結果

問題 No.2159 Filling 4x4 array
ユーザー 👑 p-adicp-adic
提出日時 2022-12-11 16:47:02
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 625 ms / 5,000 ms
コード長 11,699 bytes
コンパイル時間 3,293 ms
コンパイル使用メモリ 219,708 KB
実行使用メモリ 6,972 KB
最終ジャッジ日時 2023-08-05 16:30:35
合計ジャッジ時間 19,137 ms
ジャッジサーバーID
(参考情報)
judge12 / judge13
このコードへのチャレンジ(β)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 14 ms
6,824 KB
testcase_01 AC 2 ms
4,380 KB
testcase_02 AC 24 ms
6,764 KB
testcase_03 AC 43 ms
6,720 KB
testcase_04 AC 427 ms
6,912 KB
testcase_05 AC 45 ms
6,972 KB
testcase_06 AC 41 ms
6,912 KB
testcase_07 AC 41 ms
6,700 KB
testcase_08 AC 39 ms
6,752 KB
testcase_09 AC 37 ms
6,820 KB
testcase_10 AC 35 ms
6,752 KB
testcase_11 AC 43 ms
6,692 KB
testcase_12 AC 46 ms
6,720 KB
testcase_13 AC 42 ms
6,824 KB
testcase_14 AC 36 ms
6,816 KB
testcase_15 AC 40 ms
6,756 KB
testcase_16 AC 35 ms
6,712 KB
testcase_17 AC 45 ms
6,760 KB
testcase_18 AC 39 ms
6,812 KB
testcase_19 AC 42 ms
6,700 KB
testcase_20 AC 37 ms
6,704 KB
testcase_21 AC 42 ms
6,712 KB
testcase_22 AC 43 ms
6,700 KB
testcase_23 AC 43 ms
6,752 KB
testcase_24 AC 33 ms
6,824 KB
testcase_25 AC 607 ms
6,752 KB
testcase_26 AC 614 ms
6,824 KB
testcase_27 AC 619 ms
6,692 KB
testcase_28 AC 604 ms
6,700 KB
testcase_29 AC 602 ms
6,720 KB
testcase_30 AC 625 ms
6,764 KB
testcase_31 AC 596 ms
6,700 KB
testcase_32 AC 590 ms
6,816 KB
testcase_33 AC 604 ms
6,748 KB
testcase_34 AC 613 ms
6,752 KB
testcase_35 AC 623 ms
6,908 KB
testcase_36 AC 607 ms
6,700 KB
testcase_37 AC 607 ms
6,768 KB
testcase_38 AC 614 ms
6,748 KB
testcase_39 AC 609 ms
6,748 KB
testcase_40 AC 595 ms
6,820 KB
testcase_41 AC 612 ms
6,760 KB
testcase_42 AC 579 ms
6,820 KB
testcase_43 AC 615 ms
6,812 KB
testcase_44 AC 588 ms
6,748 KB
testcase_45 AC 1 ms
4,376 KB
testcase_46 AC 2 ms
4,380 KB
testcase_47 AC 2 ms
4,376 KB
testcase_48 AC 2 ms
4,380 KB
testcase_49 AC 2 ms
4,384 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#pragma GCC optimize ( "O3" )
#pragma GCC target ( "avx" )
#include <bits/stdc++.h>
using namespace std;

using uint = unsigned int;
using ll = long long;

#define TYPE_OF( VAR ) remove_const<remove_reference<decltype( VAR )>::type >::type
#define UNTIE ios_base::sync_with_stdio( false ); cin.tie( nullptr ) 
#define CEXPR( LL , BOUND , VALUE ) constexpr const LL BOUND = VALUE 
#define CIN( LL , A ) LL A; cin >> A 
#define ASSERT( A , MIN , MAX ) assert( MIN <= A && A <= MAX ) 
#define CIN_ASSERT( A , MIN , MAX ) CIN( TYPE_OF( MAX ) , A ); ASSERT( A , MIN , MAX ) 
#define GETLINE( A ) string A; getline( cin , A ) 
#define GETLINE_SEPARATE( A , SEPARATOR ) string A; getline( cin , A , SEPARATOR ) 
#define FOR( VAR , INITIAL , FINAL_PLUS_ONE ) for( TYPE_OF( FINAL_PLUS_ONE ) VAR = INITIAL ; VAR < FINAL_PLUS_ONE ; VAR ++ ) 
#define FOREQ( VAR , INITIAL , FINAL ) for( TYPE_OF( FINAL ) VAR = INITIAL ; VAR <= FINAL ; VAR ++ ) 
#define FOREQINV( VAR , INITIAL , FINAL ) for( TYPE_OF( INITIAL ) VAR = INITIAL ; VAR >= FINAL ; VAR -- ) 
#define FOR_ITR( ARRAY , ITR , END ) for( auto ITR = ARRAY .begin() , END = ARRAY .end() ; ITR != END ; ITR ++ ) 
#define REPEAT( HOW_MANY_TIMES ) FOR( VARIABLE_FOR_REPEAT , 0 , HOW_MANY_TIMES ) 
#define QUIT return 0 
#define COUT( ANSWER ) cout << ( ANSWER ) << "\n"; 
#define RETURN( ANSWER ) COUT( ANSWER ); QUIT 
#define DOUBLE( PRECISION , ANSWER ) cout << fixed << setprecision( PRECISION ) << ( ANSWER ) << "\n"; QUIT 

