結果
問題 | No.2112 All 2x2 are Equal |
ユーザー |
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提出日時 | 2022-10-29 04:03:18 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 71 ms / 2,000 ms |
コード長 | 3,488 bytes |
コンパイル時間 | 1,804 ms |
コンパイル使用メモリ | 203,204 KB |
最終ジャッジ日時 | 2025-02-08 15:40:58 |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 34 |
コンパイルメッセージ
main.cpp: In function ‘int geti()’: main.cpp:25:23: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 25 | int geti(){int x;scanf("%d",&x);return x;} | ~~~~~^~~~~~~~~ main.cpp: In member function ‘void Solver::solve()’: main.cpp:56:10: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 56 | scanf("%d%d",&h,&w); | ~~~~~^~~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h>#define rep(i,n) for(int i = 0; i < (n); ++i)#define rep1(i,n) for(int i = 1; i <= (n); ++i)#define drep(i,n) for(int i = (n)-1; i >= 0; --i)#define srep(i,s,t) for (int i = s; i < (t); ++i)#define rng(a) a.begin(),a.end()#define rrng(a) a.rbegin(),a.rend()#define fi first#define se second#define pb push_back#define eb emplace_back#define pob pop_back#define sz(x) (int)(x).size()#define pcnt __builtin_popcountll#define snuke srand((unsigned)clock()+(unsigned)time(NULL));#define newline puts("")using namespace std;template<typename T> using vc = vector<T>;template<typename T> using vv = vc<vc<T>>;template<typename T> using PQ = priority_queue<T,vc<T>,greater<T>>;using uint = unsigned; using ull = unsigned long long;using vi = vc<int>; using vvi = vv<int>; using vvvi = vv<vi>;using ll = long long; using vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>;using P = pair<int,int>; using vp = vc<P>; using vvp = vv<P>;int geti(){int x;scanf("%d",&x);return x;}vi pm(int n, int s=0) { vi a(n); iota(rng(a),s); return a;}template<typename T>istream& operator>>(istream&i,vc<T>&v){rep(j,sz(v))i>>v[j];return i;}template<typename T>string join(const T&v,const string& d=""){stringstream s;rep(i,sz(v))(i?s<<d:s)<<v[i];return s.str();}template<typename T>ostream& operator<<(ostream&o,const vc<T>&v){if(sz(v))o<<join(v," ");return o;}template<typename T1,typename T2>istream& operator>>(istream&i,pair<T1,T2>&v){return i>>v.fi>>v.se;}template<typename T1,typename T2>ostream& operator<<(ostream&o,const pair<T1,T2>&v){return o<<v.fi<<","<<v.se;}template<typename T1,typename T2>void operator--(pair<T1,T2>&a,int){a.fi--;a.se--;}template<typename T>void operator--(vc<T>&a,int){for(T&x:a)x--;}template<typename T>void operator+=(vc<T>&a,int b){for(T&x:a)x+=b;}template<typename T>void operator+=(vc<T>&a,const vc<T>&b){a.insert(a.end(),rng(b));}template<typename T1,typename T2>bool mins(T1& x,const T2&y){if(x>y){x=y;return true;}else return false;}template<typename T1,typename T2>bool maxs(T1& x,const T2&y){if(x<y){x=y;return true;}else return false;}template<typename Tx, typename Ty>Tx dup(Tx x, Ty y){return (x+y-1)/y;}template<typename T>ll suma(const vc<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;}template<typename T>ll suma(const vv<T>&a){ll res(0);for(auto&&x:a)res+=suma(x);return res;}template<typename T>void uni(T& a){sort(rng(a));a.erase(unique(rng(a)),a.end());}template<typename T>void prepend(vc<T>&a,const T&x){a.insert(a.begin(),x);}const double eps = 1e-10;const ll LINF = 1001002003004005006ll;const int INF = 1001001001;#define dame { puts("-1"); return;}#define yes { puts("Yes"); return;}#define no { puts("No"); return;}#define ret(x) { cout<<(x)<<endl; return;}#define yn {puts("Yes");}else{puts("No");}const int MX = 200005;struct Solver {void solve() {int h,w;scanf("%d%d",&h,&w);int mx = h*w-1;bool fl = false;if (h+w&1) {mx++;if (h&1) swap(h,w), fl = true;}vvi a(h,vi(w));rep(i,h)rep(j,w) a[i][j] = i*w+j;rep(i,h)rep(j,w) if (i+j&1) a[i][j] = mx-a[i][j];a += 1;if (fl) {swap(h,w);vvi b(h,vi(w)); swap(a,b);rep(i,h)rep(j,w) a[i][j] = b[j][i];}puts("Yes");rep(i,h) cout<<a[i]<<endl;}};int main() {// cin.tie(nullptr); ios::sync_with_stdio(false);int ts = 1;// scanf("%d",&ts);rep1(ti,ts) {Solver solver;solver.solve();}return 0;}