結果

問題 No.2366 登校
ユーザー tokusakuraitokusakurai
提出日時 2023-06-30 21:57:23
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 337 ms / 4,000 ms
コード長 5,263 bytes
コンパイル時間 2,661 ms
コンパイル使用メモリ 222,648 KB
実行使用メモリ 19,968 KB
最終ジャッジ日時 2024-06-12 07:49:16
合計ジャッジ時間 5,223 ms
ジャッジサーバーID
(参考情報)
judge3 / judge1
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,816 KB
testcase_01 AC 2 ms
6,944 KB
testcase_02 AC 2 ms
6,940 KB
testcase_03 AC 2 ms
6,944 KB
testcase_04 AC 2 ms
6,944 KB
testcase_05 AC 2 ms
6,940 KB
testcase_06 AC 2 ms
6,940 KB
testcase_07 AC 2 ms
6,940 KB
testcase_08 AC 2 ms
6,944 KB
testcase_09 AC 2 ms
6,944 KB
testcase_10 AC 2 ms
6,944 KB
testcase_11 AC 2 ms
6,940 KB
testcase_12 AC 97 ms
7,552 KB
testcase_13 AC 95 ms
7,680 KB
testcase_14 AC 95 ms
7,680 KB
testcase_15 AC 98 ms
7,552 KB
testcase_16 AC 98 ms
7,424 KB
testcase_17 AC 96 ms
7,552 KB
testcase_18 AC 95 ms
7,552 KB
testcase_19 AC 98 ms
7,552 KB
testcase_20 AC 97 ms
7,552 KB
testcase_21 AC 93 ms
7,424 KB
testcase_22 AC 74 ms
7,424 KB
testcase_23 AC 61 ms
19,840 KB
testcase_24 AC 61 ms
19,968 KB
testcase_25 AC 330 ms
19,840 KB
testcase_26 AC 337 ms
19,840 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (n); i++)
#define per(i, n) for (int i = (n)-1; i >= 0; i--)
#define rep2(i, l, r) for (int i = (l); i < (r); i++)
#define per2(i, l, r) for (int i = (r)-1; i >= (l); i--)
#define each(e, v) for (auto &e : v)
#define MM << " " <<
#define pb push_back
#define eb emplace_back
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
#define sz(x) (int)x.size()
using ll = long long;
using pii = pair<int, int>;
using pil = pair<int, ll>;
using pli = pair<ll, int>;
using pll = pair<ll, ll>;

template <typename T>
using minheap = priority_queue<T, vector<T>, greater<T>>;

template <typename T>
using maxheap = priority_queue<T>;

template <typename T>
bool chmax(T &x, const T &y) {
    return (x < y) ? (x = y, true) : false;
}

template <typename T>
bool chmin(T &x, const T &y) {
    return (x > y) ? (x = y, true) : false;
}

template <typename T>
int flg(T x, int i) {
    return (x >> i) & 1;
}

int pct(int x) { return __builtin_popcount(x); }
int pct(ll x) { return __builtin_popcountll(x); }
int topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }
int topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }
int botbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); }
int botbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }

template <typename T>
void print(const vector<T> &v, T x = 0) {
    int n = v.size();
    for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' ');
    if (v.empty()) cout << '\n';
}

template <typename T>
void printn(const vector<T> &v, T x = 0) {
    int n = v.size();
    for (int i = 0; i < n; i++) cout << v[i] + x << '\n';
}

template <typename T>
int lb(const vector<T> &v, T x) {
    return lower_bound(begin(v), end(v), x) - begin(v);
}

template <typename T>
int ub(const vector<T> &v, T x) {
    return upper_bound(begin(v), end(v), x) - begin(v);
}

template <typename T>
void rearrange(vector<T> &v) {
    sort(begin(v), end(v));
    v.erase(unique(begin(v), end(v)), end(v));
}

template <typename T>
vector<int> id_sort(const vector<T> &v, bool greater = false) {
    int n = v.size();
    vector<int> ret(n);
    iota(begin(ret), end(ret), 0);
    sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; });
    return ret;
}

template <typename T>
void reorder(vector<T> &a, const vector<int> &ord) {
    int n = a.size();
    vector<T> b(n);
    for (int i = 0; i < n; i++) b[i] = a[ord[i]];
    swap(a, b);
}

template <typename T>
T floor(T x, T y) {
    assert(y != 0);
    if (y < 0) x = -x, y = -y;
    return (x >= 0 ? x / y : (x - y + 1) / y);
}

template <typename T>
T ceil(T x, T y) {
    assert(y != 0);
    if (y < 0) x = -x, y = -y;
    return (x >= 0 ? (x + y - 1) / y : x / y);
}

template <typename S, typename T>
pair<S, T> operator+(const pair<S, T> &p, const pair<S, T> &q) {
    return make_pair(p.first + q.first, p.second + q.second);
}

template <typename S, typename T>
pair<S, T> operator-(const pair<S, T> &p, const pair<S, T> &q) {
    return make_pair(p.first - q.first, p.second - q.second);
}

template <typename S, typename T>
istream &operator>>(istream &is, pair<S, T> &p) {
    S a;
    T b;
    is >> a >> b;
    p = make_pair(a, b);
    return is;
}

template <typename S, typename T>
ostream &operator<<(ostream &os, const pair<S, T> &p) {
    return os << p.first << ' ' << p.second;
}

struct io_setup {
    io_setup() {
        ios_base::sync_with_stdio(false);
        cin.tie(NULL);
        cout << fixed << setprecision(15);
    }
} io_setup;

constexpr int inf = (1 << 30) - 1;
constexpr ll INF = (1LL << 60) - 1;
// constexpr int MOD = 1000000007;
constexpr int MOD = 998244353;

void solve() {
    int N, M, K, T;
    cin >> N >> M >> K >> T;

    int L = N + M;

    vector<vector<vector<ll>>> d(N, vector<vector<ll>>(M, vector<ll>(2 * L + 1, INF)));
    d[0][0][L] = 0;

    vector<vector<ll>> C(N, vector<ll>(M, INF)), D = C;
    rep(i, K) {
        int x, y;
        cin >> x >> y;
        x--, y--;
        cin >> C[x][y] >> D[x][y];
    }

    using P = pair<ll, tuple<int, int, ll>>;
    minheap<P> que;

    auto push = [&](int i, int j, int k) { que.emplace(d[i][j][k], make_tuple(i, j, k)); };
    push(0, 0, L);

    vector<int> dx = {1, 0, -1, 0}, dy = {0, 1, 0, -1};
    auto IN = [&](int i, int j) { return 0 <= i && i < N && 0 <= j && j < M; };

    while (!empty(que)) {
        ll t = que.top().first;
        auto [i, j, k] = que.top().second;
        que.pop();
        if (d[i][j][k] < t) continue;
        // cout << i MM j MM k MM t << '\n';

        if (C[i][j] != INF) {
            ll nk = max(0LL, k - C[i][j] + 1);
            if (chmin(d[i][j][nk], t + D[i][j])) push(i, j, nk);
        }

        rep(l, 4) {
            int ni = i + dx[l], nj = j + dy[l];
            if (!IN(ni, nj)) continue;
            int nk = k + 1;
            if (nk > 2 * L) continue;
            if (chmin(d[ni][nj][nk], t)) push(ni, nj, nk);
        }
    }

    ll ans = INF;
    rep(i, L + 1) {
        if (i <= T) chmin(ans, d[N - 1][M - 1][L + i]);
    }

    cout << (ans == INF ? -1 : ans) << '\n';
}

int main() {
    int T = 1;
    // cin >> T;
    while (T--) solve();
}
0