#define POWER( ANSWER , ARGUMENT , EXPONENT )				\
  TYPE_OF( ARGUMENT ) ANSWER{ 1 };					\
  {									\
    TYPE_OF( ARGUMENT ) ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT );	\
    TYPE_OF( EXPONENT ) EXPONENT_FOR_SQUARE_FOR_POWER = ( EXPONENT );	\
    while( EXPONENT_FOR_SQUARE_FOR_POWER != 0 ){			\
      if( EXPONENT_FOR_SQUARE_FOR_POWER % 2 == 1 ){			\
	ANSWER *= ARGUMENT_FOR_SQUARE_FOR_POWER;			\
      }									\
      ARGUMENT_FOR_SQUARE_FOR_POWER *= ARGUMENT_FOR_SQUARE_FOR_POWER;	\
      EXPONENT_FOR_SQUARE_FOR_POWER /= 2;				\
    }									\
  }									\


#define POWER_MOD( ANSWER , ARGUMENT , EXPONENT , MODULO )		\
  TYPE_OF( ARGUMENT ) ANSWER{ 1 };					\
  {									\
    TYPE_OF( ARGUMENT ) ARGUMENT_FOR_SQUARE_FOR_POWER = ( MODULO + ( ARGUMENT ) % MODULO ) % MODULO; \
    TYPE_OF( EXPONENT ) EXPONENT_FOR_SQUARE_FOR_POWER = ( EXPONENT );	\
    while( EXPONENT_FOR_SQUARE_FOR_POWER != 0 ){			\
      if( EXPONENT_FOR_SQUARE_FOR_POWER % 2 == 1 ){			\
	ANSWER = ( ANSWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO;	\
      }									\
      ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT_FOR_SQUARE_FOR_POWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO; \
      EXPONENT_FOR_SQUARE_FOR_POWER /= 2;				\
    }									\
  }									\


#define FACTORIAL_MOD( ANSWER , ANSWER_INV , MAX_I , LENGTH , MODULO )	\
  ll ANSWER[LENGTH];							\
  ll ANSWER_INV[LENGTH];						\
  {									\
    ll VARIABLE_FOR_PRODUCT_FOR_FACTORIAL = 1;				\
    ANSWER[0] = VARIABLE_FOR_PRODUCT_FOR_FACTORIAL;			\
    FOREQ( i , 1 , MAX_I ){						\
      ANSWER[i] = ( VARIABLE_FOR_PRODUCT_FOR_FACTORIAL *= i ) %= MODULO; \
    }									\
    POWER_MOD( FACTORIAL_MAX_INV , ANSWER[MAX_I] , MODULO - 2 , MODULO ); \
    ANSWER_INV[MAX_I] = FACTORIAL_MAX_INV;				\
    FOREQINV( i , MAX_I - 1 , 0 ){					\
      ANSWER_INV[i] = ( FACTORIAL_MAX_INV *= i + 1 ) %= MODULO;		\
    }									\
  }									\
									\

// 通常の二分探索
#define BS( ANSWER , MINIMUM , MAXIMUM , EXPRESSION , TARGET )		\
  ll ANSWER = MAXIMUM;							\
  {									\
    ll VARIABLE_FOR_BINARY_SEARCH_L = MINIMUM;				\
    ll VARIABLE_FOR_BINARY_SEARCH_U = ANSWER;				\
    ll VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( TARGET ) - ( EXPRESSION ); \
    if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH == 0 ){		\
      VARIABLE_FOR_BINARY_SEARCH_L = ANSWER;				\
    } else {								\
      ANSWER = ( VARIABLE_FOR_BINARY_SEARCH_L + VARIABLE_FOR_BINARY_SEARCH_U ) / 2; \
    }									\
    while( VARIABLE_FOR_BINARY_SEARCH_L != ANSWER ){			\
      VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( TARGET ) - ( EXPRESSION ); \
      if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH == 0 ){		\
	VARIABLE_FOR_BINARY_SEARCH_L = ANSWER;				\
	break;								\
      } else {								\
	if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH > 0 ){		\
	  VARIABLE_FOR_BINARY_SEARCH_L = ANSWER;			\
	} else {							\
	  VARIABLE_FOR_BINARY_SEARCH_U = ANSWER;			\
	}								\
	ANSWER = ( VARIABLE_FOR_BINARY_SEARCH_L + VARIABLE_FOR_BINARY_SEARCH_U ) / 2; \
      }									\
    }									\
  }									\
									\


