結果
問題 | No.1611 Minimum Multiple with Double Divisors |
ユーザー | mkawa2 |
提出日時 | 2023-03-09 22:40:10 |
言語 | PyPy3 (7.3.15) |
結果 |
RE
|
実行時間 | - |
コード長 | 1,438 bytes |
コンパイル時間 | 227 ms |
コンパイル使用メモリ | 82,400 KB |
実行使用メモリ | 71,932 KB |
最終ジャッジ日時 | 2024-09-18 03:05:37 |
合計ジャッジ時間 | 3,958 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | RE | - |
testcase_01 | RE | - |
testcase_02 | RE | - |
testcase_03 | RE | - |
testcase_04 | RE | - |
testcase_05 | RE | - |
testcase_06 | RE | - |
testcase_07 | RE | - |
testcase_08 | RE | - |
testcase_09 | RE | - |
testcase_10 | RE | - |
testcase_11 | RE | - |
testcase_12 | RE | - |
testcase_13 | RE | - |
testcase_14 | RE | - |
testcase_15 | RE | - |
testcase_16 | RE | - |
testcase_17 | RE | - |
testcase_18 | RE | - |
testcase_19 | RE | - |
testcase_20 | RE | - |
testcase_21 | RE | - |
testcase_22 | RE | - |
testcase_23 | RE | - |
testcase_24 | RE | - |
testcase_25 | RE | - |
testcase_26 | RE | - |
testcase_27 | RE | - |
testcase_28 | AC | 38 ms
52,780 KB |
testcase_29 | AC | 39 ms
53,304 KB |
testcase_30 | AC | 38 ms
53,140 KB |
testcase_31 | AC | 37 ms
53,344 KB |
testcase_32 | AC | 38 ms
53,204 KB |
testcase_33 | AC | 39 ms
53,704 KB |
testcase_34 | AC | 37 ms
52,524 KB |
testcase_35 | AC | 38 ms
52,584 KB |
testcase_36 | AC | 38 ms
52,988 KB |
testcase_37 | AC | 37 ms
53,748 KB |
testcase_38 | AC | 38 ms
52,532 KB |
ソースコード
import sys # sys.setrecursionlimit(200005) int1 = lambda x: int(x)-1 pDB = lambda *x: print(*x, end="\n", file=sys.stderr) p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr) def II(): return int(sys.stdin.readline()) def LI(): return list(map(int, sys.stdin.readline().split())) def LLI(rows_number): return [LI() for _ in range(rows_number)] def LI1(): return list(map(int1, sys.stdin.readline().split())) def LLI1(rows_number): return [LI1() for _ in range(rows_number)] def SI(): return sys.stdin.readline().rstrip() dij = [(0, 1), (-1, 0), (0, -1), (1, 0)] # dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)] inf = (1 << 63)-1 # inf = (1 << 31)-1 # md = 10**9+7 md = 998244353 prime = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31] def solve(): x0 = x = II() mn = inf to = [[] for _ in range(11)] for p in prime: e = 1 while x%p == 0: x //= p e += 1 if e == 1: mn = p break c = p v = e+1 while c < 31 and e < 11: to[e].append((v, c)) c *= p v += 1 for s in range(2, 6): dist = [inf]*11 dist[s] = 1 for u in range(min(s*2, 11)): for v, c in to[u]: nd = dist[u]*c dist[v] = min(dist[v], nd) mn = min(mn, dist[s*2]) print(x0*mn) for _ in range(II()): solve()