結果

問題 No.2103 ±1s Game
ユーザー sortreewsortreew
提出日時 2022-10-21 21:35:56
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 3,212 bytes
コンパイル時間 1,514 ms
コンパイル使用メモリ 166,964 KB
実行使用メモリ 17,256 KB
最終ジャッジ日時 2023-09-13 21:55:19
合計ジャッジ時間 3,243 ms
ジャッジサーバーID
(参考情報)
judge12 / judge15
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 6 ms
17,044 KB
testcase_01 AC 6 ms
16,980 KB
testcase_02 AC 7 ms
17,168 KB
testcase_03 AC 6 ms
17,092 KB
testcase_04 AC 6 ms
17,216 KB
testcase_05 AC 6 ms
16,984 KB
testcase_06 AC 6 ms
17,052 KB
testcase_07 WA -
testcase_08 AC 6 ms
17,012 KB
testcase_09 WA -
testcase_10 AC 6 ms
17,016 KB
testcase_11 AC 7 ms
16,996 KB
testcase_12 AC 6 ms
17,256 KB
testcase_13 AC 6 ms
17,112 KB
testcase_14 AC 6 ms
16,976 KB
testcase_15 WA -
testcase_16 AC 6 ms
16,992 KB
testcase_17 WA -
testcase_18 AC 6 ms
17,220 KB
testcase_19 AC 6 ms
17,052 KB
testcase_20 AC 6 ms
16,980 KB
testcase_21 AC 6 ms
17,064 KB
testcase_22 AC 6 ms
17,024 KB
testcase_23 AC 6 ms
16,976 KB
testcase_24 AC 5 ms
17,000 KB
testcase_25 AC 6 ms
17,156 KB
testcase_26 AC 6 ms
17,028 KB
testcase_27 WA -
testcase_28 WA -
testcase_29 AC 6 ms
17,084 KB
testcase_30 AC 6 ms
16,976 KB
testcase_31 WA -
testcase_32 AC 6 ms
16,988 KB
testcase_33 AC 6 ms
17,172 KB
testcase_34 AC 6 ms
17,216 KB
testcase_35 AC 6 ms
16,976 KB
testcase_36 AC 6 ms
16,996 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include "bits/stdc++.h"
#define YES "YES"
#define NO "NO"
#define Yes "Yes"
#define No "No"
#define DEFAULT              \
    LL ans = solve();        \
    if (ans == NONE)         \
    {                        \
    }                        \
    else                     \
    {                        \
        cout << ans << endl; \
    }
#define YESNO three(solve(), (OUT(YES), 1), (OUT(NO), 0))
#define YesNo three(solve(), OUT(Yes), OUT(No))
#define ECHO OUT(solve())
#define three(A, B, C) ((A) ? (B) : (C))
#define FOR(i, a, b) for (LL i = (a); i < (LL)(b); i++)
#define EFOR(i, a, b) for (LL i = (a); i <= (LL)(b); i++)
#define RFOR(i, a, b) for (LL i = (b - 1); i >= (LL)(a); i--)
#define REP(i, b) FOR(i, zero, b)
#define rep REP
#define EREP(i, b) EFOR(i, zero, b)
#define RREP(i, b) RFOR(i, zero, b)
#define ALL(c) c.begin(), c.end()
#define UNIQUE(c) \
    sort(ALL(c)); \
    c.erase(unique(ALL(c)), c.end())
#define MAX(c) (*max_element(ALL(c)))
#define MIN(c) (*min_element(ALL(c)))
#define MP make_pair
#define FI first
#define SE second
#define SI(x) (LL(x.size()))
#define PB push_back
#define DEBUG(a) OUT(a)
#define DEBUG2(a, b) OUT2(a, b)
#define cat cout << __LINE__ << endl
#define OUT(a) cout << (a) << endl
#define OUT2(a, b) cout << (a) << " " << (b) << endl
#define zero 0LL
#define all ALL
#define pb emplace_back
#define eb pb
#define int long long
using namespace std;
template <typename T>
inline void maximize(T &a, T b) { a = max(a, b); }
template <typename T>
inline void minimize(T &a, T b) { a = min(a, b); }
template <typename T>
inline bool middle(T a, T b, T c) { return b <= a && a <= c; }
template <class T>
inline bool MX(T &l, const T &r) { return l < r ? l = r, 1 : 0; }
template <class T>
inline bool MN(T &l, const T &r) { return l > r ? l = r, 1 : 0; }
typedef int LL;
typedef double ld;
typedef int ut;
typedef vector<ut> VI;
typedef vector<VI> VII;
typedef pair<ut, ut> pr;
typedef pair<ut, pr> ppr;
typedef vector<pr> Vpr;
typedef vector<ppr> Vppr;
typedef tuple<int, int, int, int> tapu;
typedef vector<tapu> Vtapu;
typedef priority_queue<pr, Vpr> PQ;
inline void outputVI(VI x)
{
    REP(i, SI(x)) { cout << three(i, " ", "") << x[i]; }
    OUT("");
}
const int SIZE1 = 5e5 + 1000;
const int SIZE2 = 5010;
const int SIZE3 = 430;
const int SIZE = SIZE1;
const int MAPSIZE = 40;
const LL p998 = 998244353;
const LL p107 = 1000000007;
const LL p = p107;
const LL INF = 1LL << 60;
const long double EPS = 1e-7;
const LL NONE = -2;
#define endl "\n"
ut N, M, K, D, Q, I, S, V, F;
VI edges[SIZE];
LL vals[SIZE], answer = zero;
// LL A[SIZE],B[SIZE],C[SIZE];
LL solve()
{
    LL X, Y, K, P;
    cin >> X >> Y >> K >> P;
    LL used = (X + Y - K);
    LL last = (used + 1) % 2;
    LL able = (X + Y - K) / 2;
    if (able >= X)
    {
        LL ys = used - X;
        LL ans = ys % 2;
    }
    if (able >= Y)
    {
        return 0;
    }
    return last;
}
signed main()
{

    ios_base::sync_with_stdio(false);
    cout << fixed << setprecision(10);
    LL T = 1;

    REP(i, T)
    {
        cout << three(solve(), "Bob", "Alice") << endl;
    }

    //	YesNo;
    //	YESNO;
    //	three(solve(),OUT("First"),OUT("Second"));
    // cin >> N;
    return 0;
}
0