// 二進法の二分探索
#define BS2( ANSWER , MINIMUM , MAXIMUM , EXPRESSION , TARGET )		\
  ll ANSWER = MINIMUM;							\
  {									\
    ll VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 = 1;			\
    ll VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( MAXIMUM ) - ANSWER; \
    while( VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 <= VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH ){ \
      VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 *= 2;			\
    }									\
    VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 /= 2;			\
    ll VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 = ANSWER;		\
    while( VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 != 0 ){		\
      ANSWER = VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 + VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2; \
      VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( TARGET ) - ( EXPRESSION ); \
      if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH == 0 ){		\
	VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 = ANSWER;		\
	break;								\
      } else if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH > 0 ){	\
	VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 = ANSWER;		\
      }									\
      VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 /= 2;			\
    }									\
    ANSWER = VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2;			\
  }									\
									\


template <typename T> inline T Absolute( const T& a ){ return a > 0 ? a : - a; }
template <typename T> inline T Residue( const T& a , const T& p ){ return a >= 0 ? a % p : p - ( - a - 1 ) % p - 1; }

int main()
{
  UNTIE;
  CEXPR( int , bound , 1000000000 );
  int hw[2][4];
  int sum[2] = {};
  FOR( k , 0 , 2 ){
    int ( &hw_k )[4] = hw[k];
    int& sum_k = sum[k];
    FOR( i , 0 , 4 ){
      CIN_ASSERT( hwi , 4 , bound );
      sum_k += hw_k[i] = hwi - 4;
    }
  }
  if( sum[0] != sum[1] ){
    RETURN( 0 );
  }
  // 次の繰り上がり計算に使う3以下のデータ6個を2進法で12桁のデータに纏めたもの(以下「桁和」)の上限値
  CEXPR( int , assign_sum_lim , 1 << 12 );
  // 桁和から元のデータを復元する
  static int assign_sum[assign_sum_lim][2][3] = {};
  int t_copy;
  FOR( t , 0 , assign_sum_lim ){
    t_copy = t;
    int ( &assign_sum_t )[2][3] = assign_sum[t];
    FOR( k , 0 , 2 ){
      int ( &assign_sum_t_k )[3] = assign_sum_t[k];
      FOR( i , 0 , 3 ){
	assign_sum_t_k[i] = t_copy % 4;
	t_copy /= 4;
      }
    }
  }
  // 次の桁を表す1以下のデータ9個を2進法で9桁のデータに纏めてたもの(以下「桁値」)の上限
  CEXPR( int , assign_lim , 1 << 9 );
  // 桁値を動かした時の次の桁和の重複を格納
  static int multiple[assign_sum_lim] = {};
  int assign[3][3] = {};
  int assign_sum_curr;
  FOR( t , 0 , assign_lim ){
    t_copy = t;
    FOR( i , 0 , 3 ){
      int ( &assign_i )[3] = assign[i];
      FOR( j , 0 , 3 ){
	assign_i[j] = t_copy % 2;
	t_copy /= 2;
      }
    }
    assign_sum_curr = 0;
    {
      FOR( i , 0 , 3 ){
	assign_sum_curr *= 4;
	int ( &assign_i )[3] = assign[i];
	FOR( j , 0 , 3 ){
	  assign_sum_curr += assign_i[j];
	}
      }
    }
    {
      FOR( j , 0 , 3 ){
	assign_sum_curr *= 4;
	FOR( i , 0 , 3 ){
	  assign_sum_curr += assign[i][j];
	}
      }
    }
    multiple[assign_sum_curr]++;
  }
  // multipleが正の桁和の抽出
  int valid_sum_num = 0;
  static int valid_sum[assign_lim];
  FOR( t , 0 , assign_sum_lim ){
    if( multiple[t] > 0 ){
      valid_sum[valid_sum_num] = t;
      valid_sum_num++;
    }
  }
  // hwの成分を2進法表記した時の特定の桁のデータ
