結果
問題 | No.2404 Vertical Throw Up |
ユーザー | woodywoody |
提出日時 | 2023-08-05 01:32:43 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 29 ms / 2,000 ms |
コード長 | 7,308 bytes |
コンパイル時間 | 4,057 ms |
コンパイル使用メモリ | 237,828 KB |
実行使用メモリ | 5,760 KB |
最終ジャッジ日時 | 2024-10-14 23:23:51 |
合計ジャッジ時間 | 5,578 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,248 KB |
testcase_02 | AC | 2 ms
5,248 KB |
testcase_03 | AC | 23 ms
5,248 KB |
testcase_04 | AC | 19 ms
5,248 KB |
testcase_05 | AC | 28 ms
5,760 KB |
testcase_06 | AC | 2 ms
5,248 KB |
testcase_07 | AC | 29 ms
5,760 KB |
testcase_08 | AC | 22 ms
5,248 KB |
testcase_09 | AC | 19 ms
5,248 KB |
testcase_10 | AC | 6 ms
5,248 KB |
testcase_11 | AC | 6 ms
5,248 KB |
testcase_12 | AC | 5 ms
5,248 KB |
testcase_13 | AC | 2 ms
5,248 KB |
testcase_14 | AC | 2 ms
5,248 KB |
testcase_15 | AC | 2 ms
5,248 KB |
testcase_16 | AC | 2 ms
5,248 KB |
testcase_17 | AC | 2 ms
5,248 KB |
testcase_18 | AC | 2 ms
5,248 KB |
testcase_19 | AC | 2 ms
5,248 KB |
testcase_20 | AC | 2 ms
5,248 KB |
testcase_21 | AC | 2 ms
5,248 KB |
testcase_22 | AC | 2 ms
5,248 KB |
testcase_23 | AC | 2 ms
5,248 KB |
testcase_24 | AC | 2 ms
5,248 KB |
testcase_25 | AC | 2 ms
5,248 KB |
testcase_26 | AC | 2 ms
5,248 KB |
testcase_27 | AC | 2 ms
5,248 KB |
testcase_28 | AC | 2 ms
5,248 KB |
testcase_29 | AC | 2 ms
5,248 KB |
testcase_30 | AC | 2 ms
5,248 KB |
testcase_31 | AC | 2 ms
5,248 KB |
testcase_32 | AC | 2 ms
5,248 KB |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,b) for(int i=0;i<b;i++) #define rrep(i,b) for(int i=b-1;i>=0;i--) #define rep1(i,b) for(int i=1;i<b;i++) #define repx(i,x,b) for(int i=x;i<b;i++) #define rrepx(i,x,b) for(int i=b-1;i>=x;i--) #define fore(i,a) for(auto& i:a) #define rng(x) (x).begin(), (x).end() #define rrng(x) (x).rbegin(), (x).rend() #define sz(x) ((int)(x).size()) #define pb push_back #define fi first #define se second #define pcnt __builtin_popcountll using namespace std; using namespace atcoder; using ll = long long; using ld = long double; template<typename T> using mpq = priority_queue<T, vector<T>, greater<T>>; template<typename T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; } template<typename T> bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; } template<typename T> ll sumv(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}} #define retval(x) {cout << #x << endl; return;} #define cout2(x,y) cout << x << " " << y << endl; #define coutp(p) cout << p.fi << " " << p.se << endl; #define out cout << ans << endl; #define outd cout << fixed << setprecision(20) << ans << endl; #define outm cout << ans.val() << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define outdv fore(yans , ans) cout << yans.val() << "\n"; #define coutv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define coutv2(v) fore(vy , v) cout << vy << "\n"; #define coutvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define coutvm2(v) fore(vy , v) cout << vy.val() << "\n"; using pll = pair<ll,ll>;using pil = pair<int,ll>;using pli = pair<ll,int>;using pii = pair<int,int>;using pdd = pair<ld,ld>; using vi = vector<int>;using vd = vector<ld>;using vl = vector<ll>;using vs = vector<string>;using vb = vector<bool>; using vpii = vector<pii>;using vpli = vector<pli>;using vpll = vector<pll>;using vpil = vector<pil>; using vvi = vector<vector<int>>;using vvl = vector<vector<ll>>;using vvs = vector<vector<string>>;using vvb = vector<vector<bool>>; using vvpii = vector<vector<pii>>;using vvpli = vector<vector<pli>>;using vvpll = vector<vpll>;using vvpil = vector<vpil>; using mint = modint998244353; //using mint = modint1000000007; //using mint = dynamic_modint<0>; using vm = vector<mint>; using vvm = vector<vector<mint>>; vector<int> dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} #define yes {cout <<"Yes"<<endl;} #define no {cout <<"No"<<endl;} const double eps = 1e-10; const ll LINF = 2001002003004005006ll; const int