結果

問題 No.2462 七人カノン
ユーザー null
提出日時 2023-09-08 21:40:57
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 170 ms / 2,000 ms
コード長 6,913 bytes
コンパイル時間 8,441 ms
コンパイル使用メモリ 450,172 KB
実行使用メモリ 13,824 KB
最終ジャッジ日時 2024-06-26 14:35:37
合計ジャッジ時間 21,712 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 23
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function 'void scans(std::string&)':
main.cpp:78:18: warning: NULL used in arithmetic [-Wpointer-arith]
   78 |         if (c == NULL)return;
      |                  ^~~~

ソースコード

diff #
プレゼンテーションモードにする

/*
!
Be accepted!
_ 
。・ω・。)━☆*
      +.
    °+ *´¨)
  .· ´¸.·*´¨) ¸.·*¨)
          (¸.·´ (¸.·'* ☆
*/
#include <cstdio>
#include <algorithm>
#include <string>
#include <cmath>
#include <cstring>
#include <vector>
#include <numeric>
#include <iostream>
#include <random>
#include <map>
#include <unordered_map>
#include <queue>
#include <regex>
#include <functional>
#include <complex>
#include <list>
#include <cassert>
#include <iomanip>
#include <set>
#include <stack>
#include <bitset>
#include <array>
#include <chrono>
#include <limits>
//#pragma GCC target("arch=skylake-avx512")
//#pragma GCC target("avx2")
//#pragma GCC optimize("O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse4")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#define repeat(i, n, m) for(int i = n; i < (m); ++i)
#define rep(i, n) for(int i = 0; i < (n); ++i)
#define printynl(a) printf(a ? "yes\n" : "no\n")
#define printyn(a) printf(a ? "Yes\n" : "No\n")
#define printYN(a) printf(a ? "YES\n" : "NO\n")
#define printim(a) printf(a ? "possible\n" : "imposible\n")
#define printdb(a) printf("%.50lf\n", a)
#define printLdb(a) printf("%.50Lf\n", a)
#define printdbd(a) printf("%.16lf\n", a)
#define prints(s) printf("%s\n", s.c_str())
#define all(x) (x).begin(), (x).end()
#define deg_to_rad(deg) (((deg)/360.0L)*2.0L*PI)
#define rad_to_deg(rad) (((rad)/2.0L/PI)*360.0L)
#define Please return
#define AC 0
#define manhattan_dist(a, b, c, d) (abs(a - c) + abs(b - d))
using ll = long long;
using ull = unsigned long long;
constexpr int INF = 1073741823;
constexpr int MINF = -1073741823;
constexpr ll LINF = ll(4661686018427387903);
constexpr ll MOD = 1e9 + 7;
constexpr ll mod = 998244353;
constexpr long double eps = 1e-14;
const long double PI = acosl(-1.0L);
using namespace std;
void scans(string& str) {
char c;
str = "";
scanf("%c", &c);
if (c == NULL)return;
else if (c == '\n')scanf("%c", &c);
while (c != '\n' && c != -1 && c != ' ') {
str += c;
scanf("%c", &c);
}
}
void scanc(char& str) {
char c;
scanf("%c", &c);
if (c == -1)return;
while (c == '\n') {
scanf("%c", &c);
}
str = c;
}
double acot(double x) {
return PI / 2 - atan(x);
}
ll LSB(ll n) { return (n & (-n)); }
template<typename T>
inline T chmin(T& a, const T& b) {
if (a > b)a = b;
return a;
}
template<typename T>
inline T chmax(T& a, const T& b) {
if (a < b)a = b;
return a;
}
//cpp_int
#if __has_include(<boost/multiprecision/cpp_int.hpp>)
#include <boost/multiprecision/cpp_int.hpp>
#include <boost/multiprecision/cpp_dec_float.hpp>
using namespace boost::multiprecision;
#else
using cpp_int = ll;
#endif
//atcoder library
#if __has_include(<atcoder/all>)