  int hw_r[2][4];
  // 繰り上がりの値である(4-1)以下のデータ8個を2進法で16桁のデータ(以下「状態」)に纏めたものの上限値
  CEXPR( int , state_lim , 1 << 16 );
  // 状態から元のデータを復元する
  static int state[state_lim][2][4] = {};
  FOR( s , 0 , state_lim ){
    int ( &state_s )[2][4] = state[s];
    t_copy = s;
    FOR( k , 0 , 2 ){
      int ( &state_s_k )[4] = state_s[k];
      FOR( i , 0 , 4 ){
	state_s_k[i] = t_copy % 4;
	t_copy /= 4;
      }
    }
  }
  // 次の状態を格納
  int hw_next[2][4];
  // 各状態ごとの、特定の桁までの数え上げ
  vector<ll> count[2] = {};
  vector<ll> count_init( state_lim );
  {
    vector<ll>& count0 = count[0];
    count0 = count_init;
    count0[0] = 1;
  }
  int i_prev = 0;
  int i_curr = 1;
  int valid_sum_t , rest_assign_sum , diff , sa_sum , s_next;
  CEXPR( ll , P , 998244353 );
  bool computing = true;
  while( computing ){
    vector<ll>& count_prev = count[i_prev];
    vector<ll>& count_curr = count[i_curr];
    count_curr = count_init;
    FOR( k , 0 , 2 ){
      int ( &hw_k )[4] = hw[k];
      int ( &hw_r_k )[4] = hw_r[k];
      FOR( i , 0 , 4 ){
	hw_r_k[i] = hw_k[i] % 2;
      }
    }
    FOR( s , 0 , state_lim ){
      ll& count_prev_s = count_prev[s];
      if( count_prev_s != 0 ){
	int ( &state_s )[2][4] = state[s];
	FOR( t , 0 , valid_sum_num ){
	  valid_sum_t = valid_sum[t];
	  int ( &assign_sum_t )[2][3] = assign_sum[valid_sum_t];
	  // 桁和から次の状態を計算する(つまり残りの16-9個の変数を決定し和を8個取る)
	  {
	    int k = 0;
	    int ( &hw_r_k )[4] = hw_r[k];
	    int ( &hw_next_k )[4] = hw_next[k];
	    int ( &assign_sum_t_k )[3] = assign_sum_t[k];
	    int ( &state_s_k )[4] = state_s[k];
	    rest_assign_sum = 0;
	    FOR( i , 0 , 3 ){
	      int& hw_next_k_i = hw_next_k[i];
	      sa_sum = state_s_k[i] + assign_sum_t_k[i];
	      rest_assign_sum += diff = ( hw_r_k[i] + sa_sum ) % 2;
	      hw_next_k_i = ( sa_sum + diff ) / 2;
	    }
	  }
	  {
	    int k = 1;
	    int ( &hw_r_k )[4] = hw_r[k];
	    int ( &hw_next_k )[4] = hw_next[k];
	    int ( &assign_sum_t_k )[3] = assign_sum_t[k];
	    int ( &state_s_k )[4] = state_s[k];
	    {
	      int i = 3;
	      int& hw_next_k_i = hw_next_k[i];
	      sa_sum = state_s_k[i] + rest_assign_sum;
	      diff = ( hw_r_k[i] + sa_sum ) % 2;
	      hw_next_k_i = ( sa_sum + diff ) / 2;
	    }
	    rest_assign_sum = 0;
	    FOR( i , 0 , 3 ){
	      int& hw_next_k_i = hw_next_k[i];
	      sa_sum = state_s_k[i] + assign_sum_t_k[i];
	      rest_assign_sum += diff = ( hw_r_k[i] + sa_sum ) % 2;
	      hw_next_k_i = ( sa_sum + diff ) / 2;
	    }
	  }
	  {
	    int k = 0;
	    int ( &hw_r_k )[4] = hw_r[k];
	    int ( &hw_next_k )[4] = hw_next[k];
	    int ( &state_s_k )[4] = state_s[k];
	    {
	      int i = 3;
	      int& hw_next_k_i = hw_next_k[i];
	      sa_sum = state_s_k[i] + rest_assign_sum;
	      diff = ( hw_r_k[i] + sa_sum ) % 2;
	      hw_next_k_i = ( sa_sum + diff ) / 2;
	    }
	  }
	  s_next = 0;
	  FOREQINV( k , 1 , 0 ){
	    int ( &hw_next_k )[4] = hw_next[k];
	    FOREQINV( i , 3 , 0 ){
	      s_next = s_next * 4 + hw_next_k[i];
	    }
	  }
	  count_curr[s_next] += count_prev_s * multiple[valid_sum_t];
	}
      }
    }
    FOR( s , 0 , state_lim ){
      count_curr[s] %= P;
    }
    computing = false;
    FOR( k , 0 , 2 ){
      int ( &hw_k )[4] = hw[k];
      FOR( i , 0 , 4 ){
	if( ( hw_k[i] /= 2 ) != 0 ){
	  computing = true;
	}
      }
    }
    swap( i_prev , i_curr );
  }
  // 最終的には繰り上がりがなくなっていないと一致しないので、状態は0のみ
  RETURN( count[i_prev][0] );
}
0