結果

問題 No.2496 LCM between Permutations
ユーザー TKTYI
提出日時 2023-10-06 22:25:49
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 129 ms / 2,000 ms
コード長 4,097 bytes
コンパイル時間 4,413 ms
コンパイル使用メモリ 266,716 KB
最終ジャッジ日時 2025-02-17 05:17:05
ジャッジサーバーID
(参考情報)
judge5 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 28
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
using namespace std;
using namespace atcoder;
typedef long long int ll;
typedef long double ld;
typedef vector<ll> vi;
typedef vector<vi> vvi;
typedef vector<vvi> vvvi;
typedef vector<vvvi> vvvvi;
typedef vector<bool> vb;
typedef vector<vb> vvb;
typedef vector<vvb> vvvb;
typedef vector<vvvb> vvvvb;
typedef pair<ll,ll> pi;
typedef pair<ll,pi> ppi;
typedef pair<ll,ppi> pppi;
typedef pair<ll,pppi> ppppi;
#define FOR(i,l,r) for(ll i=l;i<r;i++)
#define REP(i,n) FOR(i,0,n)
#define RFOR(i,l,r) for(ll i=r-1;i>=l;i--)
#define RREP(i,n) RFOR(i,0,n)
#define ALL(x) x.begin(),x.end()
#define F first
#define S second
#define BS(A,x) binary_search(ALL(A),x)
#define LB(A,x) (ll)(lower_bound(ALL(A),x)-A.begin())
#define UB(A,x) (ll)(upper_bound(ALL(A),x)-A.begin())
#define COU(A,x) (UB(A,x)-LB(A,x))
#define sz(c) ((ll)(c).size())
/*
#include<boost/multiprecision/cpp_int.hpp>
namespace mp=boost::multiprecision;
using Bint=mp::cpp_int;
*/
template<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;
template<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.F<<" "<<p.S;return os;}
template<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.F>>p.S;return is;}
template<typename T>ostream&operator<<(ostream&os,vector<T>&v){REP(i,sz(v))os<<v[i]<<(i+1!=sz(v)?" ":"");return os;}
template<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}
template<class T>bool chmax(T&a,T b){if(a<b){a=b;return 1;}return 0;}
template<class T>bool chmin(T&a,T b){if(b<a){a=b;return 1;}return 0;}
ld dist(ld x1,ld y1,ld x2,ld y2){return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));}
vi fast_mod_convolution(vi&a,vi&b,ll mod){
const ll m1=167772161,m2=469762049,m3=1224736769;
const ll m1_inv_m2=inv_mod(m1,m2);
const ll m12_inv_m3=inv_mod(m1*m2,m3);
const ll m12_mod=m1*m2%mod;
auto x=convolution<m1>(a,b);
auto y=convolution<m2>(a,b);
auto z=convolution<m3>(a,b);
vector<ll>ret(sz(a)+sz(b)-1);
REP(i,sz(ret)){
ll v1=(y[i]-x[i])*m1_inv_m2%m2;if(v1<0)v1+=m2;
ll v2=(z[i]-(x[i]+m1*v1)%m3)*m12_inv_m3%m3;if(v2<0)v2+=m3;
ret[i]=(x[i]+m1*v1+m12_mod*v2)%mod;
}
return ret;
}
const ld EPS=1e-8;
//*
using mint=modint998244353;
const ll mod=998244353;
//*/
/*
using mint=modint1000000007;
const ll mod=1000000007;
//*/
//using mint=modint;
//*
typedef vector<mint> vm;
typedef vector<vm> vvm;
typedef vector<vvm> vvvm;
typedef vector<vvvm> vvvvm;
ostream&operator<<(ostream&os,mint&a){os<<a.val();return os;}
//*/
const vi A={5,1,2,4,3,6,7,8,9,10};
const vi B={1,2,3,4,5,6,7,8,9,10};
ll query(ll i,ll j){
cout<<"? "<<i+1<<" "<<j+1<<endl;
ll res;cin>>res;
//res=A[i]*B[j]/__gcd(A[i],B[j]);
return res;
}
int main(){
vector<bool>prime(2e6,1);
prime[0]=prime[1]=0;
REP(i,2e6)if(prime[i]){
ll j=2*i;
while(j<2e6){
prime[j]=0;j+=i;
}
}
ll N;cin>>N;
if(N==1){cout<<"! 1 1"<<endl;return 0;}
vi X(N);
REP(i,N)X[i]=query(0,i);
ll m=1e18;
REP(i,N)chmin(m,X[i]);
if(m==1){
vi B=X,A(N);
ll t=0;
while(B[t]!=1)t++;
REP(i,N)A[i]=query(i,t);
cout<<"! "<<A<<" "<<B<<endl;
return 0;
}
if(prime[m]&&2*m>N){
vi A(N);
REP(i,N)A[i]=X[i]/m;
vi C,Y(N);
REP(i,N)if(A[i]==1)C.emplace_back(i);
REP(i,N)Y[i]=query(i,C[0]);
auto Z=Y;
sort(ALL(Z));
bool ok=1;
REP(i,N)if(Z[i]!=i+1)ok=0;
ll one;
if(ok)A[C[1]]=m,one=C[0];
else A[C[0]]=m,one=C[1];
vi B(N);
REP(i,N)B[i]=query(i,one);
cout<<"! "<<B<<" "<<A<<endl;
return 0;
}
vi Y(N);
REP(i,N)Y[i]=X[i]/m;
sort(ALL(Y));
ll p=0;
REP(i,N)if(COU(Y,Y[i])==1&&prime[Y[i]])chmax(p,Y[i]);
ll t=0;
while(X[t]!=m*p)t++;
vi Z(N);Z[0]=m*p;
FOR(i,1,N)Z[i]=query(i,t);
vi A(N);
REP(i,N)A[i]=Z[i]/p;
vi C;
REP(i,N)if(A[i]==1)C.emplace_back(i);
vi W(N);
REP(i,N){
if(i==t)W[i]=p;
else W[i]=query(C[0],i);
}
vi B(N);
bool one=1;
REP(i,N){
if(i==t)B[i]=p;
else{B[i]=W[i];if(B[i]%p==0)B[i]/=p,one=0;}
}
if(one)A[C[1]]=p;
else A[C[0]]=p;
cout<<"! "<<A<<" "<<B<<endl;
return 0;
}
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