結果

問題 No.1771 A DELETEQ
ユーザー akuaakua
提出日時 2023-04-15 10:01:19
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
AC  
実行時間 961 ms / 3,500 ms
コード長 5,326 bytes
コンパイル時間 18,120 ms
コンパイル使用メモリ 253,744 KB
最終ジャッジ日時 2025-02-12 08:43:08
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 26 WA * 12
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <atcoder/all>
#include <iostream> // cout, endl, cin
#include <string> // string, to_string, stoi
#include <vector> // vector
#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound
#include <utility> // pair, make_pair
#include <tuple> // tuple, make_tuple
#include <cstdint> // int64_t, int*_t
#include <cstdio> // printf
#include <map> // map
#include <queue> // queue, priority_queue
#include <set> // set
#include <stack> // stack
#include <deque> // deque
#include <unordered_map> // unordered_map
#include <unordered_set> // unordered_set
#include <bitset> // bitset
#include <cctype> // isupper, islower, isdigit, toupper, tolower
#include <math.h>
#include <iomanip>
#include <functional>
using namespace std;
using namespace atcoder;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repi(i, a, b) for (int i = (int)(a); i < (int)(b); i++)
typedef long long ll;
typedef unsigned long long ull;
const ll inf=1e18;
using graph = vector<vector<int> > ;
using P= pair<ll,ll>;
using vi=vector<int>;
using vvi=vector<vi>;
using vll=vector<ll>;
using vvll=vector<vll>;
using vp=vector<P>;
using vvp=vector<vp>;
using vd=vector<double>;
using vvd =vector<vd>;
//string T="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
//string S="abcdefghijklmnopqrstuvwxyz";
//g++ main.cpp -std=c++17 -I .
//cout <<setprecision(20);
//cout << fixed << setprecision(10);
//cin.tie(0); ios::sync_with_stdio(false);
const double PI = acos(-1);
int vx[]={0,1,0,-1,-1,1,1,-1},vy[]={1,0,-1,0,1,1,-1,-1};
void putsYes(bool f){cout << (f?"Yes":"No") << endl;}
void putsYES(bool f){cout << (f?"YES":"NO") << endl;}
void putsFirst(bool f){cout << (f?"First":"Second") << endl;}
void debug(int test){cout << "TEST" << " " << test << endl;}
ll pow_pow(ll x,ll n,ll mod){
if(n==0) return 1;
x%=mod;
ll res=pow_pow(x*x%mod,n/2,mod);
if(n&1)res=res*x%mod;
return res;
}
ll gcd(ll x,ll y){
if(y==0)return x;
return gcd(y,x%y);
}
ll lcm(ll x,ll y){
return ll(x/gcd(x,y))*y;
}
template<class T> bool chmin(T& a, T b) {
if (a > b) {
a = b;
return true;
}
else return false;
}
template<class T> bool chmax(T& a, T b) {
if (a < b) {
a = b;
return true;
}
else return false;
}
// https://youtu.be/L8grWxBlIZ4?t=9858
// https://youtu.be/ERZuLAxZffQ?t=4807 : optimize
// https://youtu.be/8uowVvQ_-Mo?t=1329 : division
ll mod =998244353;
//ll mod =1e9+7;
struct mint {
ll x; // typedef long long ll;
mint(ll x=0):x((x%mod+mod)%mod){}
mint operator-() const { return mint(-x);}
mint& operator+=(const mint a) {
if ((x += a.x) >= mod) x -= mod;
return *this;
}
mint& operator-=(const mint a) {
if ((x += mod-a.x) >= mod) x -= mod;
return *this;
}
mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
mint operator+(const mint a) const { return mint(*this) += a;}
mint operator-(const mint a) const { return mint(*this) -= a;}
mint operator*(const mint a) const { return mint(*this) *= a;}
mint pow(ll t) const {
if (!t) return 1;
mint a = pow(t>>1);
a *= a;
if (t&1) a *= *this;
return a;
}
// for prime mod
mint inv() const { return pow(mod-2);}
mint& operator/=(const mint a) { return *this *= a.inv();}
mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
// combination mod prime
// https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619
struct combination {
vector<mint> fact, ifact;
combination(int n):fact(n+1),ifact(n+1) {
//assert(n < mod);
fact[0] = 1;
for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
ifact[n] = fact[n].inv();
for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
}
mint operator()(int n, int k) {
if (k < 0 || k > n) return 0;
if (n<0) return 0;
return fact[n]*ifact[k]*ifact[n-k];
} mint p(int n, int k) { return fact[n]*ifact[n-k]; } } c(2000000);
using vm=vector<mint> ;
using vvm=vector<vm> ;
struct edge{
int to; ll cost;
edge(int to,ll cost) : to(to),cost(cost){}
};
using ve=vector<edge>;
using vve=vector<ve>;
struct Compress{
vll a;
map<ll,ll> d,d2;
int cnt;
Compress() :cnt(0) {}
void add(ll x){a.push_back(x);}
void init(){
set<ll>s(a.begin(),a.end());
for(auto y:s)d[y]=cnt++;
for(auto&y:a)y=d[y];
for(auto u:d)d2[u.second]=u.first;
}
ll to(ll x){return d[x];} //
ll from(ll x){return d2[x];}//
int size(){return cnt;}
};
vll anss;
void solve(int test){
ll a,b;cin >> a >> b;
if(a>4000 || b>4000)return;
vvm dp(a+1,vm(b+1));
dp[a][b]=1;
for(int i=a; i>=0; i--){
for(int j=b; j>=0; j--){
mint now=dp[i][j];
if(!now.x)continue;
if(i-1>=0 && j-1>=0)dp[i-1][j-1]+=now*2;
if(i-1>=0)dp[i-1][j]+=now;
if(j-1>=0)dp[i][j-1]+=now;
}
}
mint ans=0;
rep(i,a+1)rep(j,b+1){
if(i==j)ans+=dp[i][j];
}
cout << ans << endl;
}
//g++ main.cpp -std=c++17 -I .
int main(){cin.tie(0);ios::sync_with_stdio(false);
int t=1;//cin >> t;
rep(test,t)solve(test);
for(auto u:anss)cout << u << endl;
}
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