INF = 1001001001; #define MY_LOCAL_DEBUG #ifdef MY_LOCAL_DEBUG #define show(x) cerr<<#x<<" = "<<x<<endl #define showp(p) cerr<<#p<<" = "<<p.fi<<" : "<<p.se<<endl #define show2(x,y) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<endl #define show3(x,y,z) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<endl #define show4(x,y,z,x2) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<" : "<<#x2<<" = "<<x2<<endl #define test(x) cout << "test" << x << endl #define showv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define showv2(v) fore(vy , v) cout << vy << "\n"; #define showvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define showvm2(v) fore(vy , v) cout << vy.val() << "\n"; #else #define show(x) #define showp(p) #define show2(x,y) #define show3(x,y,z) #define show4(x,y,z,x2) #define test(x) #define showv(v) #define showv2(v) #define showvm(v) #define showvm2(v) #endif template< typename T, T x_low, T x_high, T id > struct DynamicLiChaoTree { struct Line { T a, b; Line(T a, T b) : a(a), b(b) {} inline T get(T x) const { return a * x + b; } }; struct Node { Line x; Node *l, *r; Node(const Line &x) : x{x}, l{nullptr}, r{nullptr} {} }; Node *root; DynamicLiChaoTree() : root{nullptr} {} Node *add_line(Node *t, Line &x, const T &l, const T &r, const T &x_l, const T &x_r) { if(!t) return new Node(x); T t_l = t->x.get(l), t_r = t->x.get(r); if(t_l <= x_l && t_r <= x_r) { return t; } else if(t_l >= x_l && t_r >= x_r) { t->x = x; return t; } else { T m = (l + r) / 2; if(m == r) --m; T t_m = t->x.get(m), x_m = x.get(m); if(t_m > x_m) { swap(t->x, x); if(x_l >= t_l) t->l = add_line(t->l, x, l, m, t_l, t_m); else t->r = add_line(t->r, x, m + 1, r, t_m + x.a, t_r); } else { if(t_l >= x_l) t->l = add_line(t->l, x, l, m, x_l, x_m); else t->r = add_line(t->r, x, m + 1, r, x_m + x.a, x_r); } return t; } } void add_line(const T &a, const T &b) { Line x(a, b); root = add_line(root, x, x_low, x_high, x.get(x_low), x.get(x_high)); } Node *add_segment(Node *t, Line &x, const T &a, const T &b, const T &l, const T &r, const T &x_l, const T &x_r) { if(r < a || b < l) return t; if(a <= l && r <= b) { Line y{x}; return add_line(t, y, l, r, x_l, x_r); } if(t) { T t_l = t->x.get(l), t_r = t->x.get(r); if(t_l <= x_l && t_r <= x_r) return t; } else { t = new Node(Line(0, id)); } T m = (l + r) / 2; if(m == r) --m; T x_m = x.get(m); t->l = add_segment(t->l, x, a, b, l, m, x_l, x_m); t->r = add_segment(t->r, x, a, b, m + 1, r, x_m + x.a, x_r); return t; } void add_segment(const T &l, const T &r, const T &a, const T &b) { Line x(a, b); root = add_segment(root, x, l, r - 1, x_low, x_high, x.get(x_low), x.get(x_high)); } T query(const Node *t, const T &l, const T &r, const T &x) const { if(!t) return id; if(l == r) return t->x.get(x); T m = (l + r) / 2; if(m == r) --m; if(x <= m) return min(t->x.get(x), query(t->l, l, m, x)); else return min(t->x.get(x), query(t->r, m + 1, r, x)); } T query(const T &x) const { return query(root, x_low, x_high, x); } }; const ll x_low = 0; const ll x_hi = INF; const ll query_id = LINF; DynamicLiChaoTree<ll,x_low,x_hi,query_id> li; // DynamicLiChaoTree // DynamicLiChaoTree<typename T, T x_low, T x_high, T id> : 初期化。 // add_line(a,b) : 直線ax+bを追加。 // add_segment_line(a,b,l,r) : 線分ax+b [l,r)を追加 // query(x) : xでのminを出力 void solve(){ using tp = tuple<ll,ll,ll>; ll a; cin>>a; int q; cin>>q; vector<tp> v(q); rep(i,q){ int t; cin>>t; int a,b; cin>>a; if (t == 1) cin>>b; tp p = make_tuple(a,t,b); v[i] = p; } // sort(rng(v)); vl ans; const ll mxx = (ll)1e8 + 1; DynamicLiChaoTree<ll,0,mxx,LINF> lt; // int cnt = 0; fore(y , v){ // show(cnt++); int type = get<1>(y); ll s = get<0>(y); ll t = get<2>(y); // show3(type,s,t); if (type == 1){ lt.add_line(-(s+t)*a,s*t*a); }else{ // show(s); ll mx = -lt.query(s); ans.pb(max(0ll,mx - s*s*a)); } } outv; return; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int t = 1; //cin>>t; rep(i,t){ solve(); } return 0; }