結果

問題 No.1688 Veterinarian
ユーザー deuteridayodeuteridayo
提出日時 2023-06-28 15:16:20
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 88 ms / 3,000 ms
コード長 3,764 bytes
コンパイル時間 4,206 ms
コンパイル使用メモリ 274,912 KB
実行使用メモリ 61,568 KB
最終ジャッジ日時 2024-07-05 08:13:43
合計ジャッジ時間 5,867 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 2 ms
5,376 KB
testcase_02 AC 2 ms
5,376 KB
testcase_03 AC 1 ms
5,376 KB
testcase_04 AC 1 ms
5,376 KB
testcase_05 AC 2 ms
5,376 KB
testcase_06 AC 2 ms
5,376 KB
testcase_07 AC 5 ms
6,912 KB
testcase_08 AC 88 ms
61,568 KB
testcase_09 AC 79 ms
57,216 KB
testcase_10 AC 8 ms
8,320 KB
testcase_11 AC 9 ms
9,216 KB
testcase_12 AC 2 ms
5,376 KB
testcase_13 AC 3 ms
5,376 KB
testcase_14 AC 2 ms
5,376 KB
testcase_15 AC 5 ms
6,784 KB
testcase_16 AC 2 ms
5,376 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<bits/stdc++.h>
#include<atcoder/all>
using namespace std;
using namespace atcoder;
using lint = long long;
using ulint = unsigned long long;
#define endl '\n'
int const INF = 1<<30;
lint const INF64 = 1LL<<61;
// lint const mod = 1e9+7;
// using mint = modint1000000007;
long const mod = 998244353;
using mint = modint998244353;
lint ceilDiv(lint x, lint y){if(x >= 0){return (x+y-1)/y;}else{return x/y;}}
lint floorDiv(lint x, lint y){if(x >= 0){return x/y;}else{return (x-y+1)/y;}}
lint Sqrt(lint x){lint upper = 1e9;lint lower = 0;while(upper - lower > 0){lint mid = (1+upper + lower)/2;if(mid * mid > x){upper = mid-1;}else{lower = mid;}}return upper;}
lint gcd(lint a,lint b){if(a<b)swap(a,b);if(a%b==0)return b;else return gcd(b,a%b);}
lint lcm(lint a,lint b){return (a / gcd(a,b)) * b;}
lint chmin(vector<lint>&v){lint ans = INF64;for(lint i:v){ans = min(ans, i);}return ans;}
lint chmax(vector<lint>&v){lint ans = -INF64;for(lint i:v){ans = max(ans, i);}return ans;}
double dist(double x1, double y1, double x2, double y2){return sqrt(pow(x1-x2, 2) + pow(y1-y2,2));}
string toString(lint n){string ans = "";if(n == 0){ans += "0";}else{while(n > 0){int a = n%10;char b = '0' + a;string c = "";c += b;n /= 10;ans = c + ans;}}return ans;}
string toString(lint n, lint k){string ans = toString(n);string tmp = "";while(ans.length() + tmp.length() < k){tmp += "0";}return tmp + ans;}
vector<lint>prime;void makePrime(lint n){prime.push_back(2);for(lint i=3;i<=n;i+=2){bool chk = true;for(lint j=0;j<prime.size() && prime[j]*prime[j] <= i;j++){if(i % prime[j]==0){chk=false;break;}}if(chk)prime.push_back(i);}}
lint Kai[20000001]; bool firstCallnCr = true; 
lint ncrmodp(lint n,lint r,lint p){ if(firstCallnCr){ Kai[0] = 1; for(int i=1;i<=20000000;i++){ Kai[i] = Kai[i-1] * i; Kai[i] %= mod;} firstCallnCr = false;} if(n<0)return 0;
if(n < r)return 0;if(n==0)return 1;lint ans = Kai[n];lint tmp = (Kai[r] * Kai[n-r]) % p;for(lint i=1;i<=p-2;i*=2){if(i & p-2){ans *= tmp;ans %= p;}tmp *= tmp;tmp %= p;}return ans;}
#define rep(i, n) for(int i = 0; i < n; i++)
#define repp(i, x, y) for(int i = x; i < y; i++)
#define vec vector
// #define pb push_back
#define se second
#define fi first
#define all(x) x.begin(),x.end()

struct edge{
    int to;
};
using graph = vector<vector<edge>>;

int main(){
    int a,b,c,n;
    cin >> a >> b >> c >> n;
    vec<vec<vec<vec<double>>>>dp(n+1, vec<vec<vec<double>>>(a+1, vec<vec<double>>(b+1, vec<double>(c+1, 0))));
    dp[0][a][b][c] = 1;
    rep(i, n) {
        rep(aa, a+1) {
            rep(bb, b+1) {
                rep(cc, c+1) {
                    double N = aa + bb + cc;
                    double pa = 0, pb = 0, pc = 0;
                  
                    if(aa >= 2)pa = aa*(aa-1)/(N*(N-1));
                    if(bb >= 2)pb = bb*(bb-1)/(N*(N-1));
                    if(cc >= 2)pc = cc*(cc-1)/(N*(N-1));
                    
                    double P = 1.0 - pa - pb - pc;
                    if(aa > 1) {
                        dp[i+1][aa-1][bb][cc] += dp[i][aa][bb][cc] * pa;
                    }
                    if(bb > 1) {
                        dp[i+1][aa][bb-1][cc] += dp[i][aa][bb][cc] * pb;
                    }
                    if(cc > 1) {
                        dp[i+1][aa][bb][cc-1] += dp[i][aa][bb][cc] * pc;
                    }
                    dp[i+1][aa][bb][cc] += dp[i][aa][bb][cc] * P;
                }
            }
        }
    }
    double aa=0, bb = 0, cc=0;
    rep(i, a+1) {
        rep(j, b+1) {
            rep(k, c+1) {
                aa += (a - i) * dp[n][i][j][k];
                bb += (b - j) * dp[n][i][j][k];
                cc += (c - k) * dp[n][i][j][k];
            }
        }
    }
    printf("%.10lf %.10lf %.10lf", aa, bb, cc);
}
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