結果
| 問題 |
No.2301 Namorientation
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-05-12 22:31:53 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 970 ms / 3,000 ms |
| コード長 | 5,115 bytes |
| コンパイル時間 | 2,598 ms |
| コンパイル使用メモリ | 219,872 KB |
| 最終ジャッジ日時 | 2025-02-12 23:16:50 |
|
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 30 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
#define SZ(x) (int) (x).size()
#define REP(i, n) for(int i = 0; i < (n); i++)
#define FOR(i, a, b) for(auto i = (a); i < (b); i++)
#define For(i, a, b, c) \
for(auto i = (a); i != (b); i += (c))
#define REPR(i, n) for(auto i = (n) -1; i >= 0; i--)
#define ALL(s) (s).begin(), (s).end()
#define so(V) sort(ALL(V))
#define rev(V) reverse(ALL(V))
#define uni(v) v.erase(unique(ALL(v)), (v).end())
#define eb emplace_back
typedef unsigned long long ull;
typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<bool> vb;
typedef vector<vi> vvi;
typedef vector<vll> vvll;
typedef pair<int, int> PI;
typedef pair<ll, ll> PL;
const double EPS = 1e-6;
const int MOD = 1e9 + 7;
const int INF = (1 << 30);
const ll LINF = 1e18;
const double math_PI = acos(-1);
template<typename T>
vector<T> make_v(size_t a) {
return vector<T>(a);
}
template<typename T, typename... Ts>
auto make_v(size_t a, Ts... ts) {
return vector<decltype(make_v<T>(ts...))>(
a, make_v<T>(ts...));
}
template<typename T, typename V>
typename enable_if<is_class<T>::value == 0>::type fill_v(
T& t, const V& v) {
t = v;
}
template<typename T, typename V>
typename enable_if<is_class<T>::value != 0>::type fill_v(
T& t, const V& v) {
for(auto& e: t) fill_v(e, v);
}
template<class T>
bool chmax(T& a, const T& b) {
if(a < b) {
a = b;
return true;
}
return false;
}
template<class T>
bool chmin(T& a, const T& b) {
if(a > b) {
a = b;
return true;
}
return false;
}
template<typename S, typename T>
istream& operator>>(istream& is, pair<S, T>& p) {
cin >> p.first >> p.second;
return is;
}
template<typename T>
istream& operator>>(istream& is, vector<T>& vec) {
for(T& x: vec) is >> x;
return is;
}
template<typename T>
string join(vector<T>& vec, string splitter) {
stringstream ss;
REP(i, SZ(vec)) {
if(i != 0) ss << splitter;
ss << vec[i];
}
return ss.str();
}
template<typename T>
ostream& operator<<(ostream& os, vector<T>& vec) {
os << join(vec, " ");
return os;
}
template<class T = ll>
struct Edge {
public:
int from, to;
T cost;
Edge() {
}
Edge(int _from, int _to, T _cost) {
from = _from;
to = _to;
cost = _cost;
}
};
template<class T = ll>
using Edges = vector<Edge<T>>;
template<class T = ll>
using Graph = vector<Edges<T>>;
vi cycle_detection(Graph<>& G) {
int N = SZ(G);
vi cycle;
vb visited(N);
vb seen(N);
auto dfs = [&](auto f, int cur, int pre = -1) -> int {
if(seen[cur]) {
return cur;
}
seen[cur] = true;
for(Edge e: G[cur]) {
if(e.to == pre) continue;
if(visited[e.to]) continue;
int begin = f(f, e.to, cur);
if(begin == -2) {
visited[cur] = true;
return -2;
}
if(begin == -1) continue;
if(begin == cur) {
cycle.push_back(cur);
visited[cur] = true;
return -2;
}
cycle.push_back(cur);
visited[cur] = true;
return begin;
}
visited[cur] = true;
return -1;
};
REP(i, N) {
if(!cycle.empty()) break;
if(visited[i]) continue;
dfs(dfs, i);
}
if(cycle.empty()) {
return vi();
}
rev(cycle);
vi C(N, -1);
REP(i, SZ(cycle)) {
C[cycle[i]] = i;
}
int ind = 0;
vi ret;
using P = pair<int, int>;
set<P> S;
while(ind != -1) {
int v = cycle[ind];
ret.push_back(v);
S.insert({ ind, SZ(ret) - 1 });
int next = -1;
int pre = -1;
for(Edge e: G[v]) {
int n = C[e.to];
if(n == -1) continue;
if(n < ind) {
auto [a, b] = *S.lower_bound({ n, 0 });
if(a != n) continue;
chmax(pre, b);
}
chmax(next, n);
}
if(pre != -1) {
vi new_ret;
FOR(i, pre, SZ(ret)) {
new_ret.push_back(ret[i]);
}
ret = new_ret;
return ret;
}
ind = next;
}
return ret;
}
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
int N;
cin >> N;
Graph<> G(N);
map<PI, int> M;
REP(i, N) {
int A, B;
cin >> A >> B;
A--;
B--;
G[A].eb(A, B, i + 1);
G[B].eb(B, A, -i - 1);
M[{ A, B }] = i + 1;
M[{ B, A }] = -1 - i;
}
vi to(N, -1);
vi ans(N, -1);
auto dfs2 = [&](auto f, int cur, int pre) -> void {
int m = M[{ pre, cur }];
if(m > 0)
ans[m - 1] = 0;
else
ans[-m - 1] = 1;
for(auto e: G[cur]) {
if(e.to == pre) continue;
f(f, e.to, cur);
}
};
bool found = false;
auto dfs = [&](auto f, int cur, int pre) -> void {
if(found) return;
if(to[cur] != -1) {
int c = cur;
int p = pre;
int m = M[{ p, c }];
if(m > 0)
ans[m - 1] = 1;
else
ans[-m - 1] = 0;
for(auto e: G[c]) {
if(e.to != to[c] && e.to != p) {
dfs2(dfs2, e.to, c);
}
}
p = c;
c = to[c];
while(c != cur) {
m = M[{ p, c }];
if(m > 0)
ans[m - 1] = 1;
else
ans[-m - 1] = 0;
for(auto e: G[c]) {
if(e.to != to[c] && e.to != p) {
dfs2(dfs2, e.to, c);
}
}
p = c;
c = to[c];
}
found = true;
return;
}
for(auto e: G[cur]) {
if(e.to == pre) continue;
to[e.from] = e.to;
f(f, e.to, e.from);
to[e.from] = -1;
}
};
dfs(dfs, 0, -1);
REP(i, N) {
if(ans[i] == 1) {
cout << "->" << endl;
} else if(ans[i] == 0) {
cout << "<-" << endl;
}
}
return 0;
}