結果
| 問題 | No.2308 [Cherry 5th Tune B] もしかして、真? |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-05-19 22:42:20 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 110 ms / 2,000 ms |
| コード長 | 4,500 bytes |
| コンパイル時間 | 3,387 ms |
| コンパイル使用メモリ | 174,708 KB |
| 実行使用メモリ | 18,312 KB |
| 最終ジャッジ日時 | 2024-12-20 01:11:46 |
| 合計ジャッジ時間 | 9,229 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 39 |
ソースコード
#include <stdio.h>
#include <iostream>
#include <iomanip>
#include <string>
#include <vector>
#include <map>
#include <algorithm>
#include <array>
#include <queue>
#include <stack>
#include <set>
#include <list>
#include <limits>
#include <unordered_map>
#include <unordered_set>
#include <bitset>
#include <cmath>
#include <math.h>
#include <climits>
#pragma warning(push)
#pragma warning(disable:26498 26450 26451 26812)
#include "atcoder/all"
#pragma warning(pop)
//#include <boost/multiprecision/cpp_int.hpp>
//using namespace boost::multiprecision;
// std::fixed << std::setprecision(10) <<
using namespace std;
using namespace atcoder;
using ll = long long;
using ull = unsigned long long;
using mint = modint998244353;
using mint2 = modint1000000007;
const double eps = 1e-9;
#define REP(i, n) for (ll i = 0; i < (n); ++i)
#define REPI(i, init, n) for (ll i = init; i < (n); ++i)
#define REPD(i, init) for (ll i = init; i >=0; --i)
#define REPDI(i, init, n) for (ll i = init; i >=n; --i)
#define REPE(i, c) for (const auto& i : c)
using vl = vector<ll>;
#define VL(a, n) vector<ll> a; a.assign(n, 0);
#define VLI(a, n) vector<ll> a; a.assign(n, 0); for(auto& x : a) cin >> x;
#define VSI(a, n) vector<string> a; a.assign(n, ""); for(auto& x : a) cin >> x;
using vvl = vector<vector<ll>>;
#define VVLI(a, n, m, init) vector<vector<ll>> a(n); for(auto& x : a) x.assign(m, init);
struct uv { ll u; ll v; ll c; };
#define VUVI(a, n) vector<uv> a; a.assign(n, {0, 0, 1}); for(auto& x : a) {cin >> x.u >> x.v; x.u--; x.v--;}
#define VUVCI(a, n) vector<uv> a; a.assign(n, {0, 0, 0}); for(auto& x : a) {cin >> x.u >> x.v >> x.c; x.u--; x.v--;}
vvl to_edge(const int n, const vector<uv>& v) { vvl ret(n); for (auto& x : v) ret[x.u].push_back(x.v); return ret; }
vvl to_edge_d(const int n, const vector<uv>& v) { vvl ret(n); for (auto& x : v) { ret[x.u].push_back(x.v); ret[x.v].push_back(x.u); } return ret; }
template <class T = long long> using pql = priority_queue<T>;
template <class T = long long> using pqg = priority_queue<T, vector<T>, greater<T>>;
const char* YES = "Yes";
const char* NO = "No";
void yn(bool f) { std::cout << (f ? YES : NO) << endl; };
template<class T> void ov(const T& v) { for (auto it = v.begin(); it != v.end(); it++) { if (it != v.begin()) cout << " "; cout << *it; } };
const ll llhuge = 1LL << 60; //十分でかいが多少足しても溢れない数値
template<class T, class U> bool chmin(T& a, const U& b) { a = min(a, b); return b == a; }
template<class T, class U> bool chmax(T& a, const U& b) { a = max(a, b); return b == a; }
template<class T> void mysort(T& v) { std::sort(begin(v), end(v)); };
template<class T, class U> void mysort(T& v, U pr) { std::sort(begin(v), end(v), pr); };
template<class T> void myrev(T& v) { std::reverse(begin(v), end(v)); };
using namespace std;
ll op(ll a, ll b) { return a + b; }
ll e() { return 0; }
using st = segtree<ll, op, e>;
struct vv {
bool v = false;
ll l = 0;
ll r = 0;
};
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
ll t;
cin >> t;
REP(ttt, t) {
ll n;
cin >> n;
vector<vv> x;
x.assign(n, {});
REP(i, n) {
string s;
cin >> s;
x[i] = { s == "True", i, i };
}
vl y(n-1);
REP(i, n-1) {
string s;
cin >> s;
if (s == "and") y[i] = 0;
if (s == "or") y[i] = 1;
if (s == "xor") y[i] = 2;
if (s == "imp") y[i] = 3;
}
vl ns(n - 1, -1);
{
vl seginit(n - 1, 1);
st seg(seginit);
VLI(s, n - 1);
REP(i, n - 1) {
ll si = s[i];
ns[i] = seg.max_right(0, [si](const ll& sum) {return sum < si; });
seg.set(ns[i], 0);
}
}
REP(i, n - 1) {
ll opi = ns[i];
ll op = y[opi];
bool nv = false;
if (op == 0) nv = x[opi].v && x[opi + 1].v;
if (op == 1) nv = x[opi].v || x[opi + 1].v;
if (op == 2) nv = x[opi].v ^ x[opi + 1].v;
if (op == 3) nv = !x[opi].v || x[opi + 1].v;
ll nl = x[opi].l;
ll nr = x[opi+1].r;
x[nl] = { nv, nl, nr };
x[nr] = { nv, nl, nr };
}
if (x[0].v) {
cout << "True" << endl;
}
else {
cout << "False" << endl;
}
}
return 0;
}