結果

問題 No.2365 Present of good number
ユーザー 👑 hos.lyrichos.lyric
提出日時 2023-06-30 22:41:50
言語 D
(dmd 2.109.1)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 4,574 bytes
コンパイル時間 3,203 ms
コンパイル使用メモリ 153,484 KB
実行使用メモリ 6,948 KB
最終ジャッジ日時 2024-07-07 10:32:44
合計ジャッジ時間 4,126 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 39
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import std.conv, std.functional, std.range, std.stdio, std.string;
import std.algorithm, std.array, std.bigint, std.bitmanip, std.complex, std.container, std.math, std.mathspecial, std.numeric, std.regex, std
    .typecons;
import core.bitop;
class EOFException : Throwable { this() { super("EOF"); } }
string[] tokens;
string readToken() { for (; tokens.empty; ) { if (stdin.eof) { throw new EOFException; } tokens = readln.split; } auto token = tokens.front; tokens
    .popFront; return token; }
int readInt() { return readToken.to!int; }
long readLong() { return readToken.to!long; }
bool chmin(T)(ref T t, in T f) { if (t > f) { t = f; return true; } else { return false; } }
bool chmax(T)(ref T t, in T f) { if (t < f) { t = f; return true; } else { return false; } }
int binarySearch(alias pred, T)(in T[] as) { int lo = -1, hi = cast(int)(as.length); for (; lo + 1 < hi; ) { const mid = (lo + hi) >> 1;
    (unaryFun!pred(as[mid]) ? hi : lo) = mid; } return hi; }
int lowerBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a >= val)); }
int upperBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a > val)); }
struct ModInt(uint M_) {
import std.conv : to;
alias M = M_;
uint x;
this(ModInt a) { x = a.x; }
this(uint x_) { x = x_ % M; }
this(ulong x_) { x = cast(uint)(x_ % M); }
this(int x_) { x = ((x_ %= cast(int)(M)) < 0) ? (x_ + cast(int)(M)) : x_; }
this(long x_) { x = cast(uint)(((x_ %= cast(long)(M)) < 0) ? (x_ + cast(long)(M)) : x_); }
ref ModInt opAssign(T)(inout(T) a) if (is(T == uint) || is(T == ulong) || is(T == int) || is(T == long)) { return this = ModInt(a); }
ref ModInt opOpAssign(string op, T)(T a) {
static if (is(T == ModInt)) {
static if (op == "+") { x = ((x += a.x) >= M) ? (x - M) : x; }
else static if (op == "-") { x = ((x -= a.x) >= M) ? (x + M) : x; }
else static if (op == "*") { x = cast(uint)((cast(ulong)(x) * a.x) % M); }
else static if (op == "/") { this *= a.inv(); }
else static assert(false);
return this;
} else static if (op == "^^") {
if (a < 0) return this = inv()^^(-a);
ModInt b = this, c = 1U;
for (long e = a; e; e >>= 1) { if (e & 1) c *= b; b *= b; }
return this = c;
} else {
return mixin("this " ~ op ~ "= ModInt(a)");
}
}
ModInt inv() const {
uint a = M, b = x; int y = 0, z = 1;
for (; b; ) { const q = a / b; const c = a - q * b; a = b; b = c; const w = y - cast(int)(q) * z; y = z; z = w; }
assert(a == 1); return ModInt(y);
}
ModInt opUnary(string op)() const {
static if (op == "+") { return this; }
else static if (op == "-") { ModInt a; a.x = x ? (M - x) : 0U; return a; }
else static assert(false);
}
ModInt opBinary(string op, T)(T a) const { return mixin("ModInt(this) " ~ op ~ "= a"); }
ModInt opBinaryRight(string op, T)(T a) const { return mixin("ModInt(a) " ~ op ~ "= this"); }
bool opCast(T: bool)() const { return (x != 0U); }
string toString() const { return x.to!string; }
}
enum MO = 10^^9 + 7;
alias Mint = ModInt!MO;
alias Mint1 = ModInt!(MO - 1);
void main() {
try {
for (; ; ) {
const N = readInt;
const K = readLong;
const lim = N + 10;
auto lpf = iota(lim).array;
foreach (p; 2 .. lim) if (lpf[p] == p) {
for (int n = 2 * p; n < lim; n += p) chmin(lpf[n], p);
}
Mint1[int] es;
for (int n = N; n > 1; ) {
const p = lpf[n];
int e;
do {
++e;
n /= p;
} while (n % p == 0);
es[p] = e;
}
long k = K;
for (; k > 0; --k) {
bool good = true;
foreach (p, e; es) {
good = good && (p <= 3);
}
if (good && k % 2 == 0) {
break;
}
Mint1[int] fs;
foreach (p, e; es) {
for (int n = p + 1; n > 1; ) {
const q = lpf[n];
int f;
do {
++f;
n /= q;
} while (n % q == 0);
auto ptr = q in fs;
if (ptr) {
*ptr += e * f;
} else {
fs[q] = e * f;
}
}
}
es = fs;
debug {
writeln(es);
}
}
if (k > 0) {
assert(k % 2 == 0);
const two = Mint1(2)^^(k / 2);
if (2 in es) es[2] *= two;
if (3 in es) es[3] *= two;
}
Mint ans = 1;
foreach (p, e; es) {
ans *= Mint(p)^^e.x;
}
writeln(ans);
}
} catch (EOFException e) {
}
}
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