結果

問題 No.2495 Three Sets
ユーザー umimel
提出日時 2023-10-06 22:11:09
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 5,250 bytes
コンパイル時間 1,884 ms
コンパイル使用メモリ 173,720 KB
実行使用メモリ 6,948 KB
最終ジャッジ日時 2024-07-26 16:22:15
合計ジャッジ時間 3,200 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 12 WA * 6
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pll = pair<ll, ll>;
#define drep(i, cc, n) for (ll i = (cc); i <= (n); ++i)
#define rep(i, n) drep(i, 0, n - 1)
#define all(a) (a).begin(), (a).end()
#define pb push_back
#define fi first
#define se second
mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count());
const ll MOD1000000007 = 1000000007;
const ll MOD998244353 = 998244353;
const ll MOD[3] = {999727999, 1070777777, 1000000007};
const ll LINF = 1LL << 60;
const int IINF = (1 << 30) - 1;
template<typename T> struct Edge{
int to; T w;
Edge(int to_, T w_=1){
to = to_;
w=w_;
}
};
template<typename T> using Tree = vector<vector<Edge<T>>>;
template<typename T> using Graph = vector<vector<Edge<T>>>;
/* & for Dinic */
template<typename T> struct REdge{
int to;
T cap;
T cost;
int rev;
REdge(int to_, T cap_, T cost_=1){
to = to_;
cap = cap_;
cost = cost_;
}
REdge(int to_, T cap_, T cost_, int rev_){
to = to_;
cap = cap_;
cost = cost_;
rev = rev_;
}
};
/* for Dinic */
template<typename T> using RGraph = vector<vector<REdge<T>>>;
struct UnionFind{
vector<ll> parent;
vector<ll> sizes;
UnionFind(ll N) : parent(N), sizes(N, 1){
rep(i, N) parent[i] = i;
}
ll root(ll x){
if (parent[x] == x) return x;
return parent[x] = root(parent[x]);
}
void unite(ll x, ll y){
ll rx = root(x);
ll ry = root(y);
if (rx == ry) return;
if (sizes[rx] < sizes[ry]) swap(rx, ry);
sizes[rx] += sizes[ry];
parent[ry] = rx;
}
bool same(ll x, ll y){
ll rx = root(x);
ll ry = root(y);
return rx == ry;
}
ll size(ll x){
return sizes[root(x)];
}
};
template<long long mod>
class modint{
long long x;
public:
modint(long long x=0) : x((x%mod+mod)%mod) {}
modint operator-() const {
return modint(-x);
}
bool operator==(const modint& a){
if(x == a) return true;
else return false;
}
bool operator==(long long a){
if(x == a) return true;
else return false;
}
bool operator!=(const modint& a){
if(x != a) return true;
else return false;
}
bool operator!=(long long a){
if(x != a) return true;
else return false;
}
modint& operator+=(const modint& a) {
if ((x += a.x) >= mod) x -= mod;
return *this;
}
modint& operator-=(const modint& a) {
if ((x += mod-a.x) >= mod) x -= mod;
return *this;
}
modint& operator*=(const modint& a) {
(x *= a.x) %= mod;
return *this;
}
modint operator+(const modint& a) const {
modint res(*this);
return res+=a;
}
modint operator-(const modint& a) const {
modint res(*this);
return res-=a;
}
modint operator*(const modint& a) const {
modint res(*this);
return res*=a;
}
modint pow(long long t) const {
if (!t) return 1;
modint a = pow(t>>1);
a *= a;
if (t&1) a *= *this;
return a;
}
// for prime mod
modint inv() const {
return pow(mod-2);
}
modint& operator/=(const modint& a) {
return (*this) *= a.inv();
}
modint operator/(const modint& a) const {
modint res(*this);
return res/=a;
}
friend std::istream& operator>>(std::istream& is, modint& m) noexcept {
is >> m.x;
m.x %= mod;
if (m.x < 0) m.x += mod;
return is;
}
friend ostream& operator<<(ostream& os, const modint& m){
os << m.x;
return os;
}
};
using mint = modint<MOD998244353>;
int main(){
cin.tie(nullptr);
ios::sync_with_stdio(false);
ll NA, NB, NC; cin >> NA >> NB >> NC;
vector<ll> A(NA), B(NB), C(NC);
rep(i, NA) cin >> A[i];
rep(j, NB) cin >> B[j];
rep(k, NC) cin >> C[k];
sort(all(A), greater<ll>());
sort(all(B), greater<ll>());
sort(all(C), greater<ll>());
ll sumA = 0, sumB = 0, sumC = 0;
ll i = 0, j = 0, k = 0;
while(A[i]>=0){
sumA+=A[i];
i++;
if(i==NA){
break;
}
}
while(B[j]>=0){
sumB+=B[j];
j++;
if(j==NB){
break;
}
}
while(C[k]>=0){
sumC+=C[k];
k++;
if(k==NC){
break;
}
}
i--; j--; k--;
while(true){
ll dA = 0, dB = 0, dC = 0;
if(i<NA-1){
dA = A[i+1]*(j+1) + sumC;
}
if(j<NB-1){
dB = B[j+1]*(k+1) + sumA;
}
if(k<NC-1){
dC = C[k+1]*(i+1) + sumB;
}
//0
if(dA<=0 && dB<=0 && dC<=0) break;
if(dB<=dA && dC<=dA){ //dA
i++;
sumA+=A[i];
}else if(dA<=dB && dC<=dB){ //dB
j++;
sumB+=B[j];
}else{
k++;
sumC+=C[k];
}
}
cout << sumA*(j+1) + sumB*(k+1) + sumC*(i+1) << endl;
}
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