#include <atcoder/all>
//using namespace atcoder;
#endif
/*
random_device seed_gen;
mt19937 engine(seed_gen());
uniform_int_distribution dist(1, 100);
*/
/*----------------------------------------------------------------------------------*/
/*
* @title segment-tree
* @docs kyopro/docs/segtree.md
*/
///0-indexed//(, )
template<typename T, typename F>
struct segtree {
//
vector<T> seg;
//1/2
int siz;
//
const T e;
////
//using F = function<T(T, T)>;
//
const F f;
//n , a () segtree
segtree(int n, const T a, const F f) : e(a), f(f) {
siz = 1;
while (siz < n)siz <<= 1;
seg.assign(2 * siz - 1, e);
--siz;
}
//k (0-indexed) t
void set(int k, const T& t) {
seg[k + siz] = t;
}
//f
void build() {
for (int i = siz - 1; i >= 0; --i) seg[i] = f(seg[i * 2 + 1], seg[i * 2 + 2]);
}
//i
T operator[](const int i) {
return seg[i + siz];
}
//k a
void update(int k, T a) {
k += siz;
//
seg[k] = a;
while (k > 0) {
k = ((k - 1) >> 1);
seg[k] = f(seg[k * 2 + 1], seg[k * 2 + 2]);
}
}
//[a, b) f
T query(int a, int b) {
T l = e, r = e;
for (a += siz, b += siz; a < b; a >>= 1, b >>= 1) {
if (!(a & 1))l = f(l, seg[a++]);
if (!(b & 1))r = f(seg[--b], r);
}
return f(l, r);
}
//[start, end) [l, r) 調 k check true left, false right f
template<typename C, typename FT>
int find(const int start, const int end, int l, int r, int k, const C check, T& checknum, const bool b, const FT revf) {
//cerr << checknum << '\n';
//
//cerr << k << ',' << checknum << '\n';
if (start <= l && r <= end && !check(seg[k], checknum)) {
checknum = revf(checknum, seg[k]);
return -1;
}
if ((r <= start || l >= end)) {
return -1;
}
//
if (k >= siz) {
return k - siz;
}
int res;
if (b) {
//調
res = find< C, FT >(start, end, l, ((l + r) >> 1), (k << 1) + 1, check, checknum, b, revf);
//
if (res != -1)return (res);
return find< C, FT >(start, end, ((l + r) >> 1), r, (k << 1) + 2, check, checknum, b, revf);
}
else {
//調
res = find< C, FT >(start, end, ((l + r) >> 1), r, (k << 1) + 2, check, checknum, b, revf);
//
if (res != -1)return (res);
return find< C, FT >(start, end, l, ((l + r) >> 1), (k << 1) + 1, check, checknum, b, revf);
}
}
template<typename C, typename FT>
int find_left(int start, int end, const C check, T checknum, FT revf) {
return find< C, FT >(start, end, 0, siz + 1, 0, check, checknum, true, revf);
}
template<typename C, typename FT>
int find_right(int start, int end, const C check, T checknum, FT revf) {
return find< C, FT >(start, end, 0, siz + 1, 0, check, checknum, false, revf);
}
};
template<typename T, typename F>
segtree<T, F> get_segtree(int n, const T& e, const F& f) {
return { n, e, f };
}
int main() {
int n, q;
scanf("%d%d", &n, &q);
vector<int> imos(100001);
vector<int> b(100000);
vector<vector<pair<int, int>>> a(n);
rep(i, q) {
int x, y, z;
scanf("%d%d%d", &x, &y, &z);
--x;
++imos[y];
--imos[z];
a[x].push_back({ y, z });
}
int cur = 0;
rep(i, 100000) {
cur += imos[i];
b[i] = cur;
}
auto seg = get_segtree(100000, 0.0L, plus<long double>());
rep(i, 100000)if(b[i] != 0) seg.set(i, 1.0L / b[i]);
seg.build();
rep(i, n) {
long double ans = 0;
for (const auto& [l, r] : a[i])ans += seg.query(l, r);
printLdb(ans);
}
Please AC;
}
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