結果
問題 | No.2209 Flip and Reverse |
ユーザー |
|
提出日時 | 2023-02-10 21:27:34 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 389 ms / 2,000 ms |
コード長 | 4,928 bytes |
コンパイル時間 | 16,148 ms |
コンパイル使用メモリ | 247,248 KB |
最終ジャッジ日時 | 2025-02-10 12:12:05 |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 30 |
ソースコード
#pragma GCC target("avx2")#pragma GCC optimize("O3")#pragma GCC optimize("unroll-loops")#include <atcoder/all>#include <iostream> // cout, endl, cin#include <string> // string, to_string, stoi#include <vector> // vector#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound#include <utility> // pair, make_pair#include <tuple> // tuple, make_tuple#include <cstdint> // int64_t, int*_t#include <cstdio> // printf#include <map> // map#include <queue> // queue, priority_queue#include <set> // set#include <stack> // stack#include <deque> // deque#include <unordered_map> // unordered_map#include <unordered_set> // unordered_set#include <bitset> // bitset#include <cctype> // isupper, islower, isdigit, toupper, tolower#include <math.h>#include <iomanip>#include <functional>using namespace std;using namespace atcoder;#define rep(i, n) for (int i = 0; i < (int)(n); i++)#define repi(i, a, b) for (int i = (int)(a); i < (int)(b); i++)typedef long long ll;typedef unsigned long long ull;const ll inf=1e18;using graph = vector<vector<int> > ;using P= pair<ll,ll>;using vi=vector<int>;using vvi=vector<vi>;using vll=vector<ll>;using vvll=vector<vll>;using vp=vector<P>;using vpp=vector<vp>;using vd=vector<double>;using vvd =vector<vd>;//string T="ABCDEFGHIJKLMNOPQRSTUVWXYZ";//string S="abcdefghijklmnopqrstuvwxyz";//g++ main.cpp -std=c++17 -I .//cout <<setprecision(20);//cout << fixed << setprecision(10);//cin.tie(0); ios::sync_with_stdio(false);const double PI = acos(-1);int vx[]={0,1,0,-1,-1,1,1,-1},vy[]={1,0,-1,0,1,1,-1,-1};void putsYes(bool f){cout << (f?"Yes":"No") << endl;}void putsYES(bool f){cout << (f?"YES":"NO") << endl;}void putsFirst(bool f){cout << (f?"First":"Second") << endl;}template<class T> void debug(T s){cout << "test" << " " << s << endl;}ll pow_pow(ll x,ll n,ll mod){if(n==0) return 1;x%=mod;ll res=pow_pow(x*x%mod,n/2,mod);if(n&1)res=res*x%mod;return res;}ll gcd(ll x,ll y){if(y==0)return x;return gcd(y,x%y);}ll lcm(ll x,ll y){return ll(x/gcd(x,y))*y;}template<class T> bool chmin(T& a, T b) {if (a > b) {a = b;return true;}else return false;}template<class T> bool chmax(T& a, T b) {if (a < b) {a = b;return true;}else return false;}// https://youtu.be/L8grWxBlIZ4?t=9858// https://youtu.be/ERZuLAxZffQ?t=4807 : optimize// https://youtu.be/8uowVvQ_-Mo?t=1329 : divisionll mod =1e9+7;struct mint {ll x; // typedef long long ll;mint(ll x=0):x((x%mod+mod)%mod){}mint operator-() const { return mint(-x);}mint& operator+=(const mint a) {if ((x += a.x) >= mod) x -= mod;return *this;}mint& operator-=(const mint a) {if ((x += mod-a.x) >= mod) x -= mod;return *this;}mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}mint operator+(const mint a) const { return mint(*this) += a;}mint operator-(const mint a) const { return mint(*this) -= a;}mint operator*(const mint a) const { return mint(*this) *= a;}mint pow(ll t) const {if (!t) return 1;mint a = pow(t>>1);a *= a;if (t&1) a *= *this;return a;}// for prime modmint inv() const { return pow(mod-2);}mint& operator/=(const mint a) { return *this *= a.inv();}mint operator/(const mint a) const { return mint(*this) /= a;}};istream& operator>>(istream& is, const mint& a) { return is >> a.x;}ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}// combination mod prime// https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619struct combination {vector<mint> fact, ifact;combination(int n):fact(n+1),ifact(n+1) {//assert(n < mod);fact[0] = 1;for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;ifact[n] = fact[n].inv();for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;}mint operator()(int n, int k) {if (k < 0 || k > n) return 0;return fact[n]*ifact[k]*ifact[n-k];} mint p(int n, int k) { return fact[n]*ifact[n-k]; } } c(5000000);using vm=vector<mint> ;using vvm=vector<vm> ;ll sqrt_(ll x) {ll l = 0, r = ll(3e9)+1;while (l+1<r) {ll c = (l+r)/2;if (c*c <= x) l = c; else r = c;}return l;}int valid(int x,int y,int h,int w){if(x>=0 && y>=0 && x<h && y<w)return 1;else return 0;}struct edge{int to; int w;edge(int to,int w) : to(to),w(w){}};using ve=vector<edge>;using vve=vector<ve>;using vvp=vector<vp>;//g++ main.cpp -std=c++17 -I .int main(){cin.tie(0);ios::sync_with_stdio(false);int n; cin >> n;string s;cin >> s;string t; cin >> t;string invs=s;reverse(invs.begin(),invs.end());int cnt=0;int ans=n+5;rep(i,n)if(s[i]!=t[i])cnt++;if(cnt%2==0)ans=cnt;cnt=0;rep(i,n)if(invs[i]!=t[i])cnt++;if(cnt%2)chmin(ans,cnt);cout << ans << endl;}