結果
問題 | No.2152 [Cherry Anniversary 2] 19 Petals of Cherry |
ユーザー | Shirotsume |
提出日時 | 2022-12-09 00:40:04 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,064 bytes |
コンパイル時間 | 244 ms |
コンパイル使用メモリ | 82,284 KB |
実行使用メモリ | 89,088 KB |
最終ジャッジ日時 | 2024-10-14 18:21:03 |
合計ジャッジ時間 | 13,796 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 200 ms
88,320 KB |
testcase_01 | WA | - |
testcase_02 | AC | 190 ms
88,192 KB |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | AC | 246 ms
88,320 KB |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | WA | - |
testcase_20 | AC | 276 ms
88,320 KB |
testcase_21 | WA | - |
testcase_22 | WA | - |
testcase_23 | WA | - |
testcase_24 | WA | - |
testcase_25 | WA | - |
testcase_26 | WA | - |
testcase_27 | WA | - |
testcase_28 | WA | - |
testcase_29 | WA | - |
testcase_30 | WA | - |
testcase_31 | WA | - |
testcase_32 | WA | - |
testcase_33 | WA | - |
testcase_34 | WA | - |
testcase_35 | WA | - |
testcase_36 | WA | - |
testcase_37 | WA | - |
testcase_38 | WA | - |
testcase_39 | WA | - |
testcase_40 | WA | - |
testcase_41 | WA | - |
testcase_42 | WA | - |
testcase_43 | WA | - |
testcase_44 | WA | - |
testcase_45 | WA | - |
testcase_46 | WA | - |
testcase_47 | AC | 193 ms
88,576 KB |
testcase_48 | AC | 273 ms
88,576 KB |
ソースコード
import sys from collections import deque, Counter sys.setrecursionlimit(5 * 10 ** 5) from pypyjit import set_param set_param('max_unroll_recursion=-1') input = lambda: sys.stdin.readline().rstrip() ii = lambda: int(input()) mi = lambda: map(int, input().split()) li = lambda: list(mi()) inf = 2 ** 63 - 1 mod = 998244353 n = 19 A = [] even = 0 odd = 0 for i in range(n): x = li() now = 0 for v in x[1:]: now |= 2 ** (v-1) A.append(now) if i % 2: odd |= now else: even |= now ppcnt = [0] * (1 << n) for i in range(1<<n): ppcnt[i] = ppcnt[i//2] + i % 2 dp0 = [0] * (1<<n) dp1 = [0] * (1<<n) dp0[0] = 1 for bit in range(1<<n): for i in range(n): if not(1 & (bit >> i)): if 1 & (A[i] >> (ppcnt[bit])): if i != ppcnt[bit] + 1: dp1[bit | (1<<i)] += dp0[bit] dp0[bit | (1<<i)] += dp1[bit] else: dp1[bit | (1<<i)] += dp1[bit] dp0[bit | (1<<i)] += dp0[bit] print(dp0[-1], dp1[-1])