結果
| 問題 |
No.1661 Sum is Prime (Hard Version)
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-04-22 20:45:07 |
| 言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 193 ms / 3,000 ms |
| コード長 | 6,901 bytes |
| コンパイル時間 | 19,533 ms |
| コンパイル使用メモリ | 250,300 KB |
| 最終ジャッジ日時 | 2025-02-12 13:13:07 |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 22 |
ソースコード
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <atcoder/all>
#include <iostream> // cout, endl, cin
#include <string> // string, to_string, stoi
#include <vector> // vector
#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound
#include <utility> // pair, make_pair
#include <tuple> // tuple, make_tuple
#include <cstdint> // int64_t, int*_t
#include <cstdio> // printf
#include <map> // map
#include <queue> // queue, priority_queue
#include <set> // set
#include <stack> // stack
#include <deque> // deque #include <unordered_map> // unordered_map #include <unordered_set> // unordered_set #include <bitset> // bitset
#include <cctype> // isupper, islower, isdigit, toupper, tolower
#include <math.h>
#include <iomanip>
#include <functional>
using namespace std;
using namespace atcoder;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repi(i, a, b) for (int i = (int)(a); i < (int)(b); i++)
typedef long long ll;
typedef unsigned long long ull;
const ll inf=1e18;
using graph = vector<vector<int> > ;
using P= pair<ll,ll>;
using vi=vector<int>;
using vvi=vector<vi>;
using vll=vector<ll>;
using vvll=vector<vll>;
using vp=vector<P>;
using vvp=vector<vp>;
using vd=vector<double>;
using vvd =vector<vd>;
//string T="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
//string S="abcdefghijklmnopqrstuvwxyz";
//g++ main.cpp -std=c++17 -I .
//cout <<setprecision(20);
//cout << fixed << setprecision(10);
//cin.tie(0); ios::sync_with_stdio(false);
const double PI = acos(-1);
int vx[]={0,1,0,-1,-1,1,1,-1},vy[]={1,0,-1,0,1,1,-1,-1};
void putsYes(bool f){cout << (f?"Yes":"No") << endl;}
void putsYES(bool f){cout << (f?"YES":"NO") << endl;}
void putsFirst(bool f){cout << (f?"First":"Second") << endl;}
void debug(int test){cout << "TEST" << " " << test << endl;}
ll pow_pow(ll x,ll n,ll mod){
if(n==0) return 1;
x%=mod;
ll res=pow_pow(x*x%mod,n/2,mod);
if(n&1)res=res*x%mod;
return res;
}
ll gcd(ll x,ll y){
if(y==0)return x;
return gcd(y,x%y);
}
ll lcm(ll x,ll y){
return ll(x/gcd(x,y))*y;
}
template<class T> bool chmin(T& a, T b) {
if (a > b) {
a = b;
return true;
}
else return false;
}
template<class T> bool chmax(T& a, T b) {
if (a < b) {
a = b;
return true;
}
else return false;
}
// https://youtu.be/L8grWxBlIZ4?t=9858
// https://youtu.be/ERZuLAxZffQ?t=4807 : optimize
// https://youtu.be/8uowVvQ_-Mo?t=1329 : division
ll mod =998244353;
//ll mod =1e9+7;
struct mint {
ll x; // typedef long long ll;
mint(ll x=0):x((x%mod+mod)%mod){}
mint operator-() const { return mint(-x);}
mint& operator+=(const mint a) {
if ((x += a.x) >= mod) x -= mod;
return *this;
}
mint& operator-=(const mint a) {
if ((x += mod-a.x) >= mod) x -= mod;
return *this;
}
mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
mint operator+(const mint a) const { return mint(*this) += a;}
mint operator-(const mint a) const { return mint(*this) -= a;}
