結果
問題 | No.117 組み合わせの数 |
ユーザー | shimomire |
提出日時 | 2015-01-05 01:54:46 |
言語 | C++11 (gcc 11.4.0) |
結果 |
RE
|
実行時間 | - |
コード長 | 5,971 bytes |
コンパイル時間 | 4,323 ms |
コンパイル使用メモリ | 234,788 KB |
実行使用メモリ | 19,492 KB |
最終ジャッジ日時 | 2024-06-13 02:38:10 |
合計ジャッジ時間 | 6,139 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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コンパイルメッセージ
main.cpp: In member function ‘void Main::run()’: main.cpp:145:28: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 145 | int T;scanf("%d",&T);//cin >> T; | ~~~~~^~~~~~~~~
ソースコード
#include <cassert>// c #include <iostream>// io #include <iomanip> #include <fstream> #include <sstream> #include <vector>// container #include <map> #include <set> #include <queue> #include <bitset> #include <stack> #include <algorithm>// other #include <complex> #include <numeric> #include <functional> #include <random> #include <regex> using namespace std; using i32=int32_t;using i64=int64_t;using ll =i64;using uint=uint32_t;using ull=uint64_t; template<typename T> using matrix=vector<vector<T> >; #define ALL(c) (begin(c)),(end(c)) #define REP(i,n) FOR(i,0,n) #define REPr(i,n) FORr(i,0,n) #define FOR(i,l,r) for(int i=(int)(l);i<(int)(r);++i) #define FORr(i,l,r) for(int i=(int)(r)-1;i>=(int)(l);--i) #define EACH(it,o) for(auto it = (o).begin(); it != (o).end(); ++it) #define IN(l,v,r) ((l)<=(v) && (v)<(r)) #define UNIQUE(v) v.erase(unique(ALL(v)),v.end()) //debug #define DUMP(x) cerr << #x << " = " << (x) #define LINE() cerr<< " (L" << __LINE__ << ")" class range { private: struct Iter{ int v; int operator*(){return v;} bool operator!=(Iter& itr) {return v < itr.v;} void operator++() {++v;} }; Iter i, n; public: range(int n) : i({0}), n({n}) {} range(int i, int n) : i({i}), n({n}) {} Iter& begin() {return i;} Iter& end() {return n;} }; //output template<typename T> ostream& operator << (ostream& os, const vector<T>& as){REP(i,as.size()){if(i!=0)os<<" "; os<<as[i];}return os;} template<typename T> ostream& operator << (ostream& os, const vector<vector<T>>& as){REP(i,as.size()){if(i!=0)os<<endl; os<<as[i];}return os;} template<typename T> ostream& operator << (ostream& os, const set<T>& ss){for(auto a:ss){if(a!=ss.begin())os<<" "; os<<a;}return os;} template<typename T1,typename T2> ostream& operator << (ostream& os, const pair<T1,T2>& p){os<<p.first<<" "<<p.second;return os;} template<typename K,typename V> ostream& operator << (ostream& os, const map<K,V>& m){bool isF=true;for(auto& p:m){if(!isF)os<<endl;os<<p;isF=false;}return os;} template<typename T1> ostream& operator << (ostream& os, const tuple<T1>& t){os << get<0>(t);return os;} template<typename T1,typename T2> ostream& operator << (ostream& os, const tuple<T1,T2>& t){os << get<0>(t)<<" "<<get<1>(t);return os;} template<typename T1,typename T2,typename T3> ostream& operator << (ostream& os, const tuple<T1,T2,T3>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t);return os;} template<typename T1,typename T2,typename T3,typename T4> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t);return os;} template<typename T1,typename T2,typename T3,typename T4,typename T5> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4,T5>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t)<<" "<<get<4>(t);return os;} template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4,T5,T6>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t)<<" "<<get<4>(t)<<" "<<get<5>(t);return os;} template<typename T1,typename T2,typename T3,typename T4,typename T5,typename T6,typename T7> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4,T5,T6,T7>& t){os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t)<<" "<<get<4>(t)<<" "<<get<5>(t)<<" "<<get<6>(t);return os;} //input char tmp[1000]; #define nextInt(n) scanf("%d",&n) #define nextLong(n) scanf("%lld",&n) //I64d #define nextDouble(n) scanf("%lf",&n) #define nextChar(n) scanf("%c",&n) #define nextString(n) scanf("%s",tmp);n=tmp // values template<typename T> T INF(){assert(false);}; template<> int INF<int>(){return 1<<28;}; template<> ll INF<ll>(){return 1LL<<58;}; template<> double INF<double>(){return 1e16;}; template<class T> T EPS(){assert(false);}; template<> int EPS<int>(){return 1;}; template<> ll EPS<ll>(){return 1LL;}; template<> double EPS<double>(){return 1e-8;}; template<> long double EPS<long double>(){return 1e-8;}; template<typename T,typename U> T pmod(T v,U M){return (v%M+M)%M;} ll gcd_positive(ll a,ll b) { return b == 0 ? a : gcd_positive(b,a%b); } ll gcd(ll a,ll b) { return gcd_positive(abs(a), abs(b)); } ll lcm(ll a,ll b){return a/gcd(a,b)*b;} template <ll M=(ll)1e9+7> class modU{ public: ll pmod(ll v){return (v%M+M)%M;} ll ainv(ll a){return pmod(-a);} ll add(ll a,ll b){return pmod(a+b);} ll mul(ll a,ll b){return pmod(a*b);} ll mpow(ll x, ll N){ ll res=1; while(N>0){ if(N%2)res=mul(res,x); x=mul(x,x); N/=2; } return res; } ll minv(ll a){return mpow(a,M-2);} // O(log M) vector<ll> minvs(){ vector<ll> inv(M + 1);inv[1] = 1; for (int i = 2; i <= M; ++i)inv[i] = mul(inv[M % i],M - M / i); return inv; } //条件 N>=0 vector<ll> factmemo=vector<ll>(2000050,-1); inline ll fact(const int N){ if(factmemo[N]!=-1)return factmemo[N]; return factmemo[N]=N==0?1:mul(N,fact(N-1)); } //条件 N>=0 ll nPr(const int N,const int r){ if(r>N)return 0; return mul(fact(N),minv(fact(N-r))); } ll nCr(const int N,const int r){ if(N<0){ if(0 <= r) return (r%2?-1:+1)*nCr(-N +r-1,r); else if(r<=N) return ((N-r)%2?-1:+1)*nCr(-r-1,N-r); else return 0; } if(0<= r && r<=N) return mul(mul(fact(N),minv(fact(r))),minv(fact(N-r))); return 0; } }; class Main{ public: modU<> mu; void run(){ int T;scanf("%d",&T);//cin >> T; REP(i,2000050)mu.fact(i); //rec nest regex re("(.)\\(([[:digit:]]+),([[:digit:]]+)\\)"); for(int t=0;t<T;t++){ int N,M;string type; // scanf("%1s(%d,%d)",type,&N,&M); string s;cin >> s; smatch match; regex_match(s,match,re); type=match[1]; N=stoi(match[2]); M=stoi(match[3]); if(type[0]=='C') cout << mu.nCr(N,M) <<endl; if(type[0]=='P') cout << mu.nPr(N,M) <<endl; if(type[0]=='H') cout << mu.nCr(N+M-1,M) <<endl; } } }; int main(){ cout <<fixed<<setprecision(20); cin.tie(0); ios::sync_with_stdio(false); Main().run(); return 0; }