結果

問題 No.2156 ぞい文字列
ユーザー mikammikam
提出日時 2022-12-09 21:46:08
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 6,059 bytes
コンパイル時間 4,765 ms
コンパイル使用メモリ 273,496 KB
実行使用メモリ 6,824 KB
最終ジャッジ日時 2024-10-14 21:25:42
合計ジャッジ時間 5,454 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 16
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <atcoder/all>
using namespace atcoder;
#include <bits/stdc++.h>
using namespace std;
// #include <boost/multiprecision/cpp_int.hpp>
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define rep2(i,a,b) for (int i = (int)(a); i < (int)(b); i++)
#define all(v) v.begin(),v.end()
#define inc(x,l,r) ((l)<=(x)&&(x)<(r)) 
#define Unique(x) sort(all(x)), x.erase(unique(all(x)), x.end())
typedef long long ll;
#define int ll
using ld = long double;
using vi = vector<int>;
using vs = vector<string>;
using P = pair<int,int>;
using vp = vector<P>;
// using Bint = boost::multiprecision::cpp_int;
template<typename T> using priority_queue_greater = priority_queue<T, vector<T>, greater<T>>;
template<typename T> ostream &operator<<(ostream &os,const vector<T> &v){rep(i,v.size())os<<v[i]<<(i+1!=v.size()?" ":"");return os;}
template<typename T> istream &operator>>(istream& is,vector<T> &v){for(T &in:v)is>>in;return is;}
template<class... T> void _IN(T&... a){(cin>> ... >> a);}
template<class T> void _OUT(T& a){cout <<a<< '\n';}
template<class T,class... Ts> void _OUT(const T&a, const Ts&... b){cout<< a;(cout<<...<<(cout<<' ',b));cout<<'\n';}
#define INT(...) int __VA_ARGS__; _IN(__VA_ARGS__)
#define STR(...) string __VA_ARGS__; _IN(__VA_ARGS__)
#define pcnt __builtin_popcountll
int sign(int x){return (x>0)-(x<0);}
int ceil(int x,int y){assert(y!=0);if(sign(x)==sign(y))return (x+y-1)/y;return -((-x/y));}
int floor(int x,int y){assert(y!=0);if(sign(x)==sign(y))return x/y;if(y<0)x*=-1,y*=-1;return x/y-(x%y<0);}
int abs(int x,int y){return abs(x-y);}
bool ins(string s,string t){return s.find(t)!=string::npos;}
P operator+ (const P &p, const P &q){ return P{p.first+q.first,p.second+q.second};}
P operator- (const P &p, const P &q){ return P{p.first-q.first,p.second-q.second};}
template<typename T1,typename T2> ostream &operator<< (ostream &os, const pair<T1,T2> &p){os << p.first <<" "<<p.second;return os;}
ostream &operator<< (ostream &os, const modint1000000007 &m){os << m.val();return os;}
istream &operator>> (istream &is, modint1000000007 &m){ll in;is>>in;m=in;return is;}
ostream &operator<< (ostream &os, const modint998244353 &m){os << m.val();return os;}
istream &operator>> (istream &is, modint998244353 &m){ll in;is>>in;m=in;return is;}
template<typename T1,typename T2> bool chmax(T1 &a, const T2 b) {if (a < b) {a = b; return true;} else return false; }
template<typename T1,typename T2> bool chmin(T1 &a, const T2 b) {if (a > b) {a = b; return true;} else return false; }
void yesno(bool ok,string y="Yes",string n="No"){ cout<<(ok?y:n)<<endl;}
int di[]={-1,0,1,0,-1,-1,1,1};
int dj[]={0,1,0,-1,-1,1,-1,1};
const int INF = 8e18;
//using mint = modint1000000007;
using mint = modint998244353;
template<typename T=int>
struct Matrix{
    vector<vector<T>> A;
    Matrix(){};
    Matrix(size_t n,size_t m):A(n,vector<T>(m,0)){};
    Matrix(size_t n):A(n,vector<T>(n,0)){};
    Matrix(vector<vector<T>> a) : A(a.size(),vector<T>(a[0].size())){
        for(int i=0;i<a.size();i++)for(int j=0;j<a[0].size();j++)A[i][j] = a[i][j];
    };
    size_t height() const{
        return (A.size());
    }
    size_t width() const{
        return (A[0].size());
    }
    inline const vector<T> &operator[](int k) const{
        return (A.at(k));
    }
    inline vector<T> &operator[](int k){
        return (A.at(k));
    }

    static Matrix I(size_t n){
        Matrix mat(n);
        rep(i,n) mat[i][i]=1;
        return (mat);
    }
    static Matrix O(size_t n){
        Matrix mat(n);
        return (mat);
    }

    Matrix &operator+=(const Matrix &B){
        size_t n = height(),m = width();
        assert(n == B.height() && m == B.width());
        for(int i=0;i<n;i++)for(int j=0;j<m;j++) (*this)[i][j] += B[i][j];
        return *this;
    }
    Matrix &operator-=(const Matrix &B){
        size_t n = height(), m = width();
        assert(n == B.height() && m == B.width());
        for(int i=0;i<n;i++)for(int j=0;j<m;j++) (*this)[i][j] -= B[i][j];
        return *this;
    }
    Matrix &operator*=(const Matrix &B){
        size_t n = height(), m = B.width(), p = width();
        assert(p == B.height());
        vector<vector<T>> C(n,vector<T>(m,0));
        for(int i=0;i<n;i++)for(int j=0;j<m;j++)for(int k=0;k<p;k++) C[i][j] += (*this)[i][k]*B[k][j];
        A.swap(C);
        return *this;
    }
    Matrix &operator+=(const T a){
        size_t n = height(),m = width();
        for(int i=0;i<n;i++)for(int j=0;j<m;j++) (*this)[i][j] += a;
        return *this;
    }
    Matrix &operator-=(const T a){
        size_t n = height(),m = width();
        for(int i=0;i<n;i++)for(int j=0;j<m;j++) (*this)[i][j] -= a;
        return *this;
    }
    Matrix &operator*=(const T a){
        size_t n = height(),m = width();
        for(int i=0;i<n;i++)for(int j=0;j<m;j++) (*this)[i][j] *= a;
        return *this;
    }

    Matrix &operator^=(long long k){
        Matrix B = I(height());
        while(k>0) {
            if(k&1) B *= (*this);
            (*this) *= (*this);
            k/=2;
        }
        A.swap(B.A);
        return *this;
    }

    Matrix operator+(const Matrix &B) const{return (Matrix(*this) += B);}
    Matrix operator-(const Matrix &B) const{return (Matrix(*this) -= B);}
    Matrix operator*(const Matrix &B) const{return (Matrix(*this) *= B);}
    Matrix operator+(const T a) const{return (Matrix(*this) += a);}
    Matrix operator-(const T a) const{return (Matrix(*this) -= a);}
    Matrix operator*(const T a) const{return (Matrix(*this) *= a);}
    Matrix operator^(const long long k) const{return (Matrix(*this) ^= k);}
};
signed main() {
    cin.tie(0);
    ios_base::sync_with_stdio(false);
    cout << fixed << setprecision(20);

    INT(n);
    Matrix<mint> mat(2,2);
    mat[0][0] = 1;
    mat[0][1] = 1;
    mat[1][0] = 1;
    mat[1][1] = 0;
    mat^=(n-1);
    Matrix<mint> a(2,1);
    a[0][0] = 1;
    a[1][0] = 0;
    mat*=a;
    cout<<mat[0][0]+mat[1][0]-1<<endl;

    return 0;
}
0