結果

問題 No.2115 Making Forest Easy
ユーザー SumitacchanSumitacchan
提出日時 2022-10-28 23:38:54
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
TLE  
実行時間 -
コード長 7,198 bytes
コンパイル時間 2,555 ms
コンパイル使用メモリ 221,308 KB
実行使用メモリ 13,756 KB
最終ジャッジ日時 2024-07-06 02:56:06
合計ジャッジ時間 6,068 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 4 ms
13,756 KB
testcase_01 AC 9 ms
6,940 KB
testcase_02 TLE -
testcase_03 -- -
testcase_04 -- -
testcase_05 -- -
testcase_06 -- -
testcase_07 -- -
testcase_08 -- -
testcase_09 -- -
testcase_10 -- -
testcase_11 -- -
testcase_12 -- -
testcase_13 -- -
testcase_14 -- -
testcase_15 -- -
testcase_16 -- -
testcase_17 -- -
testcase_18 -- -
testcase_19 -- -
testcase_20 -- -
testcase_21 -- -
testcase_22 -- -
testcase_23 -- -
testcase_24 -- -
testcase_25 -- -
testcase_26 -- -
testcase_27 -- -
testcase_28 -- -
testcase_29 -- -
testcase_30 -- -
testcase_31 -- -
testcase_32 -- -
testcase_33 -- -
testcase_34 -- -
testcase_35 -- -
testcase_36 -- -
testcase_37 -- -
testcase_38 -- -
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testcase_40 -- -
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testcase_48 -- -
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testcase_50 -- -
testcase_51 -- -
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
//using namespace atcoder;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin);i<(end);i++)
#define REP(i, n) FOR(i,0,n)
#define IFOR(i, begin, end) for(int i=(end)-1;i>=(begin);i--)
#define IREP(i, n) IFOR(i,0,n)
#define Sort(v) sort(v.begin(), v.end())
#define Reverse(v) reverse(v.begin(), v.end())
#define all(v) v.begin(),v.end()
#define SZ(v) ((int)v.size())
#define Lower_bound(v, x) distance(v.begin(), lower_bound(v.begin(), v.end(), x))
#define Upper_bound(v, x) distance(v.begin(), upper_bound(v.begin(), v.end(), x))
#define chmax(a, b) a = max(a, b)
#define chmin(a, b) a = min(a, b)
#define bit(n) (1LL<<(n))
#define debug(x) cout << #x << "=" << x << endl;
#define vdebug(v) { cout << #v << "=" << endl; REP(i_debug, (int)v.size()){ cout << v[i_debug] << ","; } cout << endl; }
#define mdebug(m) { cout << #m << "=" << endl; REP(i_debug, (int)m.size()){ REP(j_debug, (int)m[i_debug].size()){ cout << m[i_debug][j_debug] << ","; } cout << endl;} }
#define pb push_back
#define fi first
#define se second
#define int long long
#define INF 1000000000000000000
template<typename T> istream &operator>>(istream &is, vector<T> &v){ for (auto &x : v) is >> x; return is; }
template<typename T> ostream &operator<<(ostream &os, vector<T> &v){ for(int i = 0; i < (int)v.size(); i++) { cout << v[i]; if(i != (int)v.size() - 1) cout << endl; }; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p){ cout << '(' << p.first << ',' << p.second << ')'; return os; }
template<typename T> void Out(T x) { cout << x << endl; }
template<typename T1, typename T2> void chOut(bool f, T1 y, T2 n) { if(f) Out(y); else Out(n); }

using vec = vector<int>;
using mat = vector<vec>;
using Pii = pair<int, int>;
using v_bool = vector<bool>;
using v_Pii = vector<Pii>;

//int dx[4] = {1,0,-1,0};
//int dy[4] = {0,1,0,-1};
//char d[4] = {'D','R','U','L'};

//const int mod = 1000000007;
const int mod = 998244353;

template<long long MOD>
struct ModInt{

    using ll = long long;
    ll val;

    void setval(ll v) { val = v % MOD; };
    ModInt(): val(0) {}
    ModInt(ll v) { setval(v); };

    ModInt operator+(const ModInt &x) const { return ModInt(val + x.val); }
    ModInt operator-(const ModInt &x) const { return ModInt(val - x.val + MOD); }
    ModInt operator*(const ModInt &x) const { return ModInt(val * x.val); }
    ModInt operator/(const ModInt &x) const { return *this * x.inv(); }
    ModInt operator-() const { return ModInt(MOD - val); }
    ModInt operator+=(const ModInt &x) { return *this = *this + x; }
    ModInt operator-=(const ModInt &x) { return *this = *this - x; }
    ModInt operator*=(const ModInt &x) { return *this = *this * x; }
    ModInt operator/=(const ModInt &x) { return *this = *this / x; }
    bool operator==(const ModInt &x) const { return (*this).val == x.val; }

    friend ostream& operator<<(ostream &os, const ModInt &x) { os << x.val; return os; }
    friend istream& operator>>(istream &is, ModInt &x) { is >> x.val; x.val = (x.val % MOD + MOD) % MOD; return is; }

