結果

問題 No.1292 パタパタ三角形
ユーザー sepa38
提出日時 2023-03-29 09:57:37
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 1,179 bytes
コンパイル時間 150 ms
コンパイル使用メモリ 82,700 KB
実行使用メモリ 106,764 KB
最終ジャッジ日時 2024-09-21 03:44:48
合計ジャッジ時間 2,542 ms
ジャッジサーバーID
(参考情報)
judge3 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 5 WA * 9
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

s = list(map(lambda x: ord(x)-97, input()))
dir = [[-1, 0], [1, 0], [0, -1]]
flg = 1
now = [0, 0]
st = set([tuple(now)])
for c in s:
x, y = dir[c]
now[0] += x
now[1] += y
st.add(tuple(now))
if dir[c] == [-1, 0]:
if flg:
for i in range(3):
if dir[i] == [-1, 0]:
dir[i] = [1, 0]
if dir[i] == [1, 0]:
dir[i] = [0, 1]
if dir[i] == [0, -1]:
dir[i] = [0, 1]
else:
for i in range(3):
if dir[i] == [-1, 0]:
dir[i] = [1, 0]
if dir[i] == [1, 0]:
dir[i] = [0, -1]
if dir[i] == [0, 1]:
dir[i] = [-1, 0]
elif dir[c] == [1, 0]:
if flg:
for i in range(3):
if dir[i] == [1, 0]:
dir[i] = [-1, 0]
if dir[i] == [-1, 0]:
dir[i] = [0, 1]
if dir[i] == [0, -1]:
dir[i] = [1, 0]
else:
for i in range(3):
if dir[i] == [1, 0]:
dir[i] = [-1, 0]
if dir[i] == [-1, 0]:
dir[i] = [0, -1]
if dir[i] == [0, 1]:
dir[i] = [1, 0]
elif dir[c] == [0, -1]:
dir[c] = [0, 1]
elif dir[c] == [0, 1]:
dir[c] = [0, -1]
flg ^= 1
print(len(st))
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