結果

問題 No.2496 LCM between Permutations
ユーザー dyktr_06dyktr_06
提出日時 2023-10-07 03:29:51
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 114 ms / 2,000 ms
コード長 7,093 bytes
コンパイル時間 5,803 ms
コンパイル使用メモリ 301,412 KB
実行使用メモリ 25,476 KB
平均クエリ数 952.76
最終ジャッジ日時 2024-07-26 17:41:38
合計ジャッジ時間 8,856 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 24 ms
24,940 KB
testcase_01 AC 22 ms
25,220 KB
testcase_02 AC 22 ms
25,476 KB
testcase_03 AC 23 ms
24,964 KB
testcase_04 AC 22 ms
24,836 KB
testcase_05 AC 23 ms
25,220 KB
testcase_06 AC 21 ms
25,460 KB
testcase_07 AC 21 ms
25,220 KB
testcase_08 AC 21 ms
24,836 KB
testcase_09 AC 21 ms
24,580 KB
testcase_10 AC 20 ms
25,220 KB
testcase_11 AC 21 ms
25,220 KB
testcase_12 AC 20 ms
25,220 KB
testcase_13 AC 20 ms
25,208 KB
testcase_14 AC 21 ms
24,836 KB
testcase_15 AC 25 ms
25,196 KB
testcase_16 AC 27 ms
25,196 KB
testcase_17 AC 34 ms
24,556 KB
testcase_18 AC 96 ms
24,836 KB
testcase_19 AC 75 ms
25,476 KB
testcase_20 AC 89 ms
25,220 KB
testcase_21 AC 76 ms
24,836 KB
testcase_22 AC 78 ms
24,580 KB
testcase_23 AC 114 ms
25,220 KB
testcase_24 AC 88 ms
24,836 KB
testcase_25 AC 107 ms
24,836 KB
testcase_26 AC 105 ms
25,196 KB
testcase_27 AC 107 ms
25,196 KB
testcase_28 AC 105 ms
24,812 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")

#include <bits/stdc++.h>
#include <atcoder/all>

using namespace std;
using namespace atcoder;

#define overload4(_1, _2, _3, _4, name, ...) name
#define rep1(n) for(int i = 0; i < (int)(n); ++i)
#define rep2(i, n) for(int i = 0; i < (int)(n); ++i)
#define rep3(i, a, b) for(int i = (a); i < (int)(b); ++i)
#define rep4(i, a, b, c) for(int i = (a); i < (int)(b); i += (c))
#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)

#define rrep(i,n) for(int i = (int)(n) - 1; i >= 0; --i)
#define ALL(a) a.begin(), a.end()
#define Sort(a) sort(a.begin(), a.end())
#define RSort(a) sort(a.rbegin(), a.rend())

typedef long long int ll;
typedef unsigned long long ul;
typedef long double ld;
typedef vector<int> vi;
typedef vector<long long> vll;
typedef vector<char> vc;
typedef vector<string> vst;
typedef vector<double> vd;
typedef vector<long double> vld;
typedef pair<long long, long long> P;

template<class T> long long sum(const T& a){ return accumulate(a.begin(), a.end(), 0LL); }
template<class T> auto min(const T& a){ return *min_element(a.begin(), a.end()); }
template<class T> auto max(const T& a){ return *max_element(a.begin(), a.end()); }

const long long MINF = 0x7fffffffffff;
const long long INF = 0x1fffffffffffffff;
const long long MOD = 998244353;
const long double EPS = 1e-9;
const long double PI = acos(-1);
 
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

template<typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p){ is >> p.first >> p.second; return is; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){ os << "(" << p.first << ", " << p.second << ")"; return os; }
template<typename T> istream &operator>>(istream &is, vector<T> &v){ for(T &in : v) is >> in; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &v){ for(int i = 0; i < (int) v.size(); ++i){ os << v[i] << (i + 1 != (int) v.size() ? " " : ""); } return os; }
template <typename T, typename S> ostream &operator<<(ostream &os, const map<T, S> &mp){ for(auto &[key, val] : mp){ os << key << ":" << val << " "; } return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &st){ auto itr = st.begin(); for(int i = 0; i < (int)st.size(); ++i){ os << *itr << (i + 1 != (int)st.size() ? " " : ""); itr++; } return os; }
template <typename T> ostream &operator<<(ostream &os, queue<T> q){ while(q.size()){ os << q.front() << " "; q.pop(); } return os; }
template <typename T> ostream &operator<<(ostream &os, deque<T> q){ while(q.size()){ os << q.front() << " "; q.pop_front(); } return os; }
template <typename T> ostream &operator<<(ostream &os, stack<T> st){ while(st.size()){ os << st.top() << " "; st.pop(); } return os; }
template <class T, class Container, class Compare> ostream &operator<<(ostream &os, priority_queue<T, Container, Compare> pq){ while(pq.size()){ os << pq.top() << " "; pq.pop(); } return os; }

