結果
問題 | No.209 Longest Mountain Subsequence |
ユーザー |
|
提出日時 | 2023-04-22 09:00:47 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 239 ms / 2,000 ms |
コード長 | 5,783 bytes |
コンパイル時間 | 19,284 ms |
コンパイル使用メモリ | 249,920 KB |
最終ジャッジ日時 | 2025-02-12 12:58:28 |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
other | AC * 6 |
ソースコード
#pragma GCC target("avx2")#pragma GCC optimize("O3")#pragma GCC optimize("unroll-loops")#include <atcoder/all>#include <iostream> // cout, endl, cin#include <string> // string, to_string, stoi#include <vector> // vector#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound#include <utility> // pair, make_pair#include <tuple> // tuple, make_tuple#include <cstdint> // int64_t, int*_t#include <cstdio> // printf#include <map> // map#include <queue> // queue, priority_queue#include <set> // set#include <stack> // stack#include <deque> // deque #include <unordered_map> // unordered_map #include <unordered_set> // unordered_set #include <bitset> // bitset#include <cctype> // isupper, islower, isdigit, toupper, tolower#include <math.h>#include <iomanip>#include <functional>using namespace std;using namespace atcoder;#define rep(i, n) for (int i = 0; i < (int)(n); i++)#define repi(i, a, b) for (int i = (int)(a); i < (int)(b); i++)typedef long long ll;typedef unsigned long long ull;const ll inf=1e18;using graph = vector<vector<int> > ;using P= pair<ll,ll>;using vi=vector<int>;using vvi=vector<vi>;using vll=vector<ll>;using vvll=vector<vll>;using vp=vector<P>;using vvp=vector<vp>;using vd=vector<double>;using vvd =vector<vd>;//string T="ABCDEFGHIJKLMNOPQRSTUVWXYZ";//string S="abcdefghijklmnopqrstuvwxyz";//g++ main.cpp -std=c++17 -I .//cout <<setprecision(20);//cout << fixed << setprecision(10);//cin.tie(0); ios::sync_with_stdio(false);const double PI = acos(-1);int vx[]={0,1,0,-1,-1,1,1,-1},vy[]={1,0,-1,0,1,1,-1,-1};void putsYes(bool f){cout << (f?"Yes":"No") << endl;}void putsYES(bool f){cout << (f?"YES":"NO") << endl;}void putsFirst(bool f){cout << (f?"First":"Second") << endl;}void debug(int test){cout << "TEST" << " " << test << endl;}ll pow_pow(ll x,ll n,ll mod){if(n==0) return 1;x%=mod;ll res=pow_pow(x*x%mod,n/2,mod);if(n&1)res=res*x%mod;return res;}ll gcd(ll x,ll y){if(y==0)return x;return gcd(y,x%y);}ll lcm(ll x,ll y){return ll(x/gcd(x,y))*y;}template<class T> bool chmin(T& a, T b) {if (a > b) {a = b;return true;}else return false;}template<class T> bool chmax(T& a, T b) {if (a < b) {a = b;return true;}else return false;}// https://youtu.be/L8grWxBlIZ4?t=9858// https://youtu.be/ERZuLAxZffQ?t=4807 : optimize// https://youtu.be/8uowVvQ_-Mo?t=1329 : divisionll mod =998244353;//ll mod =1e9+7;struct mint {ll x; // typedef long long ll;mint(ll x=0):x((x%mod+mod)%mod){}mint operator-() const { return mint(-x);}mint& operator+=(const mint a) {if ((x += a.x) >= mod) x -= mod;return *this;}mint& operator-=(const mint a) {if ((x += mod-a.x) >= mod) x -= mod;return *this;}mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}mint operator+(const mint a) const { return mint(*this) += a;}mint operator-(const mint a) const { return mint(*this) -= a;}mint operator*(const mint a) const { return mint(*this) *= a;}mint pow(ll t) const {if (!t) return 1;mint a = pow(t>>1);a *= a;if (t&1) a *= *this;return a;}// for prime modmint inv() const { return pow(mod-2);}mint& operator/=(const mint a) { return *this *= a.inv();}mint operator/(const mint a) const { return mint(*this) /= a;}};istream& operator>>(istream& is, const mint& a) { return is >> a.x;}ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}// combination mod prime// https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619struct combination {vector<mint> fact, ifact;combination(int n):fact(n+1),ifact(n+1) {//assert(n < mod);fact[0] = 1;for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;ifact[n] = fact[n].inv();for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;}mint operator()(int n, int k) {if (k < 0 || k > n) return 0;if (n<0) return 0;return fact[n]*ifact[k]*ifact[n-k];} mint p(int n, int k) { return fact[n]*ifact[n-k]; } } c(2000000);using vm=vector<mint> ;using vvm=vector<vm> ;struct edge{int to; ll cost;edge(int to,ll cost) : to(to),cost(cost){}};using ve=vector<edge>;using vve=vector<ve>;struct Compress{vll a;map<ll,ll> d,d2;int cnt;Compress() :cnt(0) {}void add(ll x){a.push_back(x);}void init(){set<ll>s(a.begin(),a.end());for(auto y:s)d[y]=cnt++;for(auto&y:a)y=d[y];for(auto u:d)d2[u.second]=u.first;}ll to(ll x){return d[x];} //変換先ll from(ll x){return d2[x];}//逆引きint size(){return cnt;}};vll anss;ll dp[105][105];ll ep[105][105];void solve(int test){int n; cin >> n;vi a(n+1);for(int i=1; i<=n; i++)cin >> a[i];repi(i,1,n+1)repi(j,1,n+1)dp[i][j]=-inf;repi(i,1,n+1)repi(j,1,n+1)ep[i][j]=-inf;// repi(i,1,n+1)repi(j,i+1,n+1)if(a[i]<a[j])dp[i][j]=2;repi(i,1,n+1)dp[i][i]=1;repi(i,1,n+1)ep[i][i]=1;for(int i=1; i<n; i++)for(int j=i; j>=1; j--){ll now=dp[i][j];if(now==-inf)continue;repi(next,i+1,n+1){if(a[next]-a[i]>a[i]-a[j]){chmax(dp[next][i],now+1);}}}for(int i=n; i>1; i--)for(int j=i; j<=n; j++){ll now=ep[i][j];if(now==-inf)continue;for(int next=i-1; next>=1; next--){if(a[next]-a[i]>a[i]-a[j]){chmax(ep[next][i],now+1);}}}ll ans=0;repi(i,1,n+1){repi(j,1,n+1)repi(k,1,n+1)chmax(ans,dp[i][j]+ep[i][k]-1);}anss.push_back(ans);}//g++ main.cpp -std=c++17 -I .int main(){cin.tie(0);ios::sync_with_stdio(false);int t=1;cin >> t;rep(test,t)solve(test);for(auto u:anss)cout << u << endl;}