結果
問題 | No.2295 Union Path Query (Medium) |
ユーザー | 沙耶花 |
提出日時 | 2023-05-05 22:53:18 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 3,260 ms / 4,000 ms |
コード長 | 4,291 bytes |
コンパイル時間 | 5,100 ms |
コンパイル使用メモリ | 274,712 KB |
実行使用メモリ | 111,864 KB |
最終ジャッジ日時 | 2024-11-23 00:45:55 |
合計ジャッジ時間 | 108,214 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 3 ms
6,816 KB |
testcase_02 | AC | 2 ms
6,824 KB |
testcase_03 | AC | 3,134 ms
34,536 KB |
testcase_04 | AC | 2,798 ms
59,408 KB |
testcase_05 | AC | 1,861 ms
59,512 KB |
testcase_06 | AC | 1,193 ms
109,752 KB |
testcase_07 | AC | 2,603 ms
34,532 KB |
testcase_08 | AC | 1,270 ms
109,868 KB |
testcase_09 | AC | 1,303 ms
109,608 KB |
testcase_10 | AC | 1,404 ms
109,736 KB |
testcase_11 | AC | 2,488 ms
110,176 KB |
testcase_12 | AC | 3,260 ms
111,864 KB |
testcase_13 | AC | 2,316 ms
35,244 KB |
testcase_14 | AC | 1,076 ms
17,180 KB |
testcase_15 | AC | 471 ms
109,736 KB |
testcase_16 | AC | 475 ms
109,872 KB |
testcase_17 | AC | 860 ms
61,484 KB |
testcase_18 | AC | 2,034 ms
59,944 KB |
testcase_19 | AC | 2,384 ms
59,948 KB |
testcase_20 | AC | 1,420 ms
59,692 KB |
testcase_21 | AC | 1,430 ms
59,948 KB |
testcase_22 | AC | 2,223 ms
59,948 KB |
testcase_23 | AC | 2,124 ms
109,680 KB |
testcase_24 | AC | 2,130 ms
109,736 KB |
testcase_25 | AC | 724 ms
109,744 KB |
testcase_26 | AC | 1,929 ms
109,872 KB |
testcase_27 | AC | 1,829 ms
109,740 KB |
testcase_28 | AC | 1,828 ms
109,736 KB |
testcase_29 | AC | 1,750 ms
109,612 KB |
testcase_30 | AC | 1,677 ms
109,868 KB |
testcase_31 | AC | 1,664 ms
109,668 KB |
testcase_32 | AC | 1,648 ms
109,864 KB |
testcase_33 | AC | 1,709 ms
109,740 KB |
testcase_34 | AC | 1,631 ms
109,740 KB |
testcase_35 | AC | 1,597 ms
109,864 KB |
testcase_36 | AC | 1,616 ms
109,740 KB |
testcase_37 | AC | 1,654 ms
109,740 KB |
testcase_38 | AC | 1,676 ms
109,740 KB |
testcase_39 | AC | 1,638 ms
109,736 KB |
testcase_40 | AC | 1,564 ms
109,872 KB |
testcase_41 | AC | 1,586 ms
109,680 KB |
testcase_42 | AC | 1,573 ms
109,872 KB |
testcase_43 | AC | 1,572 ms
109,744 KB |
testcase_44 | AC | 2,706 ms
111,380 KB |
testcase_45 | AC | 2,130 ms
109,740 KB |
testcase_46 | AC | 1,604 ms
109,744 KB |
testcase_47 | AC | 1,711 ms
109,740 KB |
testcase_48 | AC | 2,636 ms
109,872 KB |
testcase_49 | AC | 2,693 ms
109,868 KB |
testcase_50 | AC | 1,289 ms
109,740 KB |
testcase_51 | AC | 1,580 ms
109,736 KB |
testcase_52 | AC | 1,660 ms
109,740 KB |
testcase_53 | AC | 1,548 ms
109,740 KB |
testcase_54 | AC | 1,661 ms
109,668 KB |
testcase_55 | AC | 1,649 ms
110,168 KB |
ソースコード
#include <stdio.h> #include <bits/stdc++.h> #include <atcoder/all> using namespace atcoder; using mint = modint998244353; using namespace std; #define rep(i,n) for (int i = 0; i < (n); ++i) #define Inf32 1000000001 #define Inf64 4000000000000000001 template <typename T> struct perArray{ struct node{ T value; int l=-1,r=-1; }; int sz; vector<node> nodes; vector<int> roots; void build(vector<T> v,int now = -1){ if(now==-1){ sz = v.size(); nodes.push_back(node()); now = 0; roots.push_back(0); } if(v.size()==1){ nodes[now].value = v[0]; return; } vector<T> l,r; rep(i,v.size()){ if(i<v.size()/2){ l.push_back(v[i]); } else{ r.push_back(v[i]); } } nodes[now].l = nodes.size(); nodes.push_back(node()); build(l,nodes[now].l); nodes[now].r = nodes.size(); nodes.push_back(node()); build(r,nodes[now].r); } int set(int p, int ind, T x, int now = -1, int length = -1){ int ret = roots.size(); if(now==-1){ roots.push_back(nodes.size()); now = nodes.size(); nodes.push_back(nodes[roots[p]]); length = sz; } if(length==1){ nodes[now].value = x; } else{ if(ind < (length>>1)){ int temp = nodes[now].l; nodes[now].l = nodes.size(); nodes.push_back(nodes[temp]); set(p,ind,x,nodes.size()-1,(length>>1)); } else{ int temp = nodes[now].r; nodes[now].r = nodes.size(); nodes.push_back(nodes[temp]); set(p,ind - (length>>1),x,nodes.size()-1,(length+1)>>1); } } return ret; } T get(int p,int ind,int now = -1,int length = -1){ if(now==-1){ now = roots[p]; length = sz; } if(length==1)return nodes[now].value; if(ind<(length>>1)){ return get(p,ind,nodes[now].l,length>>1); } else{ return get(p,ind - (length>>1),nodes[now].r,(length+1)>>1); } } int size(){ return sz; } }; struct perDsu{ perArray<int> A; vector<int> roots; perDsu(int n){ vector<int> t(n,-1); A.build(t); roots.push_back(0); } int merge(int p,int a,int b){ int ret = roots.size(); int La = leader(p,a); int Lb = leader(p,b); if(La==Lb)return p; if(size(p,La)<size(p,Lb))swap(La,Lb); int temp = A.set(roots[p],La,-(size(p,La)+size(p,Lb))); roots.push_back(A.set(temp,Lb,La)); return ret; } bool same(int p,int a,int b){ return (leader(p,a)==leader(p,b)); } int size(int p,int a){ int temp = A.get(roots[p],a); if(temp<0)return -temp; return size(p,temp); } int leader(int p,int a){ int temp = A.get(roots[p],a); if(temp<0)return a; return leader(p,temp); } vector<vector<int>> groups(int p){ vector<vector<int>> temp(A.size(),vector<int>()); rep(i,A.size()){ temp[leader(p,i)].push_back(i); } vector<vector<int>> ret; rep(i,temp.size()){ if(temp[i].size()>0)ret.push_back(temp[i]); } return ret; } }; int main(){ int n,x0,q; cin>>n>>x0>>q; perDsu D(n); vector<int> t(q+1),a(q+1),b(q+1),p(q+1); int x= x0; vector<int> memo(q+1); for(int i=1;i<=q;i++){ scanf("%d",&t[i]); p[i] = p[i-1]; if(t[i]==1){ scanf("%d %d",&a[i],&b[i]); //cin>>a[i]>>b[i]; p[i] = D.merge(p[i],a[i],x); } if(t[i]==2){ scanf("%d %d",&a[i],&b[i]); if(a[i]==b[i])continue; if(D.same(p[i],a[i],b[i])){ int ok = 0,ng = i; while(ng-ok>1){ int mid = (ok+ng)/2; if(D.same(p[mid],a[i],b[i]))ng = mid; else ok = mid; } memo[i] = b[ok+1]; x += b[ok+1]; x %= n; } } if(t[i]==3){ scanf("%d",&a[i]); } if(t[i]==4){ scanf("%d",&a[i]); x += a[i]; x %= n; } } //cout<<'a'<<endl; x = x0; dsu D2(n); vector<mint> A(n); for(int i=1;i<=q;i++){ if(t[i]==1){ int la = D2.leader(a[i]),lb = D2.leader(x); if(D2.same(la,lb))continue; mint tt = D2.size(a[i]); tt *= D2.size(x); tt *= b[i]; tt += A[la] + A[lb]; D2.merge(la,lb); int lc = D2.leader(la); int ld = lc^la^lb; A[ld] = 0; A[lc] = tt; } if(t[i]==2){ if(a[i]==b[i]){ printf("0\n"); continue; } if(D.same(p[i],a[i],b[i])){ x += memo[i]; x %= n; printf("%d\n",memo[i]); //cout<<b[ok+1]<<endl; } else printf("-1\n"); } if(t[i]==3){ printf("%d\n",A[D2.leader(a[i])].val()); } if(t[i]==4){ x += a[i]; x %= n; } } return 0; }