結果
問題 | No.2181 LRM Question 2 |
ユーザー |
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提出日時 | 2022-10-19 20:42:54 |
言語 | PyPy3 (7.3.15) |
結果 |
RE
|
実行時間 | - |
コード長 | 2,369 bytes |
コンパイル時間 | 286 ms |
コンパイル使用メモリ | 82,048 KB |
実行使用メモリ | 383,200 KB |
最終ジャッジ日時 | 2024-06-29 21:42:07 |
合計ジャッジ時間 | 9,972 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 RE * 2 |
other | AC * 7 RE * 16 |
ソースコード
import sysinput = sys.stdin.readlineclass BinomialCoefficient:def __init__(self, mod):self.mod = modself.prime = self.prime_factorize(mod)self.facs = []self.invs = []self.pows = []self.mods = {}for p, c in self.prime:pc = pow(p, c)fac = [1] * pcinv = [1] * pcfor i in range(1, pc):k = iif(i % p == 0):k = 1fac[i] = fac[i - 1] * k % pcinv[-1] = fac[-1]for i in range(pc - 1, 0, -1):k = iif(i % p == 0):k = 1inv[i - 1] = inv[i] * k % pcself.facs.append(fac)self.invs.append(inv)pw = [1]while(pw[-1] * p != pc):pw.append(pw[-1] * p)self.pows.append(pw)r = [0] * len(self.prime)pcs = [pow(p, c) for p, c in self.prime]for i in range(1, mod):for j, pc in enumerate(pcs):r[j] += 1if(r[j] >= pc):r[j] -= pcself.mods[tuple(r)] = idef prime_factorize(self, n):prime = []f = 2while(f * f <= n):if(n % f == 0):n //= fcnt = 1while(n % f == 0):n //= fcnt += 1prime.append((f, cnt))f += 1if(n != 1):prime.append((n, 1))return primedef inv_gcd(self, n, m):n %= mif(n == 0):return m, 0s, t, m0, m1 = m, n, 0, 1while(t):u = s // ts -= t * um0 -= m1 * um0, m1, s, t = m1, m0, t, sif(m0 < 0):m0 += m // sreturn s, m0def inv_mod(self, n, m):g, im = self.inv_gcd(n, m)return imdef calc_e(self, n, k, r, p):e = 0while(n):n //= pe += nwhile(k):k //= pe -= kwhile(r):r //= pe -= rreturn edef lucas(self, n, k, p, c, i):pw = self.pows[i]fac = self.facs[i]inv = self.invs[i]r = n - kpc = pow(p, c)e = self.calc_e(n, k, r, p)if(e >= len(pw)):return 0ret = pw[e]if((p != 2 or c < 3) and (self.calc_e(n // pw[-1], k // pw[-1], r // pw[-1], p) & 1)):ret *= -1while(n):ret *= fac[n % pc] * inv[k % pc] * inv[r % pc]ret %= pcn //= pk //= pr //= preturn retdef __call__(self, n, k):if(k < 0 or k > n):return 0if(k == 0 or k == n):return 1r = [self.lucas(n, k, p, c, i) for i, (p, c) in enumerate(self.prime)]return self.mods[tuple(r)]"""Main Code"""l, r, m = map(int, input().split())nCk = BinomialCoefficient(m)ans = 0for i in range(l, r + 1):ans += nCk(2 * i, i) + m - 2ans %= mprint(ans)