template<class T, class U> inline T vin(T& vec, U n) { vec.resize(n); for(int i = 0; i < (int) n; ++i) cin >> vec[i]; return vec; }
template<class T> inline void vout(T vec, string s = "\n"){ for(auto x : vec) cout << x << s; }
template<class... T> void in(T&... a){ (cin >> ... >> a); }
void out(){ cout << '\n'; }
template<class T, class... Ts> void out(const T& a, const Ts&... b){ cout << a; (cout << ... << (cout << ' ', b)); cout << '\n'; }
template<class T, class U> void inGraph(vector<vector<T>>& G, U n, U m, bool directed = false){ G.resize(n); for(int i = 0; i < m; ++i){ int a, b; cin >> a >> b; a--, b--; G[a].push_back(b); if(!directed) G[b].push_back(a); } }

namespace prime{
    
    template <typename T>
    bool isPrime(T n){
        switch(n) {
            case 0: // fall-through
            case 1: return false;
            case 2: return true;
        }

        if(n % 2 == 0) return false;

        for(T i = 3; i*i <= n; i += 2){
            if(n % i == 0){
                return false;
            }
        }
        return true;
    }

    template <typename T>
    vector<pair<T, T>> factorize(T n) {
        vector<pair<T, T>> ret;
        for (T i = 2; i * i <= n; i++) {
            if (n % i != 0) continue;
            T tmp = 0;
            while (n % i == 0) {
                tmp++;
                n /= i;
            }
            ret.push_back(make_pair(i, tmp));
        }
        if (n != 1) ret.push_back(make_pair(n, 1));
        return ret;
    }

    template <typename T>
    vector<T> divisor(T n){
        T rt = sqrt(n);
        vector<T> res, resB;
        for(T i = 1; i * i <= n; i++){
            if(n % i == 0){
                res.push_back(i);
                T j = n / i;
                if(j != rt){
                    resB.push_back(j);
                }
            }
        }
        for(int i = (int) resB.size() - 1; i >= 0; i--){
            res.push_back(resB[i]);
        }
        return res;
    }
    
    template <typename T>
    vector<T> sieve(T n){
        vector<T> c(n+1);
        for(int i = 2; i <= n; i++){
            if(c[i] != 0) continue;
            for(int j = i; j <= n; j += i){
                c[j] += 1;
            }
        }
        return c;
    }
}

ll n;

void input(){
    in(n);
}

void solve(){
    if(n == 1){
        cout << "! " << 1 << " " << 1 << endl;
        return;
    }
    auto query = [](ll i, ll j){
        cout << "? " << i << " " << j << endl;
        ll res; in(res);
        return res;
    };
    auto output = [](vll &a, vll &b){
        cout << "! ";
        rep(i, n){
            if(i >= 1) cout << " ";
            cout << a[i];
        }
        cout << " ";
        rep(i, n){
            if(i >= 1) cout << " ";
            cout << b[i];
        }
        cout << endl;
    };
    ll p = 0;
    rep(i, n / 2 + 1, n + 1){
        if(prime::isPrime(i)) p = i;
    }
    ll idx1 = -1, idx2 = -1;
    rep(i, 1, n + 1){
        if(query(i, i) % p == 0){
            if(idx1 == -1){
                idx1 = i;
            }else{
                idx2 = i;
            }
        }
    }
    vll a(n), b(n);
    if(idx2 != -1){
        // idx1 ... a, idx2 ... b
        if(query(idx1, idx2) % p){
            swap(idx1, idx2);
        }
    }else{
        idx2 = idx1;
    }
    a[idx1 - 1] = p;
    b[idx2 - 1] = p;
    rep(i, 1, n + 1){
        if(i == idx1) continue;
        a[i - 1] = query(i, idx2) / p;
    }
    rep(i, 1, n + 1){
        if(i == idx2) continue;
        b[i - 1] = query(idx1, i) / p;
    }
    output(a, b);
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout << fixed << setprecision(20);
    
    input();
    solve();
}
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