結果
問題 | No.2263 Perms |
ユーザー | woodywoody |
提出日時 | 2023-04-18 01:34:25 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 8 ms / 2,000 ms |
コード長 | 5,085 bytes |
コンパイル時間 | 3,911 ms |
コンパイル使用メモリ | 245,688 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-10-13 00:25:56 |
合計ジャッジ時間 | 5,737 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,820 KB |
testcase_02 | AC | 2 ms
6,820 KB |
testcase_03 | AC | 2 ms
6,816 KB |
testcase_04 | AC | 2 ms
6,816 KB |
testcase_05 | AC | 2 ms
6,816 KB |
testcase_06 | AC | 6 ms
6,816 KB |
testcase_07 | AC | 5 ms
6,820 KB |
testcase_08 | AC | 3 ms
6,816 KB |
testcase_09 | AC | 8 ms
6,820 KB |
testcase_10 | AC | 2 ms
6,816 KB |
testcase_11 | AC | 5 ms
6,816 KB |
testcase_12 | AC | 5 ms
6,820 KB |
testcase_13 | AC | 7 ms
6,816 KB |
testcase_14 | AC | 6 ms
6,820 KB |
testcase_15 | AC | 2 ms
6,820 KB |
testcase_16 | AC | 3 ms
6,816 KB |
testcase_17 | AC | 2 ms
6,816 KB |
testcase_18 | AC | 2 ms
6,816 KB |
testcase_19 | AC | 3 ms
6,816 KB |
testcase_20 | AC | 6 ms
6,820 KB |
testcase_21 | AC | 6 ms
6,816 KB |
testcase_22 | AC | 5 ms
6,820 KB |
testcase_23 | AC | 3 ms
6,816 KB |
testcase_24 | AC | 3 ms
6,820 KB |
testcase_25 | AC | 5 ms
6,820 KB |
testcase_26 | AC | 6 ms
6,820 KB |
testcase_27 | AC | 3 ms
6,816 KB |
testcase_28 | AC | 2 ms
6,816 KB |
testcase_29 | AC | 3 ms
6,820 KB |
testcase_30 | AC | 2 ms
6,820 KB |
testcase_31 | AC | 2 ms
6,816 KB |
testcase_32 | AC | 2 ms
6,816 KB |
testcase_33 | AC | 2 ms
6,816 KB |
testcase_34 | AC | 2 ms
6,816 KB |
testcase_35 | AC | 2 ms
6,820 KB |
testcase_36 | AC | 2 ms
6,820 KB |
testcase_37 | AC | 2 ms
6,816 KB |
testcase_38 | AC | 6 ms
6,816 KB |
testcase_39 | AC | 2 ms
6,820 KB |
testcase_40 | AC | 2 ms
6,816 KB |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,b) for(int i=0;i<b;i++) #define rrep(i,b) for(int i=b-1;i>=0;i--) #define rep1(i,b) for(int i=1;i<b;i++) #define repx(i,x,b) for(int i=x;i<b;i++) #define rrepx(i,x,b) for(int i=b-1;i>=x;i--) #define fore(i,a) for(auto i:a) #define fore1(i,a) for(auto &i:a) #define rng(x) (x).begin(), (x).end() #define rrng(x) (x).rbegin(), (x).rend() #define sz(x) ((int)(x).size()) #define pb push_back #define fi first #define se second #define pcnt __builtin_popcountll using namespace std; using namespace atcoder; using ll = long long; using ld = long double; template<typename T> using mpq = priority_queue<T, vector<T>, greater<T>>; template<typename T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; } template<typename T> bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; } template<typename T> ll sumv(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}} #define dame { cout << "No" << endl; return;} #define dame1 { cout << -1 << endl; return;} #define cout2(x,y) cout << x << " " << y << endl; #define coutp(p) cout << p.fi << " " << p.se << endl; #define out cout << ans << endl; #define outd cout << fixed << setprecision(20) << ans << endl; #define outm cout << ans.val() << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define outdv fore(yans , ans) cout << yans.val() << "\n"; #define coutv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define coutv2(v) fore(vy , v) cout << vy << "\n"; #define coutvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define coutvm2(v) fore(vy , v) cout << vy.val() << "\n"; using pll = pair<ll,ll>;using pil = pair<int,ll>;using pli = pair<ll,int>;using pii = pair<int,int>;using pdd = pair<ld,ld>; using tp = tuple<int ,int ,int>; using vi = vector<int>;using vd = vector<ld>;using vl = vector<ll>;using vs = vector<string>;using vb = vector<bool>; using vpii = vector<pii>;using vpli = vector<pli>;using vpll = vector<pll>;using vpil = vector<pil>; using vvi = vector<vector<int>>;using vvl = vector<vector<ll>>;using vvs = vector<vector<string>>;using vvb = vector<vector<bool>>; using vvpii = vector<vector<pii>>;using vvpli = vector<vector<pli>>;using vvpll = vector<vpll>;using vvpil = vector<vpil>; using mint = modint998244353; //using mint = modint1000000007; //using mint = dynamic_modint<0>; using vm = vector<mint>; using vvm = vector<vector<mint>>; vector<int> dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} #define yes {cout <<"Yes"<<endl;} #define yesr { cout <<"Yes"<<endl; return;} #define no {cout <<"No"<<endl;} #define nor { cout <<"No"<<endl; return;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; #ifdef MY_LOCAL_DEBUG #define show(x) cerr<<#x<<" = "<<x<<endl #define showp(p) cerr<<#p<<" = "<<p.fi<<" : "<<p.se<<endl #define show2(x,y) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<endl #define show3(x,y,z) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<endl #define show4(x,y,z,x2) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<" : "<<#x2<<" = "<<x2<<endl #define test(x) cout << "test" << x << endl #define showv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define showv2(v) fore(vy , v) cout << vy << "\n"; #define showvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define showvm2(v) fore(vy , v) cout << vy.val() << "\n"; #else #define show(x) #define showp(p) #define show2(x,y) #define show3(x,y,z) #define show4(x,y,z,x2) #define test(x) #define showv(v) #define showv2(v) #define showvm(v) #define showvm2(v) #endif void solve(){ int n,m; cin>>n>>m; vvi a(n,vi(n)); rep(i,n) rep(j,n) cin>>a[i][j]; bool ok = true; vvi ans; using edge = mf_graph<int>::edge; rep(i,m){ vi cnt1(n),cnt2(n); rep(j,n) cnt1[j] = sumv(a[j]); rep(j,n) rep(k,n) cnt2[k] += a[j][k]; rep(j,n){ if (cnt1[j]!=m-i) ok = false; if (cnt2[j]!=m-i) ok = false; } if (!ok) break; mf_graph<int> mg(2*n+2); int st = 2*n; int go = 2*n+1; rep(j,n) mg.add_edge(st,j,1); rep(j,n) mg.add_edge(j+n,go,1); rep(j,n) rep(k,n) if (a[j][k]) mg.add_edge(j,k+n,1); int f = mg.flow(st,go); assert(f==n); vi state(n,-1); vector<edge> v = mg.edges(); fore(y , v){ if (y.from>=n) continue; if (y.to<n || y.to>=2*n) continue; if (y.flow==0) continue; assert(state[y.from]==-1); a[y.from][y.to-n]--; state[y.from] = y.to-n+1; } ans.pb(state); } if (!ok) dame1; fore(y , ans) coutv(y); return; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int t = 1; //cin>>t; rep(i,t){ solve(); } return 0; }