結果
問題 | No.2137 Stairs of Permutation |
ユーザー | PCTprobability |
提出日時 | 2022-11-25 21:57:33 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 713 ms / 2,000 ms |
コード長 | 5,089 bytes |
コンパイル時間 | 4,845 ms |
コンパイル使用メモリ | 271,256 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-10-02 04:32:22 |
合計ジャッジ時間 | 12,788 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,248 KB |
testcase_02 | AC | 120 ms
5,248 KB |
testcase_03 | AC | 508 ms
5,248 KB |
testcase_04 | AC | 417 ms
5,248 KB |
testcase_05 | AC | 320 ms
5,248 KB |
testcase_06 | AC | 666 ms
5,248 KB |
testcase_07 | AC | 701 ms
5,248 KB |
testcase_08 | AC | 77 ms
5,248 KB |
testcase_09 | AC | 36 ms
5,248 KB |
testcase_10 | AC | 105 ms
5,248 KB |
testcase_11 | AC | 637 ms
5,248 KB |
testcase_12 | AC | 240 ms
5,248 KB |
testcase_13 | AC | 341 ms
5,248 KB |
testcase_14 | AC | 506 ms
5,248 KB |
testcase_15 | AC | 702 ms
5,248 KB |
testcase_16 | AC | 232 ms
5,248 KB |
testcase_17 | AC | 203 ms
5,248 KB |
testcase_18 | AC | 319 ms
5,248 KB |
testcase_19 | AC | 261 ms
5,248 KB |
testcase_20 | AC | 174 ms
5,248 KB |
testcase_21 | AC | 698 ms
5,248 KB |
testcase_22 | AC | 2 ms
5,248 KB |
testcase_23 | AC | 713 ms
5,248 KB |
testcase_24 | AC | 2 ms
5,248 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #if __has_include(<atcoder/all>) #include <atcoder/all> using namespace atcoder; #endif using ll = long long; using ld = long double; using ull = unsigned long long; #define endl "\n" typedef pair<int, int> Pii; #define REP(i, n) for (int i = 0; i < (n); ++i) #define REP3(i, m, n) for (int i = (m); (i) < int(n); ++ (i)) #define FOR(i,a,b) for(ll i=a;i<=(ll)(b);i++) #define rep(i,a,b) for(int i=(int)(a);i<(int)(b);i++) #define ALL(x) begin(x), end(x) #define rrep(i,a,b) for(int i=a;i>=b;i--) #define fore(i,a) for(auto &i:a) #define all(s) (s).begin(),(s).end() #define drep2(i, m, n) for (int i = (m)-1; i >= (n); --i) #define drep(i, n) drep2(i, n, 0) #define rever(vec) reverse(vec.begin(), vec.end()) #define sor(vec) sort(vec.begin(), vec.end()) #define fi first #define se second #define pb push_back #define P pair<ll,ll> #define PQminll priority_queue<ll, vector<ll>, greater<ll>> #define PQmaxll priority_queue<ll,vector<ll>,less<ll>> #define PQminP priority_queue<P, vector<P>, greater<P>> #define PQmaxP priority_queue<P,vector<P>,less<P>> #define NP next_permutation //const ll mod = 1000000009; //const ll mod = 998244353; const ll mod = 1000000007; const ll inf = 4100000000000000000ll; const ld eps = ld(0.00000000001); static const long double pi = 3.141592653589793; template<class T>void vcin(vector<T> &n){for(int i=0;i<int(n.size());i++) cin>>n[i];} template<class T,class K>void vcin(vector<T> &n,vector<K> &m){for(int i=0;i<int(n.size());i++) cin>>n[i]>>m[i];} template<class T>void vcout(vector<T> &n){for(int i=0;i<int(n.size());i++){cout<<n[i]<<" ";}cout<<endl;} template<class T>void vcin(vector<vector<T>> &n){for(int i=0;i<int(n.size());i++){for(int j=0;j<int(n[i].size());j++){cin>>n[i][j];}}} template<class T>void vcout(vector<vector<T>> &n){for(int i=0;i<int(n.size());i++){for(int