結果

問題 No.1292 パタパタ三角形
ユーザー buey_t
提出日時 2023-03-29 13:39:14
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 227 ms / 2,000 ms
コード長 3,385 bytes
コンパイル時間 225 ms
コンパイル使用メモリ 82,520 KB
実行使用メモリ 124,600 KB
最終ジャッジ日時 2024-09-21 06:41:13
合計ジャッジ時間 4,048 ms
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 14
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

def main():
from math import sqrt,sin,cos,tan,ceil,radians,floor,gcd,exp,log,log10,log2,factorial,fsum
from heapq import heapify, heappop, heappush
from bisect import bisect_left, bisect_right
from copy import deepcopy
import copy
import random
from collections import deque,Counter,defaultdict
from itertools import permutations,combinations
from decimal import Decimal,ROUND_HALF_UP
#tmp = Decimal(mid).quantize(Decimal('0'), rounding=ROUND_HALF_UP)
from functools import lru_cache, reduce
#@lru_cache(maxsize=None)
from operator import add,sub,mul,xor,and_,or_,itemgetter
INF = 10**18
mod1 = 10**9+7
mod2 = 998244353
#DecimalPython
#Python!!!!!!!!!!!!!!!!!!!!!!!!!!
'''
(1,√3)
(0,-1)
(-1,√3)
'''
S = list(input())
N = len(S)
st = set()
u = 'a'
r = 'c'
l = 'b'
x,y = 0,0
st.add((x,y))
rev = 1
for i in range(N):
if rev == 1:
if S[i] == u:
dx,dy = 0,-1
elif S[i] == l:
dx,dy = -1,1
if l == 'b':
u = 'c'
r = 'b'
l = 'a'
elif l == 'a':
u = 'b'
r = 'a'
l = 'c'
else:
u = 'a'
l = 'b'
r = 'c'
else:
dx,dy = 1,1
if u == 'a':
u = 'b'
l = 'c'
r = 'a'
elif u == 'b':
u = 'c'
l = 'a'
r = 'b'
else:
u = 'a'
r = 'c'
l = 'b'
else:
if S[i] == r:
dx,dy = 1,-1
if u == 'a':
u = 'b'
r = 'a'
l = 'c'
elif u == 'b':
u = 'c'
r = 'b'
l = 'a'
else:
u = 'a'
r = 'c'
l = 'b'
elif S[i] == u:
dx,dy = 0,1
else:
dx,dy = -1,-1
if u == 'a':
u = 'c'
l = 'a'
r = 'b'
elif u == 'b':
u = 'a'
l = 'b'
r = 'c'
else:
u = 'b'
l = 'c'
r = 'a'
x += dx
y += dy
st.add((x,y))
rev *= -1
print(len(st))
if __name__ == '__main__':
main()
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