結果
問題 | No.2117 中国剰余定理入門 |
ユーザー |
|
提出日時 | 2022-11-04 21:46:02 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 5,735 bytes |
コンパイル時間 | 2,023 ms |
コンパイル使用メモリ | 190,816 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-07-18 19:29:47 |
合計ジャッジ時間 | 2,422 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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ファイルパターン | 結果 |
---|---|
other | AC * 20 |
ソースコード
#include <bits/stdc++.h>using namespace std;using ll = long long;//#include <atcoder/modint>//using namespace atcoder;//using mint = modint998244353;# define M_PI 3.14159265358979323846 /* pi */#define watch(x) cout << (#x) << " is " << (x) << endl//#pragma GCC target ("avx2")#pragma GCC optimization ("O3")//const int MOD = (1e9+7);template < typename T = int > ostream& operator << (ostream &out, const vector < T > &v){for (const T &x: v) out << x << ' ';return out;}void printmat(const vector<vector<int>>& mat) {for (auto row : mat) {for (auto elem : row)cout << elem << " ";cout << "\n";}}void printdq(const deque<int>& v) {for (auto elem : v)cout << elem << " ";cout << endl;}void printv(const vector<int>& v) {for (auto elem : v)cout << elem << " ";cout << "\n";}void printvll(const vector<ll>& v) {for (auto elem : v)cout << elem << " ";cout << endl;}void printd(const deque<int>& v) {for (auto elem : v)cout << elem << " ";cout << endl;}void printvp(const vector<pair<int,int>>& vp) {for (auto pr : vp) {cout << pr.first << " " << pr.second;cout << "\n";}}void printvs(const vector<set<int>>& vs) {for (auto row : vs) {for (auto elem : row)cout << elem << ", ";cout << endl;}}void printht(const unordered_map<int, int>& ht) {for (auto elem : ht)cout << elem.first << " : " << elem.second << endl;}void printmp(const map<int, int>& ht) {for (auto elem : ht)cout << elem.first << " : " << elem.second << endl;}void printst(const set<int>& st) {for (auto elem : st)cout << elem << " ";cout << endl;}bool isPrime(long long n) {if (n <= 1)return false;if (n <= 3)return true;if (n % 2 == 0 || n % 3 == 0)return false;for (long long i = 5; i * i <= n; i = i + 6)if (n % i == 0 || n % (i + 2) == 0)return false;return true;}map<long long, long long> primeFactors(long long n) {map<long long, long long> ans;while (n % 2 == 0) {ans[2]++;n = n/2;}for (long long i = 3; i*i <= (n); i = i + 2) {while (n % i == 0) {ans[i]++;n = n/i;}}if (n > 2)ans[n]++;return ans;}int find_f(const vector<int>& uf, int i) {while (uf[i]!=i)i = uf[i];return i;}bool union_f(vector<int>& uf, vector<int>& sz, int a, int b) {a = find_f(uf, a);b = find_f(uf, b);//cout << "a, b = " << a << ", " << b << endl;if (a==b) return false;if (sz[a] < sz[b]) {//cout << "sz[a], sz[b] = " << sz[a] << ", " << sz[b] << endl;//cout << "a, b = " << a << ", " << b << endl;swap(a,b);//cout << "a, b = " << a << ", " << b << endl;}sz[a] += sz[b];uf[b] = a;return true;}long long modexp(long long b, long long e, long long M) {if (!e) return 1;b %= M;long long x = modexp(b * b % M, e / 2, M);if (e % 2) {return b * x % M;} else {return x;}}ll gcdExtended(ll a, ll b, ll* x, ll* y) {if (a == 0) {*x = 0, *y = 1;return b;}ll x1, y1;ll gcd = gcdExtended(b % a, a, &x1, &y1);*x = y1 - (b / a) * x1;*y = x1;return gcd;}ll modInverse(ll a, ll m) {ll x, y, res=-1;ll g = gcdExtended(a, m, &x, &y);if (g != 1) {//cout << "Inverse doesn't exist";res = -1;} else {// m is added to handle negative xres = (x % m + m) % m;}return res;}int lenOfLIS(vector<int>& v) {int n = v.size(), len = 0;vector<int> dp(n,0);for (int num : v) {int i = lower_bound(dp.begin(), dp.begin()+len, num) - dp.begin();dp[i] = num;if (i == len) {len++;}}return len;}const int MOD = 1e9 + 7;struct mi {int v; explicit operator int() const { return v; }mi() { v = 0; }mi(long long _v) : v(_v % MOD) { v += (v < 0) * MOD; }};mi& operator+=(mi& a, mi b) {if ((a.v += b.v) >= MOD) a.v -= MOD;return a;}mi& operator-=(mi& a, mi b) {if ((a.v -= b.v) < 0) a.v += MOD;return a;}mi operator+(mi a, mi b) { return a += b; }mi operator-(mi a, mi b) { return a -= b; }mi operator*(mi a, mi b) { return mi((long long) a.v * b.v); }mi& operator*=(mi& a, mi b) { return a = a * b; }mi pow(mi a, long long p) {assert(p >= 0);return p == 0 ? 1 : pow(a * a, p / 2) * (p & 1 ? a : 1);}mi inv(mi a) { assert(a.v != 0); return pow(a, MOD - 2); }mi operator/(mi a, mi b) { return a * inv(b); }int main() {ios_base::sync_with_stdio(false);cin.tie(NULL);int T=1, caseIdx=0;//cin >> T;while (T--) {//caseIdx++;int b0, c0, b1, c1, ans=-1;cin >> b0 >> c0;cin >> b1 >> c1;while (c0<0) {c0 = b0 + c0;}while (c1<0) {c1 = b1 + c1;}c0 %= b0;c1 %= b1;bool found = false;for (int i=0; i<=b0*b1; i++) {int x = i%b0;int y = i%b1;//cout << "x, y = " << x << ", " << y << endl;if (x==c0 && y==c1) {ans = i;break;}}if (ans==-1) {cout << "NaN" << "\n";continue;}//cout << fixed << setprecision(9);cout << ans << "\n";//cout << "Case #" << caseIdx << ": " << ans << "\n";}}