結果

問題 No.2462 七人カノン
ユーザー dyktr_06dyktr_06
提出日時 2023-09-08 21:33:34
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 101 ms / 2,000 ms
コード長 6,161 bytes
コンパイル時間 6,422 ms
コンパイル使用メモリ 301,288 KB
実行使用メモリ 11,112 KB
最終ジャッジ日時 2023-09-08 21:33:50
合計ジャッジ時間 16,578 ms
ジャッジサーバーID
(参考情報)
judge15 / judge14
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 3 ms
5,404 KB
testcase_01 AC 5 ms
5,472 KB
testcase_02 AC 3 ms
5,400 KB
testcase_03 AC 7 ms
5,412 KB
testcase_04 AC 7 ms
5,512 KB
testcase_05 AC 7 ms
5,464 KB
testcase_06 AC 7 ms
5,516 KB
testcase_07 AC 7 ms
5,528 KB
testcase_08 AC 7 ms
5,536 KB
testcase_09 AC 7 ms
5,436 KB
testcase_10 AC 8 ms
5,460 KB
testcase_11 AC 7 ms
5,408 KB
testcase_12 AC 7 ms
5,416 KB
testcase_13 AC 84 ms
10,208 KB
testcase_14 AC 96 ms
10,788 KB
testcase_15 AC 87 ms
10,284 KB
testcase_16 AC 99 ms
11,040 KB
testcase_17 AC 99 ms
11,060 KB
testcase_18 AC 63 ms
8,572 KB
testcase_19 AC 77 ms
8,632 KB
testcase_20 AC 91 ms
10,956 KB
testcase_21 AC 92 ms
11,112 KB
testcase_22 AC 94 ms
10,956 KB
testcase_23 AC 91 ms
10,980 KB
testcase_24 AC 84 ms
9,624 KB
testcase_25 AC 101 ms
10,952 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")

#include <bits/stdc++.h>
#include <atcoder/all>

using namespace std;
using namespace atcoder;

#define overload4(_1, _2, _3, _4, name, ...) name
#define rep1(n) for(int i = 0; i < (int)(n); ++i)
#define rep2(i, n) for(int i = 0; i < (int)(n); ++i)
#define rep3(i, a, b) for(int i = (a); i < (int)(b); ++i)
#define rep4(i, a, b, c) for(int i = (a); i < (int)(b); i += (c))
#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)

#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; --i)
#define ALL(a) a.begin(), a.end()
#define Sort(a) sort(a.begin(), a.end())
#define RSort(a) sort(a.rbegin(), a.rend())

typedef long long int ll;
typedef unsigned long long ul;
typedef long double ld;
typedef vector<int> vi;
typedef vector<long long> vll;
typedef vector<char> vc;
typedef vector<string> vst;
typedef vector<double> vd;
typedef vector<long double> vld;
typedef pair<long long, long long> P;

template<class T> long long sum(const T& a){ return accumulate(a.begin(), a.end(), 0LL); }
template<class T> auto min(const T& a){ return *min_element(a.begin(), a.end()); }
template<class T> auto max(const T& a){ return *max_element(a.begin(), a.end()); }

const long long MINF = 0x7fffffffffff;
const long long INF = 0x1fffffffffffffff;
const long long MOD = 998244353;
const long double EPS = 1e-9;
const long double PI = acos(-1);
 
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

template<typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p){ is >> p.first >> p.second; return is; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){ os << "(" << p.first << ", " << p.second << ")"; return os; }
template<typename T> istream &operator>>(istream &is, vector<T> &v){ for(T &in : v) is >> in; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &v){ for(int i = 0; i < (int) v.size(); ++i){ os << v[i] << (i + 1 != (int) v.size() ? " " : ""); } return os; }
template <typename T, typename S> ostream &operator<<(ostream &os, const map<T, S> &mp){ for(auto &[key, val] : mp){ os << key << ":" << val << " "; } return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, queue<T> q){ while(q.size()){ os << q.front() << " "; q.pop(); } return os; }
template <typename T> ostream &operator<<(ostream &os, deque<T> q){ while(q.size()){ os << q.front() << " "; q.pop_front(); } return os; }
template <typename T> ostream &operator<<(ostream &os, stack<T> st){ while(st.size()){ os << st.top() << " "; st.pop(); } return os; }
template <class T, class Container, class Compare> ostream &operator<<(ostream &os, priority_queue<T, Container, Compare> pq){ while(pq.size()){ os << pq.top() << " "; pq.pop(); } return os; }

template<class T, class U> inline T vin(T& vec, U n) { vec.resize(n); for(int i = 0; i < (int) n; ++i) cin >> vec[i]; return vec; }
template<class T> inline void vout(T vec, string s = "\n"){ for(auto x : vec) cout << x << s; }
template<class... T> void in(T&... a){ (cin >> ... >> a); }
void out(){ cout << '\n'; }
template<class T, class... Ts> void out(const T& a, const Ts&... b){ cout << a; (cout << ... << (cout << ' ', b)); cout << '\n'; }
template<class T, class U> void inGraph(vector<vector<T>>& G, U n, U m, bool directed = false){ G.resize(n); for(int i = 0; i < m; ++i){ int a, b; cin >> a >> b; a--, b--; G[a].push_back(b); if(!directed) G[b].push_back(a); } }

template <typename T>
struct BinaryIndexedTree{
    int N;
    vector<T> BIT;
    BinaryIndexedTree(const int &N): N(N), BIT(N + 1, 0){
    }

    T get(int i){
        return sum(i + 1) - sum(i);
    }

    void add(int i, T x){
        i++;
        while(i <= N){
            BIT[i] += x;
            i += i & -i;
        }
    }

    T sum(int i) const {
        T ans = 0;
        while(i > 0){
            ans += BIT[i];
            i -= i & -i;
        }
        return ans;
    }

    T sum(int L, int R) const {
        return sum(R) - sum(L);
    }

    int lower_bound(T x) const {
        if(x <= 0){
            return 0;
        }else{
            int v = 0, r = 1;
            while(r < N) r = r << 1;
            for(int len = r; len > 0; len = len >> 1){
                if(v + len < N && BIT[v + len] < x){
                    x -= BIT[v + len];
                    v += len;
                }
            }
            return v;
        }
    }

    int upper_bound(T x) const {
        if(x < 0){
            return 0;
        }else{
            int v = 0, r = 1;
            while(r <= N) r = r << 1;
            for(int len = r; len > 0; len = len >> 1){
                if(v + len <= N && BIT[v + len] <= x){
                    x -= BIT[v + len];
                    v += len;
                }
            }
            return v;
        }
    }

    T operator [](int i) const {
        return sum(i, i + 1);
    }
};

ll n, q;

void input(){
    in(n, q);
}

void solve(){
    ll mx = 100000;
    vll imos(mx + 1);
    vll I(q), s(q), t(q);
    rep(i, q){
        in(I[i], s[i], t[i]); I[i]--;
        imos[s[i]]++;
        imos[t[i]]--; 
    }
    rep(i, mx) imos[i + 1] += imos[i];
    BinaryIndexedTree<ld> BIT(mx + 1);
    rep(i, mx + 1){
        if(imos[i] == 0) continue;
        BIT.add(i, (ld) 1 / imos[i]);
    }
    vld ans(n);
    rep(i, q){
        ans[I[i]] += BIT.sum(s[i], t[i]);
    }
    vout(ans, "\n");
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout << fixed << setprecision(20);
    
    input();
    solve();
}
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