結果
問題 |
No.635 自然門松列
|
ユーザー |
![]() |
提出日時 | 2023-01-18 20:04:07 |
言語 | Ruby (3.4.1) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,594 bytes |
コンパイル時間 | 308 ms |
コンパイル使用メモリ | 7,552 KB |
実行使用メモリ | 12,544 KB |
最終ジャッジ日時 | 2024-06-11 20:24:58 |
合計ジャッジ時間 | 3,045 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 16 WA * 4 RE * 3 |
コンパイルメッセージ
Syntax OK
ソースコード
N = gets.to_i def check1(x1, x2, x3, y1, y2, y3) return true if x1 != x2 && x1 != x3 && x2 != x3 && x1 < x2 && x2 > x3 return true if y1 != y2 && y1 != y3 && y2 != y3 && y1 < y2 && y2 > y3 return false if x1 >= x2 && y1 >= y2 return false if x2 <= x3 && y2 <= y3 return false if x1 == x3 && y1 == y3 range1 = if x1 >= x2 && y1 < y2 diff = x1 - x2 + 1 time = Rational(diff, y2 - y1).ceil [time, Float::INFINITY] elsif x1 < x2 if y1 > y2 diff = x2 - x1 time = Rational(diff, y1 - y2).ceil [0, time] else [0, Float::INFINITY] end end range2 = if x2 <= x3 && y2 > y3 diff = x3 - x2 + 1 time = Rational(diff, y2 - y3).ceil [time, Float::INFINITY] elsif x2 > x3 if y2 < y3 diff = y3 - y2 time = Rational(diff, y3 - y2).ceil [0, time] else [0, Float::INFINITY]; end end if range2[0] <= range1[1] true elsif range1[0] <= range2[1] true else false end end def check2(x1, x2, x3, y1, y2, y3) return true if x1 != x2 && x1 != x3 && x2 != x3 && x1 > x2 && x2 < x3 return true if y1 != y2 && y1 != y3 && y2 != y3 && y1 > y2 && y2 < y3 return false if x1 <= x2 && y1 <= y2 return false if x2 >= x3 && y2 >= y3 return false if x1 == x3 && y1 == y3 range1 = if x1 <= x2 && y1 > y2 diff = x2 - x1 + 1 time = Rational(diff, y1 - y1).ceil [time, Float::INFINITY] elsif x1 > x2 if y1 < y2 diff = x1 - x2 time = Rational(diff, y2 - y1).ceil [0, time] else [0, Float::INFINITY] end end range2 = if x2 >= x3 && y2 < y3 diff = x2 - x3 + 1 time = Rational(diff, y3 - y2).ceil [time, Float::INFINITY] elsif x2 < x3 if y2 > y3 diff = x3 - x2 time = Rational(diff, y2 - y3).ceil [0, time] else [0, Float::INFINITY] end end if range2[0] <= range1[1] true elsif range1[0] <= range2[1] true else false end end N.times do x1, x2, x3, y1, y2, y3 = gets.split.map(&:to_i) if check1(x1, x2, x3, y1, y2, y3) puts "YES" elsif check2(x1, x2, x3, y1, y2, y3) puts "YES" else puts "NO" end end