結果
問題 | No.1916 Making Palindrome on Gird |
ユーザー | akua |
提出日時 | 2022-09-18 12:14:18 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 646 ms / 3,000 ms |
コード長 | 7,694 bytes |
コンパイル時間 | 4,044 ms |
コンパイル使用メモリ | 199,480 KB |
実行使用メモリ | 450,560 KB |
最終ジャッジ日時 | 2024-12-22 01:15:55 |
合計ジャッジ時間 | 25,556 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 557 ms
450,304 KB |
testcase_01 | AC | 562 ms
450,176 KB |
testcase_02 | AC | 561 ms
450,304 KB |
testcase_03 | AC | 555 ms
450,304 KB |
testcase_04 | AC | 556 ms
450,304 KB |
testcase_05 | AC | 563 ms
450,304 KB |
testcase_06 | AC | 566 ms
450,304 KB |
testcase_07 | AC | 564 ms
450,304 KB |
testcase_08 | AC | 558 ms
450,304 KB |
testcase_09 | AC | 564 ms
450,304 KB |
testcase_10 | AC | 565 ms
450,304 KB |
testcase_11 | AC | 559 ms
450,304 KB |
testcase_12 | AC | 555 ms
450,304 KB |
testcase_13 | AC | 583 ms
450,420 KB |
testcase_14 | AC | 585 ms
450,464 KB |
testcase_15 | AC | 595 ms
450,340 KB |
testcase_16 | AC | 585 ms
450,384 KB |
testcase_17 | AC | 629 ms
450,432 KB |
testcase_18 | AC | 638 ms
450,384 KB |
testcase_19 | AC | 639 ms
450,396 KB |
testcase_20 | AC | 646 ms
450,432 KB |
testcase_21 | AC | 641 ms
450,560 KB |
testcase_22 | AC | 640 ms
450,304 KB |
testcase_23 | AC | 634 ms
450,304 KB |
testcase_24 | AC | 621 ms
450,408 KB |
testcase_25 | AC | 621 ms
450,396 KB |
testcase_26 | AC | 623 ms
450,432 KB |
testcase_27 | AC | 625 ms
450,432 KB |
testcase_28 | AC | 627 ms
450,376 KB |
testcase_29 | AC | 631 ms
450,432 KB |
testcase_30 | AC | 631 ms
450,304 KB |
testcase_31 | AC | 626 ms
450,408 KB |
testcase_32 | AC | 632 ms
450,304 KB |
ソースコード
#include <atcoder/all> #include <iostream> // cout, endl, cin #include <string> // string, to_string, stoi #include <vector> // vector #include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound #include <utility> // pair, make_pair #include <tuple> // tuple, make_tuple #include <cstdint> // int64_t, int*_t #include <cstdio> // printf #include <map> // map #include <queue> // queue, priority_queue #include <set> // set #include <stack> // stack #include <deque> // deque #include <unordered_map> // unordered_map #include <unordered_set> // unordered_set #include <bitset> // bitset #include <cctype> // isupper, islower, isdigit, toupper, tolower #include <math.h> #include <iomanip> using namespace std; using namespace atcoder; #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define repi(i, a, b) for (int i = (int)(a); i < (int)(b); i++) typedef long long ll; typedef unsigned long long ull; const ll inf=1e18; using graph = vector<vector<int> > ; using P= pair<ll,ll>; using vi=vector<int>; using vvi=vector<vi>; using vll=vector<ll>; using vvll=vector<vll>; using vp=vector<P>; using vpp=vector<vp>; //string T="ABCDEFGHIJKLMNOPQRSTUVWXYZ"; //string S="abcdefghijklmnopqrstuvwxyz"; //g++ main.cpp -std=c++14 -I . //cout <<setprecision(20); //cout << fixed << setprecision(10); //cin.tie(0); ios::sync_with_stdio(false); const double PI = acos(-1); int vx[]={0,1,0,-1,-1,1,1,-1},vy[]={1,0,-1,0,1,1,-1,-1}; ll pow_pow(ll x,ll n,ll mod){ if(n==0) return 1; x%=mod; ll res=pow_pow(x*x%mod,n/2,mod); if(n&1)res=res*x%mod; return res; } struct UnionFind { vector<int> par, siz; UnionFind(int n) : par(n, -1) , siz(n, 1) { } int root(int x) { if (par[x] == -1) return x; else return par[x] = root(par[x]); } bool issame(int x, int y) { return root(x) == root(y); } bool unite(int x, int y) { x = root(x), y = root(y); if (x == y) return false; if (siz[x] < siz[y]) swap(x, y); par[y] = x; siz[x] += siz[y]; return true; } int size(int x) { return siz[root(x)]; } }; ll gcd(ll x,ll y){ if(y==0)return x; return gcd(y,x%y); } ll lcm(ll x,ll y){ return ll(x/gcd(x,y))*y; } template<class T> bool chmin(T& a, T b) { if (a > b) { a = b; return true; } else return false; } template<class T> bool chmax(T& a, T b) { if (a < b) { a = b; return true; } else return false; } // https://youtu.be/L8grWxBlIZ4?t=9858 // https://youtu.be/ERZuLAxZffQ?t=4807 : optimize // https://youtu.be/8uowVvQ_-Mo?t=1329 : division const ll mod =1e9+7; struct mint { ll x; // typedef long long ll; mint(ll x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; istream& operator>>(istream& is, const mint& a) { return is >> a.x;} ostream& operator<<(ostream& os, const mint& a) { return os << a.x;} // combination mod prime // https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619 struct combination { vector<mint> fact, ifact; combination(int n):fact(n+1),ifact(n+1) { //assert(n < mod); fact[0] = 1; for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i; ifact[n] = fact[n].inv(); for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i; } mint operator()(int n, int k) { if (k < 0 || k > n) return 0; return fact[n]*ifact[k]*ifact[n-k]; } mint p(int n, int k) { return fact[n]*ifact[n-k]; } } c(20000050); using vm=vector<mint> ; using vvm=vector<vm> ; ll sqrt_(ll x) { ll l = 0, r = ll(3e9)+1; while (l+1<r) { ll c = (l+r)/2; if (c*c <= x) l = c; else r = c; } return l; } int valid(int x,int y,int h,int w){ if(x>=0 && y>=0 && x<h && y<w)return 1; else return 0; } ll comb[51][51]; void init_comb(){ comb[0][0]=1; for(int i=1; i<=50; i++){ for(int j=0; j<=i; j++){ if(j==0 || j==i)comb[i][j]=1; else comb[i][j]=comb[i-1][j]+comb[i-1][j-1]; } } } ll nCk(int n,int k){ return comb[n][k]; } struct edge{ int to; ll cost; edge(int to,ll cost) : to(to),cost(cost) {} }; using ve=vector<edge>; using vve =vector<ve>; map<ll,ll>d; void comp(vll&a){ set<ll>s(a.begin(),a.end()); int cnt=0; for(auto y:s)d[y]=cnt++; for(auto&y:a)y=d[y]; } const int MAX_ROW = 510; // to be set appropriately const int MAX_COL = 510; // to be set appropriately struct BitMatrix { int H, W; bitset<MAX_COL> val[MAX_ROW]; BitMatrix(int m = 1, int n = 1) : H(m), W(n) {} inline bitset<MAX_COL>& operator [] (int i) {return val[i];} }; int GaussJordan(BitMatrix &A, bool is_extended = false) { int rank = 0; for (int col = 0; col < A.W; ++col) { if (is_extended && col == A.W - 1) break; int pivot = -1; for (int row = rank; row < A.H; ++row) { if (A[row][col]) { pivot = row; break; } } if (pivot == -1) continue; swap(A[pivot], A[rank]); for (int row = 0; row < A.H; ++row) { if (row != rank && A[row][col]) A[row] ^= A[rank]; } ++rank; } return rank; } int linear_equation(BitMatrix A, vector<int> b, vector<int> &res) { int m = A.H, n = A.W; BitMatrix M(m, n + 1); for (int i = 0; i < m; ++i) { for (int j = 0; j < n; ++j) M[i][j] = A[i][j]; M[i][n] = b[i]; } int rank = GaussJordan(M, true); // check if it has no solution for (int row = rank; row < m; ++row) if (M[row][n]) return -1; // answer res.assign(n, 0); for (int i = 0; i < rank; ++i) res[i] = M[i][n]; return rank; }; mint dp[205][205][205]; mint old[205][205][205]; int main(){cin.tie(0); ios::sync_with_stdio(false); int h,w; cin >> h >> w; vector<string> s(h); rep(i,h)cin >> s[i]; if(s[0][0]==s[h-1][w-1])dp[0][0][h-1]=1; auto f=[&](int i,int j,int x,int y){ mint now=old[i][j][x]; if(i+1<h && x-1>=0 && s[i+1][j]==s[x-1][y]){ dp[i+1][j][x-1]+=now; } if(j+1<w && x-1>=0 && s[i][j+1]==s[x-1][y]){ dp[i][j+1][x-1]+=now; } if(i+1<h && y-1>=0 && s[i+1][j]==s[x][y-1]){ dp[i+1][j][x]+=now; } if(j+1<w && y-1>=0 && s[i][j+1]==s[x][y-1]){ dp[i][j+1][x]+=now; } }; int n=h+w-1; mint ans=0; rep(k,(n+1)/2+1){ rep(i,h)rep(x,h){ int j=k-i,y=h-1-x+w-1-k; if(j<0 || j>=w)continue; if(y<0 || y>=w)continue; if(i==x && y-j==1)ans+=dp[i][j][x]; if(i==x && y==j)ans+=dp[i][j][x]; if(x-i==1 && y==j)ans+=dp[i][j][x]; } rep(i,h)rep(x,h){ int j=k-i,y=h-1-x+w-1-k; if(j<0 || j>=w)continue; if(y<0 || y>=w)continue; old[i][j][x]=dp[i][j][x]; dp[i][j][x]=0; } rep(i,h)rep(x,h){ int j=k-i,y=h-1-x+w-1-k; if(j<0 || j>=w)continue; if(y<0 || y>=w)continue; f(i,j,x,y); } } cout << ans << endl; }