I .
//cout <<setprecision(20);
//cout << fixed << setprecision(10);
//cin.tie(0); ios::sync_with_stdio(false);
const double PI = acos(-1);
int vx[]={0,1,0,-1,-1,1,1,-1},vy[]={1,0,-1,0,1,1,-1,-1};
ll pow_pow(ll x,ll n,ll mod){
if(n==0) return 1;
x%=mod;
ll res=pow_pow(x*x%mod,n/2,mod);
if(n&1)res=res*x%mod;
return res;
}
struct UnionFind { vector<int> par, siz; UnionFind(int n) : par(n, -1) , siz(n, 1) { } int root(int x) { if (par[x] == -1) return x;
else return par[x] = root(par[x]);
}
bool issame(int x, int y) {
return root(x) == root(y);
}
bool unite(int x, int y) {
x = root(x), y = root(y);
if (x == y) return false;
if (siz[x] < siz[y]) swap(x, y);
par[y] = x;
siz[x] += siz[y];
return true;
}
int size(int x) {
return siz[root(x)];
}
};
ll gcd(ll x,ll y){
if(y==0)return x;
return gcd(y,x%y);
}
ll lcm(ll x,ll y){
return ll(x/gcd(x,y))*y;
}
template<class T> bool chmin(T& a, T b) {
if (a > b) {
a = b;
return true;
}
else return false;
}
template<class T> bool chmax(T& a, T b) {
if (a < b) {
a = b;
return true;
}
else return false;
}
// https://youtu.be/L8grWxBlIZ4?t=9858
// https://youtu.be/ERZuLAxZffQ?t=4807 : optimize
// https://youtu.be/8uowVvQ_-Mo?t=1329 : division
const ll mod =1e9+7;
struct mint {
ll x; // typedef long long ll;
mint(ll x=0):x((x%mod+mod)%mod){}
mint operator-() const { return mint(-x);}
mint& operator+=(const mint a) {
if ((x += a.x) >= mod) x -= mod;
return *this;
}
mint& operator-=(const mint a) {
if ((x += mod-a.x) >= mod) x -= mod;
return *this;
}
mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
mint operator+(const mint a) const { return mint(*this) += a;}
mint operator-(const mint a) const { return mint(*this) -= a;}
mint operator*(const mint a) const { return mint(*this) *= a;}
mint pow(ll t) const {
if (!t) return 1;
mint a = pow(t>>1);
a *= a;
if (t&1) a *= *this;
return a;
}
// for prime mod
mint inv() const { return pow(mod-2);}
mint& operator/=(const mint a) { return *this *= a.inv();}
mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
// combination mod prime
// https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619
struct combination {
vector<mint> fact, ifact;
combination(int n):fact(n+1),ifact(n+1) {
//assert(n < mod);
fact[0] = 1;
for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
ifact[n] = fact[n].inv();
for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
}
mint operator()(int n, int k) {
if (k < 0 || k > n) return 0;
return fact[n]*ifact[k]*ifact[n-k];
}
mint p(int n, int k) {
return fact[n]*ifact[n-k];
}
} c(20000050);
using vm=vector<mint> ;
using vvm=vector<vm> ;
ll sqrt_(ll x) {
ll l = 0, r = ll(3e9)+1;
while (l+1<r) {
ll c = (l+r)/2;
if (c*c <= x) l = c; else r = c;
}
return l;
}
int valid(int x,int y,int h,int w){
if(x>=0 && y>=0 && x<h && y<w)return 1;
else return 0;
}
ll comb[51][51];
void init_comb(){
comb[0][0]=1;
for(int i=1; i<=50; i++){
for(int j=0; j<=i; j++){
if(j==0 || j==i)comb[i][j]=1;
else comb[i][j]=comb[i-1][j]+comb[i-1][j-1];
}
}
}
ll nCk(int n,int k){
return comb[n][k];
}
struct edge{
int to; ll cost;
edge(int to,ll cost) : to(to),cost(cost) {}
};
using ve=vector<edge>;
using vve =vector<ve>;
map<ll,ll>d;
void comp(vll&a){
set<ll>s(a.begin(),a.end());
int cnt=0;
for(auto y:s)d[y]=cnt++;
for(auto&y:a)y=d[y];
}
const int MAX_ROW = 510; // to be set appropriately
const int MAX_COL = 510; // to be set appropriately
struct BitMatrix {
int H, W;
bitset<MAX_COL> val[MAX_ROW];
BitMatrix(int m = 1, int n = 1) : H(m), W(n) {}
inline bitset<MAX_COL>& operator [] (int i) {return val[i];}
};
int GaussJordan(BitMatrix &A, bool is_extended = false) {
int rank = 0;
for (int col = 0; col < A.W; ++col) {
if (is_extended && col == A.W - 1) break;
int pivot = -1;
for (int row = rank; row < A.H; ++row) {
if (A[row][col]) {
pivot = row;
break;
}
}
if (pivot == -1) continue;
swap(A[pivot], A[rank]);
for (int row = 0; row < A.H; ++row) {
if (row != rank && A[row][col]) A[row] ^= A[rank];
}
++rank;
}
return rank;
}
int linear_equation(BitMatrix A, vector<int> b, vector<int> &res) {
int m = A.H, n = A.W;
BitMatrix M(m, n + 1);
for (int i = 0; i < m; ++i) {
for (int j = 0; j < n; ++j) M[i][j] = A[i][j];
M[i][n] = b[i];
}
int rank = GaussJordan(M, true);
// check if it has no solution
for (int row = rank; row < m; ++row) if (M[row][n]) return -1;
// answer
res.assign(n, 0);
for (int i = 0; i < rank; ++i) res[i] = M[i][n];
return rank;
};
using np=pair<P,int>;
int main(){cin.tie(0); ios::sync_with_stdio(false);
int n; cin >> n;
map<int,ll> mp;
vll a(n);rep(i,n)cin >> a[i];
ll ans=1;
rep(i,n)ans*=(i+1);
rep(i,n)mp[a[i]]++;
for(auto u:mp){
for(int i=1; i<=u.second; i++)ans/=i;
}
cout << ans << endl;
}
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