結果

問題 No.2382 Amidakuji M
ユーザー fumofumofuni
提出日時 2023-07-14 22:41:08
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 121 ms / 2,000 ms
コード長 4,823 bytes
コンパイル時間 2,345 ms
コンパイル使用メモリ 198,824 KB
最終ジャッジ日時 2025-02-15 14:23:29
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 19
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
using namespace std;
//#pragma GCC optimize("Ofast")
#define rep(i,n) for(ll i=0;i<n;i++)
#define repl(i,l,r) for(ll i=(l);i<(r);i++)
#define per(i,n) for(ll i=(n)-1;i>=0;i--)
#define perl(i,r,l) for(ll i=r-1;i>=l;i--)
#define fi first
#define se second
#define pb push_back
#define ins insert
#define pqueue(x) priority_queue<x,vector<x>,greater<x>>
#define all(x) (x).begin(),(x).end()
#define CST(x) cout<<fixed<<setprecision(x)
#define vtpl(x,y,z) vector<tuple<x,y,z>>
#define rev(x) reverse(x);
using ll=long long;
using vl=vector<ll>;
using vvl=vector<vector<ll>>;
using pl=pair<ll,ll>;
using vpl=vector<pl>;
using vvpl=vector<vpl>;
const ll MOD=1000000007;
const ll MOD9=998244353;
const int inf=1e9+10;
const ll INF=4e18;
const ll dy[9]={1,0,-1,0,1,1,-1,-1,0};
const ll dx[9]={0,1,0,-1,1,-1,1,-1,0};
template<class T> inline bool chmin(T& a, T b) {
if (a > b) {
a = b;
return true;
}
return false;
}
template<class T> inline bool chmax(T& a, T b) {
if (a < b) {
a = b;
return true;
}
return false;
}
//2DBIT, 0-indexed;
template <typename T>
struct BIT2D{
int H;
T def;
vector<ll> height;
vector<vector<ll>> width;
vector<vector<T>> data;
function<T(T,T)> fx;
BIT2D(vl &x,vl &y,T _def,function<T(T,T)> _fx){
def=_def,fx=_fx;
height=x;
sort(all(height));
height.erase(unique(all(height)),height.end());
H=height.size();
width.resize(H);
data.resize(H);
rep(i,x.size()){
ll idx=lower_bound(all(height),x[i])-height.begin();
width[idx].emplace_back(y[i]);
}
rep(i,H){
sort(all(width[i]));
}
rep(i,H){
width[i].erase(unique(all(width[i])),width[i].end());
data[i].resize(width[i].size(),def);
ll to=i|(i+1);
if(to<H){
vector<ll> hoge;
merge(all(width[i]),all(width[to]),back_inserter(hoge));
swap(width[to],hoge);
}
}
}
void change(ll _x,ll _y,T val){
int a=lower_bound(all(height),_x)-height.begin();
for(int x=a;x<H;x|=x+1){
int b=lower_bound(all(width[x]),_y)-width[x].begin();
for(int y=b;y<width[x].size();y|=y+1){
data[x][y]=fx(data[x][y],val);
}
}
}
T fold(ll _x,ll _y){
T ret=def;
int a=lower_bound(all(height),_x)-height.begin();
for(int x=a-1;x>=0;x=(x&(x+1))-1){
int b=lower_bound(all(width[x]),_y)-width[x].begin();
for(int y=b-1;y>=0;y=(y&(y+1))-1){
ret=fx(ret,data[x][y]);
}
}
return ret;
}
};
//0-indexed,2
template <class T>
struct SegTree {
private:
int n;//
vector<T> data;// vector
T def; //
function<T(T, T)> operation; // 使
function<T(T, T)> change;// 使
T find(int a, int b) {
T val_left = def, val_right = def;
for (a += (n - 1), b += (n - 1); a < b; a >>= 1, b >>= 1)
{
if ((a & 1) == 0){
val_left = operation(val_left, data[a]);
}
if ((b & 1) == 0){
val_right = operation(data[--b],val_right);
}
}
return operation(val_left, val_right);
}
public:
// _n:, _def:, _operation:,
// _change:
SegTree(size_t _n, T _def, function<T(T, T)> _operation,
function<T(T, T)> _change=[](T a,T b){return b;})
: def(_def), operation(_operation), change(_change) {
n = 1;
while (n < _n) {
n *= 2;
}
data = vector<T>(2 * n - 1, def);
}
void set(int i, T x) { data[i + n - 1] = x; }
void build() {
for (int k=n-2;k>=0;k--) data[k] = operation(data[2*k+1],data[2*k+2]);
}
// i(0-indexed)x
void update(int i, T x) {
i += n - 1;
data[i] = change(data[i], x);
while (i > 0) {
i = (i - 1) / 2;
data[i] = operation(data[i * 2 + 1], data[i * 2 + 2]);
}
}
T all_prod(){
return data[0];
}
// [a, b)
T query(int a, int b) {
//return _query(a, b, 0, 0, n);
return find(a,b);
}
//
T operator[](int i) {
return data[i + n - 1];
}
};
int main(){
ll n,m;cin >> n >> m;
vl v(n);rep(i,n)cin >> v[i],v[i]--;
ll ans=0;
SegTree<ll> st(n,0,[](ll a,ll b){return a+b;});
rep(i,n){
ans+=st.query(v[i],n);
st.update(v[i],1);
}
ll q=(ans+m-1)/m*m;
if((q-ans)%2==0){
cout << q << endl;
}
else{
q+=m;
if((q-ans)%2==0)cout << q << endl;
else cout << -1 << endl;
}
}
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