結果

問題 No.1768 The frog in the well knows the great ocean.
ユーザー akuaakua
提出日時 2023-04-24 09:04:35
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 777 ms / 3,000 ms
コード長 6,030 bytes
コンパイル時間 6,230 ms
コンパイル使用メモリ 235,948 KB
実行使用メモリ 75,284 KB
最終ジャッジ日時 2024-11-15 04:25:57
合計ジャッジ時間 21,289 ms
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 156 ms
34,620 KB
testcase_01 AC 165 ms
34,780 KB
testcase_02 AC 165 ms
34,748 KB
testcase_03 AC 165 ms
34,676 KB
testcase_04 AC 165 ms
34,736 KB
testcase_05 AC 164 ms
34,728 KB
testcase_06 AC 552 ms
45,860 KB
testcase_07 AC 610 ms
52,740 KB
testcase_08 AC 507 ms
50,368 KB
testcase_09 AC 509 ms
45,576 KB
testcase_10 AC 556 ms
53,916 KB
testcase_11 AC 648 ms
54,884 KB
testcase_12 AC 647 ms
54,792 KB
testcase_13 AC 648 ms
54,896 KB
testcase_14 AC 651 ms
55,012 KB
testcase_15 AC 660 ms
54,864 KB
testcase_16 AC 760 ms
74,336 KB
testcase_17 AC 736 ms
74,224 KB
testcase_18 AC 724 ms
73,476 KB
testcase_19 AC 777 ms
75,284 KB
testcase_20 AC 761 ms
74,124 KB
testcase_21 AC 156 ms
34,496 KB
testcase_22 AC 157 ms
34,544 KB
testcase_23 AC 158 ms
34,580 KB
testcase_24 AC 304 ms
35,168 KB
testcase_25 AC 486 ms
69,660 KB
testcase_26 AC 481 ms
69,660 KB
testcase_27 AC 156 ms
34,512 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <atcoder/all>
#include <iostream> // cout, endl, cin
#include <string> // string, to_string, stoi
#include <vector> // vector
#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound
#include <utility> // pair, make_pair
#include <tuple> // tuple, make_tuple
#include <cstdint> // int64_t, int*_t
#include <cstdio> // printf
#include <map> // map
#include <queue> // queue, priority_queue
#include <set> // set
#include <stack> // stack
#include <deque> // deque #include <unordered_map> // unordered_map #include <unordered_set> // unordered_set #include <bitset> // bitset
#include <cctype> // isupper, islower, isdigit, toupper, tolower
#include <math.h>
#include <iomanip>
#include <functional>
using namespace std;  
using namespace atcoder;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repi(i, a, b) for (int i = (int)(a); i < (int)(b); i++)
typedef long long ll;
typedef unsigned long long ull;
const ll inf=1e18;  
using graph = vector<vector<int> > ;
using P= pair<ll,ll>;  
using vi=vector<int>;
using vvi=vector<vi>;
using vll=vector<ll>; 
using vvll=vector<vll>;
using vp=vector<P>;
using vvp=vector<vp>;
using vd=vector<double>;
using vvd =vector<vd>;
//string T="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
//string S="abcdefghijklmnopqrstuvwxyz";
//g++ main.cpp -std=c++17 -I .  
//cout <<setprecision(20);
//cout << fixed << setprecision(10);
//cin.tie(0); ios::sync_with_stdio(false);
const double PI = acos(-1);
int vx[]={0,1,0,-1,-1,1,1,-1},vy[]={1,0,-1,0,1,1,-1,-1};
void putsYes(bool f){cout << (f?"Yes":"No") << endl;}
void putsYES(bool f){cout << (f?"YES":"NO") << endl;}
void putsFirst(bool f){cout << (f?"First":"Second") << endl;}
void debug(int test){cout << "TEST" << " " << test << endl;}
ll pow_pow(ll x,ll n,ll mod){
    if(n==0) return 1; 
    x%=mod;
    ll res=pow_pow(x*x%mod,n/2,mod);
    if(n&1)res=res*x%mod;
    return res;
}
ll gcd(ll x,ll y){
    if(y==0)return x;
    return gcd(y,x%y);
}
 
