結果

問題 No.2263 Perms
ユーザー ShirotsumeShirotsume
提出日時 2023-04-07 22:41:23
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 5,045 bytes
コンパイル時間 160 ms
コンパイル使用メモリ 82,024 KB
実行使用メモリ 213,888 KB
最終ジャッジ日時 2024-10-02 20:04:34
合計ジャッジ時間 4,545 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 WA -
testcase_01 AC 46 ms
55,424 KB
testcase_02 AC 46 ms
55,552 KB
testcase_03 AC 46 ms
55,424 KB
testcase_04 AC 49 ms
55,680 KB
testcase_05 WA -
testcase_06 TLE -
testcase_07 -- -
testcase_08 -- -
testcase_09 -- -
testcase_10 -- -
testcase_11 -- -
testcase_12 -- -
testcase_13 -- -
testcase_14 -- -
testcase_15 -- -
testcase_16 -- -
testcase_17 -- -
testcase_18 -- -
testcase_19 -- -
testcase_20 -- -
testcase_21 -- -
testcase_22 -- -
testcase_23 -- -
testcase_24 -- -
testcase_25 -- -
testcase_26 -- -
testcase_27 -- -
testcase_28 -- -
testcase_29 -- -
testcase_30 -- -
testcase_31 -- -
testcase_32 -- -
testcase_33 -- -
testcase_34 -- -
testcase_35 -- -
testcase_36 -- -
testcase_37 -- -
testcase_38 -- -
testcase_39 -- -
testcase_40 -- -
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys
from collections import deque, Counter
input = lambda: sys.stdin.readline().rstrip()
ii = lambda: int(input())
mi = lambda: map(int, input().split())
li = lambda: list(mi())
inf = 2 ** 63 - 1
mod = 998244353

import heapq
class mcf_graph():
    n=1
    pos=[]
    g=[[]]
    def __init__(self,N):
        self.n=N
        self.pos=[]
        self.g=[[] for i in range(N)]
    def add_edge(self,From,To,cap,cost):
        assert 0<=From and From<self.n
        assert 0<=To and To<self.n
        m=len(self.pos)
        self.pos.append((From,len(self.g[From])))
        self.g[From].append({"to":To,"rev":len(self.g[To]),"cap":cap,"cost":cost})
        self.g[To].append({"to":From,"rev":len(self.g[From])-1,"cap":0,"cost":-cost})
    def get_edge(self,i):
        m=len(self.pos)
        assert 0<=i and i<m
        _e=self.g[self.pos[i][0]][self.pos[i][1]]
        _re=self.g[_e["to"]][_e["rev"]]
        return {"from":self.pos[i][0],"to":_e["to"],"cap":_e["cap"]+_re["cap"],
        "flow":_re["cap"],"cost":_e["cost"]}
    def edges(self):
        m=len(self.pos)
        result=[{} for i in range(m)]
        for i in range(m):
            tmp=self.get_edge(i)
            result[i]["from"]=tmp["from"]
            result[i]["to"]=tmp["to"]
            result[i]["cap"]=tmp["cap"]
            result[i]["flow"]=tmp["flow"]
            result[i]["cost"]=tmp["cost"]
        return result
    def flow(self,s,t,flow_limit=-1-(-1<<63)):
        return self.slope(s,t,flow_limit)[-1]
    def slope(self,s,t,flow_limit=-1-(-1<<63)):
        assert 0<=s and s<self.n
        assert 0<=t and t<self.n
        assert s!=t
        '''
         variants (C = maxcost):
         -(n-1)C <= dual[s] <= dual[i] <= dual[t] = 0
         reduced cost (= e.cost + dual[e.from] - dual[e.to]) >= 0 for all edge
        '''
        dual=[0 for i in range(self.n)]
        dist=[0 for i in range(self.n)]
        pv=[0 for i in range(self.n)]
        pe=[0 for i in range(self.n)]
        vis=[False for i in range(self.n)]
        def dual_ref():
            for i in range(self.n):
                dist[i]=-1-(-1<<63)
                pv[i]=-1
                pe[i]=-1
                vis[i]=False
            que=[]
            heapq.heappush(que,(0,s))
            dist[s]=0
            while(que):
                v=heapq.heappop(que)[1]
                if vis[v]:continue
                vis[v]=True
                if v==t:break
                '''
                 dist[v] = shortest(s, v) + dual[s] - dual[v]
                 dist[v] >= 0 (all reduced cost are positive)
                 dist[v] <= (n-1)C
                '''
                for i in range(len(self.g[v])):
                    e=self.g[v][i]
                    if vis[e["to"]] or (not(e["cap"])):continue
                    '''
                     |-dual[e.to]+dual[v]| <= (n-1)C
                     cost <= C - -(n-1)C + 0 = nC
                    '''
                    cost=e["cost"]-dual[e["to"]]+dual[v]
                    if dist[e["to"]]-dist[v]>cost:
                        dist[e["to"]]=dist[v]+cost
                        pv[e["to"]]=v
                        pe[e["to"]]=i
                        heapq.heappush(que,(dist[e["to"]],e["to"]))
            if not(vis[t]):
                return False
            for v in range(self.n):
                if not(vis[v]):continue
                dual[v]-=dist[t]-dist[v]
            return True
        flow=0
        cost=0
        prev_cost=-1
        result=[(flow,cost)]
        while(flow<flow_limit):
            if not(dual_ref()):
                break
            c=flow_limit-flow
            v=t
            while(v!=s):
                c=min(c,self.g[pv[v]][pe[v]]["cap"])
                v=pv[v]
            v=t
            while(v!=s):
                self.g[pv[v]][pe[v]]["cap"]-=c
                self.g[v][self.g[pv[v]][pe[v]]["rev"]]["cap"]+=c
                v=pv[v]
            d=-dual[s]
            flow+=c
            cost+=c*d
            if(prev_cost==d):
                result.pop()
            result.append((flow,cost))
            prev_cost=cost
        return result

n, m = mi()

a = [li() for _ in range(n)]
cnt = 0
for i in range(n):
    for j in range(n):
        cnt += a[i][j]
if cnt != n * m:
    print(-1)
    exit()
G = mcf_graph(2 + 2 * n)
S = 2 * n
T = 1 + 2 * n

for i in range(n):
    for j in range(m):
        G.add_edge(S, i, 1, 2 ** j)

for i in range(n):
    for j in range(n):
        G.add_edge(i, n + j, a[i][j], 0)

for i in range(n):
    for j in range(m):
        G.add_edge(n + i, T, 1, 2 ** j)

F = [[0] * n for _ in range(n)]
ans = []
for i in range(m):
    f = G.flow(S, T, n)
    if f[0] != n:
        print(-1)
        exit()
    F2 = G.edges()
    p = [0] * n
    for v in F2:
        st = v["from"]
        gl = v["to"]
        ff = v["flow"]
        if 0 <= st < n and n <= gl < 2 * n:
            gl -= n
            if F[st][gl] != ff:
                p[st] = gl + 1
                F[st][gl] = ff
    ans.append(p)

for v in ans:
    print(*v)

0