j=0;j<int(n[i].size());j++){cout<<n[i][j]<<" ";}cout<<endl;}cout<<endl;} void yes(bool a){cout<<(a?"yes":"no")<<endl;} void YES(bool a){cout<<(a?"YES":"NO")<<endl;} void Yes(bool a){cout<<(a?"Yes":"No")<<endl;} void possible(bool a){ cout<<(a?"possible":"impossible")<<endl; } void Possible(bool a){ cout<<(a?"Possible":"Impossible")<<endl; } void POSSIBLE(bool a){ cout<<(a?"POSSIBLE":"IMPOSSIBLE")<<endl; } template<class T>auto min(const T& a){ return *min_element(all(a)); } template<class T>auto max(const T& a){ return *max_element(all(a)); } template<class T,class F>void print(pair<T,F> a){cout<<a.fi<<" "<<a.se<<endl;} template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0;} template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0;} template<class T> void ifmin(T t,T u){if(t>u){cout<<-1<<endl;}else{cout<<t<<endl;}} template<class T> void ifmax(T t,T u){if(t>u){cout<<-1<<endl;}else{cout<<t<<endl;}} ll fastgcd(ll u,ll v){ll shl=0;while(u&&v&&u!=v){bool eu=!(u&1);bool ev=!(v&1);if(eu&&ev){++shl;u>>=1;v>>=1;}else if(eu&&!ev){u>>=1;}else if(!eu&&ev){v>>=1;}else if(u>=v){u=(u-v)>>1;}else{ll tmp=u;u=(v-u)>>1;v=tmp;}}return !u?v<<shl:u<<shl;} ll modPow(ll a, ll n, ll mod) { if(mod==1) return 0;ll ret = 1; ll p = a % mod; while (n) { if (n & 1) ret = ret * p % mod; p = p * p % mod; n >>= 1; } return ret; } vector<ll> divisor(ll x){ vector<ll> ans; for(ll i = 1; i * i <= x; i++){ if(x % i == 0) {ans.push_back(i); if(i*i!=x){ ans.push_back(x / ans[i]);}}}sor(ans); return ans; } ll pop(ll x){return __builtin_popcountll(x);} ll poplong(ll x){ll y=-1;while(x){x/=2;y++;}return y;} P hyou(P a){ll x=fastgcd(abs(a.fi),abs(a.se));a.fi/=x;a.se/=x;if(a.se<0){a.fi*=-1;a.se*=-1;}return a;} P Pplus(P a,P b){ return hyou({a.fi*b.se+b.fi*a.se,a.se*b.se});} P Ptimes(P a,ll b){ return hyou({a.fi*b,a.se});} P Ptimes(P a,P b){ return hyou({a.fi*b.fi,a.se*b.se});} P Pminus(P a,P b){ return hyou({a.fi*b.se-b.fi*a.se,a.se*b.se});} P Pgyaku(P a){ return hyou({a.se,a.fi});} template<class T> struct Sum{ vector<T> data; Sum(const vector<T>& v):data(v.size()+1){ for(ll i=0;i<v.size();i++) data[i+1]=data[i]+v[i]; } T get(ll l,ll r) const { return data[r]-data[l]; } }; template<class T> struct Sum2{ vector<vector<T>> data; Sum2(const vector<vector<T>> &v):data(v.size()+1,vector<T>(v[0].size()+1)){ for(int i=0;i<v.size();i++) for(int j=0;j<v[i].size();j++) data[i+1][j+1]=data[i][j+1]+v[i][j]; for(int i=0;i<v.size();i++) for(int j=0;j<v[i].size();j++) data[i+1][j+1]+=data[i+1][j]; } T get(ll x1,ll y1,ll x2,ll y2) const { return data[x2][y2]+data[x1][y1]-data[x1][y2]-data[x2][y1]; } }; void cincout(){ ios::sync_with_stdio(false); std::cin.tie(nullptr); cout<< fixed << setprecision(15); } using mint = modint998244353; int main() { cincout(); ll n; cin>>n; vector<mint> dp(4); dp[0]=1; vector<mint> a={1,mint(1)/mint(1),mint(1)/mint(2),mint(1)/mint(6)}; for(int i=1;i<=n;i++){ vector<mint> dp2(4); for(int j=0;j<=3;j++){ for(int k=j;k<=3;k++){ if(j!=k) dp2[k]+=dp[j]*a[k-j]; else dp2[k]+=dp[j]*i; } } dp=dp2; } dp[3]*=6; cout<<dp[3].val()<<endl; }