結果
問題 | No.2511 Mountain Sequence |
ユーザー | umimel |
提出日時 | 2023-10-20 23:51:58 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 144 ms / 2,000 ms |
コード長 | 3,246 bytes |
コンパイル時間 | 1,733 ms |
コンパイル使用メモリ | 168,580 KB |
実行使用メモリ | 15,608 KB |
最終ジャッジ日時 | 2024-09-21 00:08:26 |
合計ジャッジ時間 | 7,852 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 141 ms
15,480 KB |
testcase_01 | AC | 141 ms
15,356 KB |
testcase_02 | AC | 141 ms
15,480 KB |
testcase_03 | AC | 141 ms
15,480 KB |
testcase_04 | AC | 141 ms
15,480 KB |
testcase_05 | AC | 141 ms
15,608 KB |
testcase_06 | AC | 142 ms
15,480 KB |
testcase_07 | AC | 143 ms
15,476 KB |
testcase_08 | AC | 142 ms
15,352 KB |
testcase_09 | AC | 141 ms
15,484 KB |
testcase_10 | AC | 141 ms
15,348 KB |
testcase_11 | AC | 142 ms
15,352 KB |
testcase_12 | AC | 141 ms
15,608 KB |
testcase_13 | AC | 142 ms
15,352 KB |
testcase_14 | AC | 142 ms
15,352 KB |
testcase_15 | AC | 141 ms
15,480 KB |
testcase_16 | AC | 143 ms
15,480 KB |
testcase_17 | AC | 141 ms
15,480 KB |
testcase_18 | AC | 142 ms
15,520 KB |
testcase_19 | AC | 142 ms
15,348 KB |
testcase_20 | AC | 142 ms
15,352 KB |
testcase_21 | AC | 142 ms
15,348 KB |
testcase_22 | AC | 141 ms
15,352 KB |
testcase_23 | AC | 142 ms
15,452 KB |
testcase_24 | AC | 141 ms
15,352 KB |
testcase_25 | AC | 141 ms
15,352 KB |
testcase_26 | AC | 141 ms
15,352 KB |
testcase_27 | AC | 141 ms
15,352 KB |
testcase_28 | AC | 141 ms
15,604 KB |
testcase_29 | AC | 144 ms
15,356 KB |
testcase_30 | AC | 141 ms
15,352 KB |
testcase_31 | AC | 141 ms
15,560 KB |
testcase_32 | AC | 142 ms
15,352 KB |
testcase_33 | AC | 141 ms
15,352 KB |
testcase_34 | AC | 142 ms
15,356 KB |
ソースコード
#include<bits/stdc++.h> using namespace std; using ll = long long; using pll = pair<ll, ll>; #define drep(i, cc, n) for (ll i = (cc); i <= (n); ++i) #define rep(i, n) drep(i, 0, n - 1) #define all(a) (a).begin(), (a).end() #define pb push_back #define fi first #define se second mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count()); const ll MOD1000000007 = 1000000007; const ll MOD998244353 = 998244353; const ll MOD[3] = {999727999, 1070777777, 1000000007}; const ll LINF = 1LL << 60LL; const int IINF = (1 << 30) - 1; template<long long mod> class modint{ long long x; public: modint(long long x=0) : x((x%mod+mod)%mod) {} modint operator-() const { return modint(-x); } bool operator==(const modint& a){ if(x == a) return true; else return false; } bool operator==(long long a){ if(x == a) return true; else return false; } bool operator!=(const modint& a){ if(x != a) return true; else return false; } bool operator!=(long long a){ if(x != a) return true; else return false; } modint& operator+=(const modint& a) { if ((x += a.x) >= mod) x -= mod; return *this; } modint& operator-=(const modint& a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } modint& operator*=(const modint& a) { (x *= a.x) %= mod; return *this; } modint operator+(const modint& a) const { modint res(*this); return res+=a; } modint operator-(const modint& a) const { modint res(*this); return res-=a; } modint operator*(const modint& a) const { modint res(*this); return res*=a; } modint pow(long long t) const { if (!t) return 1; modint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod modint inv() const { return pow(mod-2); } modint& operator/=(const modint& a) { return (*this) *= a.inv(); } modint operator/(const modint& a) const { modint res(*this); return res/=a; } friend std::istream& operator>>(std::istream& is, modint& m) noexcept { is >> m.x; m.x %= mod; if (m.x < 0) m.x += mod; return is; } friend ostream& operator<<(ostream& os, const modint& m){ os << m.x; return os; } }; using mint = modint<MOD998244353>; const ll MAX = 510000; mint fac[MAX], finv[MAX], inv[MAX]; void cominit(){ fac[0] = fac[1] = 1; finv[0] = finv[1] = 1; inv[1] = 1; for(ll i=2; i<MAX; i++){ fac[i] = fac[i-1] * i; inv[i] = mint(i).inv(); finv[i] = finv[i-1] * inv[i]; } } mint com(ll n, ll k){ if(n < k) return 0; if(n < 0 || k < 0) return mint(0); return fac[n] * finv[k] * finv[n-k]; } void solve(){ ll n, m; cin >> n >> m; mint ans = 0; for(ll j=1; j<=m; j++){ if(2*(j-1) < n-1) continue; ans += com(2*(j-1), n-1); } cout << ans << endl; } int main(){ cin.tie(nullptr); ios::sync_with_stdio(false); cominit(); int T=1; //cin >> T; while(T--) solve(); }