結果
問題 | No.2244 Integer Complete |
ユーザー | Jeroen Op de Beek |
提出日時 | 2023-03-10 23:18:55 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,264 bytes |
コンパイル時間 | 2,094 ms |
コンパイル使用メモリ | 205,016 KB |
実行使用メモリ | 6,948 KB |
最終ジャッジ日時 | 2024-09-18 05:29:34 |
合計ジャッジ時間 | 4,636 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 2 ms
5,376 KB |
testcase_07 | AC | 2 ms
5,376 KB |
testcase_08 | AC | 2 ms
5,376 KB |
testcase_09 | AC | 2 ms
5,376 KB |
testcase_10 | AC | 2 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | WA | - |
testcase_16 | AC | 2 ms
5,376 KB |
testcase_17 | AC | 19 ms
5,376 KB |
testcase_18 | AC | 18 ms
5,376 KB |
testcase_19 | AC | 22 ms
5,376 KB |
testcase_20 | AC | 51 ms
5,376 KB |
testcase_21 | AC | 52 ms
5,376 KB |
testcase_22 | WA | - |
testcase_23 | AC | 9 ms
5,376 KB |
testcase_24 | AC | 48 ms
5,376 KB |
testcase_25 | WA | - |
testcase_26 | WA | - |
testcase_27 | AC | 55 ms
5,376 KB |
testcase_28 | AC | 26 ms
5,376 KB |
testcase_29 | AC | 56 ms
5,376 KB |
testcase_30 | AC | 50 ms
5,376 KB |
testcase_31 | AC | 10 ms
5,376 KB |
testcase_32 | AC | 9 ms
5,376 KB |
testcase_33 | AC | 4 ms
5,376 KB |
testcase_34 | AC | 15 ms
5,376 KB |
testcase_35 | WA | - |
testcase_36 | WA | - |
testcase_37 | WA | - |
testcase_38 | WA | - |
testcase_39 | AC | 12 ms
5,376 KB |
testcase_40 | AC | 11 ms
5,376 KB |
testcase_41 | AC | 13 ms
5,376 KB |
testcase_42 | AC | 13 ms
5,376 KB |
testcase_43 | WA | - |
testcase_44 | WA | - |
testcase_45 | WA | - |
testcase_46 | WA | - |
testcase_47 | WA | - |
testcase_48 | AC | 12 ms
5,376 KB |
testcase_49 | AC | 12 ms
5,376 KB |
testcase_50 | AC | 12 ms
5,376 KB |
testcase_51 | AC | 18 ms
5,376 KB |
testcase_52 | AC | 18 ms
5,376 KB |
testcase_53 | AC | 15 ms
5,376 KB |
testcase_54 | AC | 15 ms
5,376 KB |
testcase_55 | WA | - |
testcase_56 | WA | - |
testcase_57 | WA | - |
testcase_58 | WA | - |
testcase_59 | WA | - |
ソースコード
#include "bits/stdc++.h" using namespace std; #define all(x) begin(x),end(x) template<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { return os << '(' << p.first << ", " << p.second << ')'; } template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> ostream& operator<<(ostream &os, const T_container &v) { string sep; for (const T &x : v) os << sep << x, sep = " "; return os; } #define debug(a) cerr << "(" << #a << ": " << a << ")\n"; typedef long long ll; typedef vector<int> vi; typedef vector<vi> vvi; typedef pair<int,int> pi; const int mxN = 1e5+1, oo = 1e9; int main() { // ok, what can I not do? // some integer such that // prime you cannot make at least... // 1e4 + something to be prime, it's impossible to make // so can just brute force check 1e4 candidates. // for each candidate, factorize int n,m; cin >> n >> m; vi a(n),b(m); for(auto& i : a) cin >> i; for(auto& i : b) cin >> i; // can make a lot more numbers than I thought // some prime such that it's not within those and not within those? // actually a bit like convolution. // but multiplicative. // answer not bigger than 1e9+7. // if you just constantly do the least thing not being able // ok, a prime number has to be made by 1 p, or p 1. // so if there's some gap, than immediately smaller than the gap you win // everything up to that can be made vi cnt(max(*max_element(all(a)), *max_element(all(b))) + 100); for(int i : a) cnt[i]++; for(int j : b) cnt[j]++; int i=1; if(cnt[1]==2) { while(cnt[i]) ++i; } // now restrict to here // need to test ~1e4 candidates for(ll c=i*i;;c++) { bool gd=0; auto check = [&](ll i, ll j) { i = sqrtl(i+0.5), j =sqrtl(j+0.5); cnt[i]--; cnt[j]--; if(cnt[i]>=0 and cnt[j]>=0) gd=1; cnt[i]++,cnt[j]++; }; for(ll j=1;j*j<=c;++j) { if(c%j==0) { check(j,c/j); check(c/j,j); } } if(!gd) { cout << c << '\n'; break; } } }