結果
| 問題 | No.2127 Mod, Sum, Sum, Mod |
| コンテスト | |
| ユーザー |
tails
|
| 提出日時 | 2023-03-16 15:04:50 |
| 言語 | C90 (gcc 12.3.0) |
| 結果 |
AC
|
| 実行時間 | 5 ms / 2,000 ms |
| コード長 | 287 bytes |
| コンパイル時間 | 841 ms |
| コンパイル使用メモリ | 22,528 KB |
| 実行使用メモリ | 5,376 KB |
| 最終ジャッジ日時 | 2024-09-18 09:21:20 |
| 合計ジャッジ時間 | 1,911 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 27 |
コンパイルメッセージ
main.c:9:1: warning: return type defaults to ‘int’ [-Wimplicit-int]
9 | main(){
| ^~~~
main.c: In function ‘main’:
main.c:11:9: warning: implicit declaration of function ‘scanf’ [-Wimplicit-function-declaration]
11 | scanf("%d%d",&n,&i);
| ^~~~~
main.c:1:1: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’
+++ |+#include <stdio.h>
1 | typedef __int128_t t;
main.c:11:9: warning: incompatible implicit declaration of built-in function ‘scanf’ [-Wbuiltin-declaration-mismatch]
11 | scanf("%d%d",&n,&i);
| ^~~~~
main.c:11:9: note: include ‘<stdio.h>’ or provide a declaration of ‘scanf’
main.c:11:17: warning: format ‘%d’ expects argument of type ‘int *’, but argument 2 has type ‘t *’ {aka ‘__int128 *’} [-Wformat=]
11 | scanf("%d%d",&n,&i);
| ~^ ~~
| | |
| | t * {aka __int128 *}
| int *
main.c:11:19: warning: format ‘%d’ expects argument of type ‘int *’, but argument 3 has type ‘t *’ {aka ‘__int128 *’} [-Wformat=]
11 | scanf("%d%d",&n,&i);
| ~^ ~~
| | |
| int * t * {aka __int128 *}
main.c:18:9: warning: implicit declaration of function ‘printf’ [-Wimplicit-function-declaration]
18 | printf("%d",a%998244353);
| ^~~~~~
main.c:18:9: note: include ‘<stdio.h>’ or provide a declaration of ‘printf’
main.c:18:9: warning: incompatible implicit declaration of built-in function ‘printf’ [-Wbuiltin-declaration-mismatch]
main.c:18:9: note: include ‘<stdio.h>’ or provide a declaration of ‘printf’
main.c:18:18: warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘t’ {aka ‘__int128’} [-Wformat=]
18 | printf("%d",a%998244353);
| ~^ ~~~~~
ソースコード
typedef __int128_t t;
t f(t i,t n,t v){
t i2=i*(i+1)/2;
t i3=i2*(i*2+1)/3;
t n2=n*(n+1)/2;
t v2=v*(v+1)/2;
return i*n2-i2*(n+1)*v+i3*v2;
}
main(){
t n=0,i=0,a=0,v;
scanf("%d%d",&n,&i);
while(i){
v=n/i;
a+=f(i,n,v);
i=n/(v+1);
a-=f(i,n,v);
}
printf("%d",a%998244353);
}
tails