結果

問題 No.2495 Three Sets
ユーザー ゆにぽけ
提出日時 2023-10-07 11:05:30
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2,850 ms / 3,000 ms
コード長 5,195 bytes
コンパイル時間 1,495 ms
コンパイル使用メモリ 132,140 KB
最終ジャッジ日時 2025-02-17 06:05:46
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 18
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<iostream>
#include<vector>
#include<algorithm>
#include<cstring>
#include<cassert>
#include<cmath>
#include<ctime>
#include<iomanip>
#include<numeric>
#include<stack>
#include<queue>
#include<map>
#include<unordered_map>
#include<set>
#include<unordered_set>
#include<bitset>
#include<random>
using namespace std;
template<int m> struct modint
{
private:
unsigned int value;
static constexpr int mod() {return m;}
public:
constexpr modint(const long long x = 0) noexcept
{
long long y = x;
if(y < 0 || y >= mod())
{
y %= mod();
if(y < 0) y += mod();
}
value = (unsigned int)y;
}
constexpr unsigned int val() noexcept {return value;}
constexpr modint &operator+=(const modint &other) noexcept
{
value += other.value;
if(value >= mod()) value -= mod();
return *this;
}
constexpr modint &operator-=(const modint &other) noexcept
{
unsigned int x = value;
if(x < other.value) x += mod();
x -= other.value;
value = x;
return *this;
}
constexpr modint &operator*=(const modint &other) noexcept
{
unsigned long long x = value;
x *= other.value;
value = (unsigned int) (x % mod());
return *this;
}
constexpr modint &operator/=(const modint &other) noexcept
{
return *this *= other.inverse();
}
constexpr modint inverse() const noexcept
{
assert(value);
long long a = value,b = mod(),x = 1,y = 0;
while(b)
{
long long q = a/b;
a -= q*b; swap(a,b);
x -= q*y; swap(x,y);
}
return modint(x);
}
constexpr modint power(long long N) const noexcept
{
assert(N >= 0);
modint p = *this,ret = 1;
while(N)
{
if(N & 1) ret *= p;
p *= p;
N >>= 1;
}
return ret;
}
constexpr modint operator+() {return *this;}
constexpr modint operator-() {return modint() - *this;}
constexpr modint &operator++(int) noexcept {return *this += 1;}
constexpr modint &operator--(int) noexcept {return *this -= 1;}
friend modint operator+(const modint& lhs, const modint& rhs) {return modint(lhs) += rhs;}
friend modint operator-(const modint& lhs, const modint& rhs) {return modint(lhs) -= rhs;}
friend modint operator*(const modint& lhs, const modint& rhs) {return modint(lhs) *= rhs;}
friend modint operator/(const modint& lhs, const modint& rhs) {return modint(lhs) /= rhs;}
friend ostream &operator<<(ostream &os,const modint &x) {return os << x.value;}
};
using mint = modint<998244353>;
//using mint = modint<1000000007>;
template<class S>
struct combination
{
vector<S> f,invf;
combination(int N = 0) : f(1,1),invf(1,1)
{
update(N);
}
void update(int N)
{
if((int)f.size() > N) return;
int pi = (int)f.size();
N = max(N,pi*2);
f.resize(N+1),invf.resize(N+1);
for(int i = pi;i <= N;i++) f[i] = f[i-1]*i;
invf[N] = S(1)/f[N];
for(int i = N-1;i >= pi;i--) invf[i] = invf[i+1]*(i+1);
}
S factorial(int N)
{
update(N);
return f[N];
}
S invfactorial(int N)
{
update(N);
return invf[N];
}
S P(int N,int K)
{
assert(0 <= K && K <= N);
update(N);
return f[N]*invf[N-K];
}
S C(int N,int K)
{
assert(0 <= K && K <= N);
update(N);
return f[N]*invf[K]*invf[N-K];
}
S H(int N,int K)
{
if(!N) return K == 0 ? 1:0;
return C(N+K-1,K);
}
};
#include<algorithm>
#include<vector>
#include<cassert>
using namespace std;
struct UnionFind
{
private:
int n;
vector<int> par,siz;
public:
UnionFind(int n) :n(n),par(n,-1),siz(n,1) {}
int root(int u)
{
assert(0 <= u && u < n);
return (par[u] < 0 ? u:par[u] = root(par[u]));
}
bool same(int u,int v)
{
assert(0 <= u && u < n && 0 <= v && v < n);
return root(u) == root(v);
}
bool unite(int u,int v)
{
assert(0 <= u && u < n && 0 <= v && v < n);
u = root(u),v = root(v);
if(u == v) return false;
if(siz[u] < siz[v]) swap(u,v);
siz[u] += siz[v];
par[v] = u;
return true;
}
int size(int u)
{
assert(0 <= u && u < n);
return siz[root(u)];
}
vector<vector<int>> components()
{
vector<vector<int>> ret(n);
for(int u = 0;u < n;u++) ret[root(u)].push_back(u);
ret.erase(remove_if(ret.begin(),ret.end(),[](vector<int> v) { return v.empty();}),ret.end());
return ret;
}
};
int N[3];
vector<int> A[3];
vector<long long> S[3];
int memo[6001];
void solve()
{
for(int i = 0;i < 3;i++) cin >> N[i];
for(int i = 0;i < 3;i++)
{
A[i].resize(N[i]);
for(int j = 0;j < N[i];j++) cin >> A[i][j];
sort(A[i].rbegin(),A[i].rend());
S[i].resize(N[i]+1);
for(int j = 0;j < N[i];j++) S[i][j+1] = S[i][j] + A[i][j];
reverse(A[i].begin(),A[i].end());
}
long long ans = 0;
int ai = 0;
for(int a = -3000;a <= 3000;a++)
{
while(ai < N[0] && A[0][ai] < a) ai++;
int bi = 0;
for(int b = -3000;b <= 3000;b++)
{
if(a == -3000) while(bi < N[1] && A[1][bi] < b) bi++,memo[b+3000] = bi;
else bi = memo[b+3000];
int i = N[0]-ai,j = N[1]-bi;
long long sum = S[0][i]*j;
if(i == 0)
{
int k = N[2];
sum += S[1][j]*k;
}
else
{
auto cit = lower_bound(A[2].begin(),A[2].end(),-S[1][j]/i);
int k = A[2].end()-cit;
sum += S[1][j]*k + S[2][k]*i;
}
ans = max(ans,sum);
}
}
cout << ans << endl;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
int T = 1;
//cin >> T;
while(T--) solve();
}
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