ll lcm(ll x,ll y){
    return ll(x/gcd(x,y))*y;
}
template<class T> bool chmin(T& a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    else return false;
}
template<class T> bool chmax(T& a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    else return false;
}
// https://youtu.be/L8grWxBlIZ4?t=9858
// https://youtu.be/ERZuLAxZffQ?t=4807 : optimize
// https://youtu.be/8uowVvQ_-Mo?t=1329 : division
//ll mod =998244353;
ll mod =1e9+7;
struct mint {
  ll x; // typedef long long ll;
  mint(ll x=0):x((x%mod+mod)%mod){}
  mint operator-() const { return mint(-x);}
  mint& operator+=(const mint a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += mod-a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
  mint operator+(const mint a) const { return mint(*this) += a;}
  mint operator-(const mint a) const { return mint(*this) -= a;}
  mint operator*(const mint a) const { return mint(*this) *= a;}
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if (t&1) a *= *this;
    return a;
  }
 
  // for prime mod
  mint inv() const { return pow(mod-2);}
  mint& operator/=(const mint a) { return *this *= a.inv();}
  mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
// combination mod prime
// https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619
struct combination {
  vector<mint> fact, ifact;
  combination(int n):fact(n+1),ifact(n+1) {
    //assert(n < mod);
    fact[0] = 1;
    for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
    ifact[n] = fact[n].inv();
    for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
  }
  mint operator()(int n, int k) {
    if (k < 0 || k > n) return 0;
    if (n<0) return 0;
    return fact[n]*ifact[k]*ifact[n-k];
  } mint p(int n, int k) { return fact[n]*ifact[n-k]; } } c(2000000); 
using vm=vector<mint> ;
using vvm=vector<vm> ;
struct edge{
  int to; ll cost;
  edge(int to,ll cost) : to(to),cost(cost){}
};
using ve=vector<edge>;
using vve=vector<ve>;
struct Compress{
   vll a;
   map<ll,ll> d,d2;
   int cnt;
   Compress() :cnt(0) {}
   void add(ll x){a.push_back(x);}
   void init(){
     set<ll>s(a.begin(),a.end());
     for(auto y:s)d[y]=cnt++;
     for(auto&y:a)y=d[y];
     for(auto u:d)d2[u.second]=u.first;
   }
   ll to(ll x){return d[x];} //変換先
   ll from(ll x){return d2[x];}//逆引き
   int size(){return cnt;}
};
using S=int;
S op(S a,S b){return max(a,b);}
S e(){return -100000000;}
vll anss;
void solve(int test){
  int n; cin >> n;
  vi a(n),b(n);
  rep(i,n)cin >> a[i];
  rep(i,n)cin >> b[i];
  Compress comp;
  rep(i,n)comp.add(a[i]);
  rep(i,n)comp.add(b[i]);
  comp.init();
  rep(i,n)a[i]=comp.to(a[i]);
  rep(i,n)b[i]=comp.to(b[i]);
  int m=comp.size();
  vvi g(m);
  rep(i,n)g[a[i]].push_back(i);
  segtree<S,op,e> seg(a);
  vi b2(n);rep(i,n)b2[i]=b[i]*-1;
  segtree<S,op,e> seg2(b2);
  vp p;
  rep(i,n)p.push_back(P(b[i],i));
  sort(p.begin(),p.end());
  int ans=1;
  for(auto u:p){
    int i=u.second;
    if(g[b[i]].size()==0){
      ans=0;
    }
    else {
      int index=lower_bound(g[b[i]].begin(),g[b[i]].end(),i)-g[b[i]].begin();
      int ok=0;
      if(b[i]==a[i])ok=1;
      if(index!=g[b[i]].size()){
        if(seg.prod(i,g[b[i]][index]+1)==b[i]){
          if(seg2.prod(i+1,g[b[i]][index]+1)<=-b[i])ok=1;
        }
      }
      index--;
      if(index>=0){
        if(seg.prod(g[b[i]][index],i+1)==b[i]){
           if(seg2.prod(g[b[i]][index],i)<=-b[i])ok=1;
        }
      }
      if(!ok)ans=0;
    }
 //   debug(ans);
  }
  anss.push_back(ans);
}
//g++ main.cpp -std=c++17 -I .
int main(){cin.tie(0);ios::sync_with_stdio(false);
  int t=1;cin >> t;
  rep(test,t)solve(test);
  for(auto u:anss)putsYes(u);
}
0