結果
問題 | No.2382 Amidakuji M |
ユーザー |
|
提出日時 | 2023-07-14 21:41:00 |
言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 51 ms / 2,000 ms |
コード長 | 4,187 bytes |
コンパイル時間 | 2,683 ms |
コンパイル使用メモリ | 248,644 KB |
実行使用メモリ | 8,940 KB |
最終ジャッジ日時 | 2024-09-16 06:34:51 |
合計ジャッジ時間 | 3,887 ms |
ジャッジサーバーID (参考情報) |
judge6 / judge2 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 19 |
ソースコード
#include<bits/stdc++.h>#include <algorithm>#ifdef _MSC_VER#include <intrin.h>#endifnamespace atcoder {namespace internal {// @param n `0 <= n`// @return minimum non-negative `x` s.t. `n <= 2**x`int ceil_pow2(int n) {int x = 0;while ((1U << x) < (unsigned int)(n)) x++;return x;}// @param n `1 <= n`// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`int bsf(unsigned int n) {#ifdef _MSC_VERunsigned long index;_BitScanForward(&index, n);return index;#elsereturn __builtin_ctz(n);#endif}} // namespace internal} // namespace atcoder#include <cassert>#include <vector>namespace atcoder {template <class S, S (*op)(S, S), S (*e)()> struct segtree {public:segtree() : segtree(0) {}segtree(int n) : segtree(std::vector<S>(n, e())) {}segtree(const std::vector<S>& v) : _n(int(v.size())) {log = internal::ceil_pow2(_n);size = 1 << log;d = std::vector<S>(2 * size, e());for (int i = 0; i < _n; i++) d[size + i] = v[i];for (int i = size - 1; i >= 1; i--) {update(i);}}void set(int p, S x) {assert(0 <= p && p < _n);p += size;d[p] = x;for (int i = 1; i <= log; i++) update(p >> i);}S get(int p) {assert(0 <= p && p < _n);return d[p + size];}S prod(int l, int r) {assert(0 <= l && l <= r && r <= _n);S sml = e(), smr = e();l += size;r += size;while (l < r) {if (l & 1) sml = op(sml, d[l++]);if (r & 1) smr = op(d[--r], smr);l >>= 1;r >>= 1;}return op(sml, smr);}S all_prod() { return d[1]; }template <bool (*f)(S)> int max_right(int l) {return max_right(l, [](S x) { return f(x); });}template <class F> int max_right(int l, F f) {assert(0 <= l && l <= _n);assert(f(e()));if (l == _n) return _n;l += size;S sm = e();do {while (l % 2 == 0) l >>= 1;if (!f(op(sm, d[l]))) {while (l < size) {l = (2 * l);if (f(op(sm, d[l]))) {sm = op(sm, d[l]);l++;}}return l - size;}sm = op(sm, d[l]);l++;} while ((l & -l) != l);return _n;}template <bool (*f)(S)> int min_left(int r) {return min_left(r, [](S x) { return f(x); });}template <class F> int min_left(int r, F f) {assert(0 <= r && r <= _n);assert(f(e()));if (r == 0) return 0;r += size;S sm = e();do {r--;while (r > 1 && (r % 2)) r >>= 1;if (!f(op(d[r], sm))) {while (r < size) {r = (2 * r + 1);if (f(op(d[r], sm))) {sm = op(d[r], sm);r--;}}return r + 1 - size;}sm = op(d[r], sm);} while ((r & -r) != r);return 0;}private:int _n, size, log;std::vector<S> d;void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }};} // namespace atcoderusing namespace std;using namespace atcoder;long long op(long long a,long long b){return a+b;}long long e(){return 0;}long long llceil(long long a,long long b){if(a%b==0){return a/b;}return (a/b)+1;}int main(){ios::sync_with_stdio(false);cin.tie(nullptr);long long n,m;cin >> n >> m;vector<long long> init(n+5,0);segtree<long long, op, e> seg(init);long long inv=0;for(long long i=0;i<n;i++){long long a;cin >> a;inv+=i;inv-=seg.prod(0,a);seg.set(a,1);}long long ce=llceil(inv,m);if((ce*m)%2 == inv%2){cout << ce*m << "\n";return 0;}ce++;if((ce*m)%2 == inv%2){cout << ce*m << "\n";return 0;}cout << "-1\n";// cout << inv << "\n";return 0;}