mint operator*(const mint a) const { return mint(*this) *= a;}
mint pow(ll t) const {
if (!t) return 1;
mint a = pow(t>>1);
a *= a;
if (t&1) a *= *this;
return a;
}
// for prime mod
mint inv() const { return pow(mod-2);}
mint& operator/=(const mint a) { return *this *= a.inv();}
mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
// combination mod prime
// https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619
struct combination {
vector<mint> fact, ifact;
combination(int n):fact(n+1),ifact(n+1) {
//assert(n < mod);
fact[0] = 1;
for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
ifact[n] = fact[n].inv();
for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
}
mint operator()(int n, int k) {
if (k < 0 || k > n) return 0;
if (n<0) return 0;
return fact[n]*ifact[k]*ifact[n-k];
} mint p(int n, int k) { return fact[n]*ifact[n-k]; } } c(2000000);
using vm=vector<mint> ;
using vvm=vector<vm> ;
struct edge{
int to; ll cost;
edge(int to,ll cost) : to(to),cost(cost){}
};
using ve=vector<edge>;
using vve=vector<ve>;
struct Compress{
vll a;
map<ll,ll> d,d2;
int cnt;
Compress() :cnt(0) {}
void add(ll x){a.push_back(x);}
void init(){
set<ll>s(a.begin(),a.end());
for(auto y:s)d[y]=cnt++;
for(auto&y:a)y=d[y];
for(auto u:d)d2[u.second]=u.first;
}
ll to(ll x){return d[x];} //変換先
ll from(ll x){return d2[x];}//逆引き
int size(){return cnt;}
};
int isqrt(ll n) {
return sqrtl(n);
}
ll prime_pi(const ll N) {
if (N <= 1) return 0;
if (N == 2) return 1;
const int v = isqrt(N);
int s = (v + 1) / 2;
vector<int> smalls(s);
for (int i = 1; i < s; i++) smalls[i] = i;
vector<int> roughs(s);
for (int i = 0; i < s; i++) roughs[i] = 2 * i + 1;
vector<ll> larges(s);
for (int i = 0; i < s; i++) larges[i] = (N / (2 * i + 1) - 1) / 2;
vector<bool> skip(v + 1);
const auto divide = [](ll n, ll d) -> int { return (double)n / d;};
const auto half = [](int n) -> int { return (n - 1) >> 1;};
int pc = 0;
for (int p = 3; p <= v; p += 2) if (!skip[p]) {
int q = p * p;
if ((ll)q * q > N) break;
skip[p] = true;
for (int i = q; i <= v; i += 2 * p) skip[i] = true;
int ns = 0;
for (int k = 0; k < s; k++) {
int i = roughs[k];
if (skip[i]) continue;
ll d = (ll)i * p;
larges[ns] = larges[k] - (d <= v ? larges[smalls[d >> 1] - pc] : smalls[half(divide(N, d))]) + pc;
roughs[ns++] = i;
}
s = ns;
for (int i = half(v), j = ((v / p) - 1) | 1; j >= p; j -= 2) {
int c = smalls[j >> 1] - pc;
for (int e = (j * p) >> 1; i >= e; i--) smalls[i] -= c;
}
pc++;
}
larges[0] += (ll)(s + 2 * (pc - 1)) * (s - 1) / 2;
for (int k = 1; k < s; k++) larges[0] -= larges[k];
for (int l = 1; l < s; l++) {
ll q = roughs[l];
ll M = N / q;
int e = smalls[half(M / q)] - pc;
if (e < l + 1) break;
ll t = 0;
for (int k = l + 1; k <= e; k++)
t += smalls[half(divide(M, roughs[k]))];
larges[0] += t - (ll)(e - l) * (pc + l - 1);
}
return larges[0] + 1;
}
vll anss;
void solve(int test){
ll l,r; cin >> l >> r;
ll ans=0;
if(r!=l){
ans+=prime_pi(2*r-1);
if(2*l+1-1>=1)ans-=prime_pi(2*l+1-1);
}
ans+=prime_pi(r);
if(l-1>=1)ans-=prime_pi(l-1);
cout << ans << endl;
}
//g++ main.cpp -std=c++17 -I .
int main(){cin.tie(0);ios::sync_with_stdio(false);
int t=1;//cin >> t;
rep(test,t)solve(test);
for(auto u:anss)cout << u << endl;
}