    ModInt pow(ll n) const {
        ModInt a = 1;
        if(n == 0) return a;
        int i0 = 64 - __builtin_clzll(n);
        for(int i = i0 - 1; i >= 0; i--){
            a = a * a;
            if((n >> i) & 1) a *= (*this); 
        }
        return a;
    }
    ModInt inv() const { return this->pow(MOD - 2); }
    
    void add_product(ModInt a, ModInt b){
        (val += a.val * b.val) %= MOD;
    }

    void sbt_product(ModInt a, ModInt b){
        (val -= a.val * b.val) %= MOD;
        if(val < 0) val += MOD;
    }
};

using mint = ModInt<mod>; mint pow(mint x, long long n) { return x.pow(n); }
//using mint = double; //for debug
using mvec = vector<mint>;
using mmat = vector<mvec>;

struct Combination{

    vector<mint> fact, invfact;

    Combination(int N){
        fact = vector<mint>({mint(1)});
        invfact = vector<mint>({mint(1)});
        fact_initialize(N);
    }

    void fact_initialize(int N){
        int i0 = fact.size();
        if(i0 >= N + 1) return;
        fact.resize(N + 1);
        invfact.resize(N + 1);
        for(int i = i0; i <= N; i++) fact[i] = fact[i - 1] * i;
        invfact[N] = (mint)1 / fact[N];
        for(int i = N - 1; i >= i0; i--) invfact[i] = invfact[i + 1] * (i + 1); 
    }

    mint nCr(int n, int r){
        if(n < 0 || r < 0 || r > n) return mint(0);
        if((int)fact.size() < n + 1) fact_initialize(n);
        return fact[n] * invfact[r] * invfact[n - r];
    }

    mint nPr(int n, int r){
        if(n < 0 || r < 0 || r > n) return mint(0);
        if((int)fact.size() < n + 1) fact_initialize(n);
        return fact[n] * invfact[n - r];
    }

    mint Catalan(int n){
        if(n < 0) return 0;
        else if(n == 0) return 1;
        if((int)fact.size() < 2 * n + 1) fact_initialize(2 * n);
        return fact[2 * n] * invfact[n + 1] * invfact[n];
    }

};

template<typename T> 
struct edge{ int to; T cost; int id; };

template<typename T = long long>
struct Graph
{

    int N;
    vector<vector<edge<T>>> E;
    vec A;
    mvec dp, dq;

    Graph(int N): N(N){
        E = vector<vector<edge<T>>>(N, vector<edge<T>>(0));
        dp.resize(N);
        dq.resize(N);
    }

    void add_Directed_edge(int from, int to, T cost = 1, int id = 0){
        E[from].push_back(edge<T>({ to, cost, id }));
    }

    void add_Undirected_edge(int v1, int v2, T cost = 1, int id = 0){
        add_Directed_edge(v1, v2, cost, id);
        add_Directed_edge(v2, v1, cost, id);
    }

    void dfs1(int v, int x, int p = -1){
        if(A[v] < x) dp[v] = 1;
        else dp[v] = 0;
        for(auto e: E[v]) if(e.to != p){
            dfs1(e.to, x, v);
            dp[v] *= (mint)1 - ((mint)1 - dp[e.to]) / 2;
        }
    }

    void dfs2(int v, int x, mint &ans, int p = -1){
        if(p == -1) dq[v] = 1;

        vec ch;
        for(auto e: E[v]) if(e.to != p){
            ch.pb(e.to);
        }
        int n = SZ(ch);
        
        mint q0 = (mint)1 - ((mint)1 - dq[v]) / 2;
        if(A[v] < x){
            mvec dl(n + 1, 0), dr(n + 1, 0);
            dl[0] = dr[0] = 1;
            REP(i, n){
                mint q = (mint)1 - ((mint)1 - dp[ch[i]]) / 2;
                dl[i + 1] = dl[i] * q;
            }
            REP(i, n){
                mint q = (mint)1 - ((mint)1 - dp[ch[n - 1 - i]]) / 2;
                dr[i + 1] = dr[i] * q;
            }
            REP(i, n){
                dq[ch[i]] = dl[i] * dr[n - 1 - i] * q0;
            }
        }else{
            REP(i, n){
                dq[ch[i]] = 0;
            }
        }

        REP(i, n) dfs2(ch[i], x, ans, v);
        ans += (mint)1 - dp[v] * q0;
    }

};

signed main(){

    int N; cin >> N;
    vec A(N); cin >> A;
    Graph G(N);
    REP(i, N - 1){
        int u, v; cin >> u >> v;
        u--; v--;
        G.add_Undirected_edge(u, v);
    }
    G.A = A;

    mint ans = 0;
    FOR(x, 1, 1001){
        G.dfs1(0, x);
        G.dfs2(0, x, ans);
    }
    ans *= pow((mint)2, N - 1);

    Out(ans);

    return 0;
}
0