結果
問題 | No.2496 LCM between Permutations |
ユーザー |
|
提出日時 | 2023-10-07 00:00:05 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
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実行時間 | 236 ms / 2,000 ms |
コード長 | 5,362 bytes |
コンパイル時間 | 339 ms |
コンパイル使用メモリ | 82,496 KB |
実行使用メモリ | 95,052 KB |
平均クエリ数 | 928.07 |
最終ジャッジ日時 | 2024-07-26 17:28:29 |
合計ジャッジ時間 | 6,048 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 28 |
ソースコード
import sys, randominput = lambda : sys.stdin.readline().rstrip()write = lambda x: sys.stdout.write(x+"\n"); writef = lambda x: print("{:.12f}".format(x))debug = lambda x: sys.stderr.write(x+"\n")YES="Yes"; NO="No"; pans = lambda v: print(YES if v else NO); INF=10**18LI = lambda : list(map(int, input().split())); II=lambda : int(input()); SI=lambda : [ord(c)-ord("a") for c in input()]def debug(_l_):for s in _l_.split():print(f"{s}={eval(s)}", end=" ")print()def dlist(*l, fill=0):if len(l)==1:return [fill]*l[0]ll = l[1:]return [dlist(*ll, fill=fill) for _ in range(l[0])]def hurui(n):"""線形篩pl: 素数のリストmpf: iを割り切る最小の素因数"""pl = []mpf = [None]*(n+1)for d in range(2,n+1):if mpf[d] is None:mpf[d] = dpl.append(d)for p in pl:if p*d>n or p>mpf[d]:breakmpf[p*d] = preturn pl, mpffrom collections import defaultdictdef factor(num):d = defaultdict(int)if num==1:d.update({1:1})return dwhile num>1:d[mpf[num]] += 1num //= mpf[num]return ddef fs(num):f = factor(num)ans = [1]for k,v in f.items():tmp = []for i in range(len(ans)):val = 1for _ in range(v):val *= kans.append(ans[i]*val)return anspl, mpf = hurui(10000)prime = set(pl)# 標準出力による質問 interactiveTEST = 0import sysdef _q(i,j):print("?", i+1, j+1)sys.stdout.flush()val = II()return valdef answer(v):print(f"! {v}")sys.stdout.flush()n = int(input())NUM = 100 if TEST else 1from math import gcdfor _ in range(NUM):if TEST:import random_a = list(range(1,n+1))_b = list(range(1,n+1))random.shuffle(_a)random.shuffle(_b)n = 6_a = list(map(int, "5 4 3 6 1 2".split()))_b = list(map(int, "5 4 1 6 3 2".split()))_c = 0def _q(i,j):global _c_c += 1return _a[i]*_b[j]//gcd(_a[i], _b[j])if n<=4:from itertools import permutations as psdic = {}for a in ps(range(1,n+1)):for b in ps(range(1,n+1)):k = []for i in range(n-1):for j in range(n):k.append(a[i]*b[j]//gcd(a[i],b[j]))dic[tuple(k)] = (a,b)tmp = []for i in range(n-1):res = [_q(i,j) for j in range(n)]tmp.extend(res)resa,resb = dic[tuple(tmp)]else:vals = [_q(0,j) for j in range(n)]m = min(vals)p1 = p2 = Nonej1 = j2 = Noneresa = [0]*nresb = [0]*nif m==1:resb = vals[:]for j in range(n):if resb[j]==1:for i in range(n):resa[i] = _q(i,j)breakelif n==6 and m in prime and 2*m>n:resb = [v//m for v in vals]j1,j2 = [j for j in range(n) if resb[j]==1]for i in range(n):val = _q(i,j1)resa[i] = valif len(set(resa))==n:resb[j2] = melse:resb[j1] = mresb[j2] = 1for i in range(n):resa[i] = _q(i,j2)else:js = []ps = []for j in range(n):if (vals[j]//m in prime and ((vals[j]//m)%m!=0)):js.append(j)ps.append(vals[j]//m)resb[j] = vals[j]//m# elif (2*m>n and vals[j]==m):# js.append(j)# ps.append(m)# resb[j] = mmp = max(ps)for i in range(len(ps)):if ps[i]==mp:j1 = js[i]p1 = ps[i]breakvals2 = [_q(i,j1) for i in range(n)]i0 = i1 = Nonefor i in range(n):if vals2[i]==p1:if i0 is None:i0 = ielif i1 is None:i1 = ielse:resa[i] = vals2[i]//p1vals3 = [_q(i0,j) for j in range(n)]if len(set(vals3))==n:resb = vals3[:]# i0 は 1resa[i0] = 1resa[i1] = p1else:for j in range(n):if j==j1:continueresb[j] = vals3[j]//p1# i0 は p1, i1 は 1resa[i1] = 1resa[i0] = p1ind = i1js = [j for j in range(n) if resb[j]==p1]for j in js:if j!=j1:resb[j] = 1breakassert len(set(resa))==n and min(resa)==1 and max(resa)==nassert len(set(resb))==n and min(resb)==1 and max(resb)==nif TEST:assert resa==_aassert resb==_bprint("!", *resa, *resb)