結果
問題 | No.2531 Coloring Vertices on Namori |
ユーザー |
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提出日時 | 2023-11-03 22:00:16 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 167 ms / 2,000 ms |
コード長 | 7,504 bytes |
コンパイル時間 | 1,990 ms |
コンパイル使用メモリ | 160,408 KB |
最終ジャッジ日時 | 2025-02-17 18:15:07 |
ジャッジサーバーID (参考情報) |
judge2 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 31 |
ソースコード
#pragma GCC optimize("O3")#pragma GCC optimize("unroll-loops")#include<iostream>#include<string>#include<cstdio>#include<vector>#include<cmath>#include<algorithm>#include<functional>#include<iomanip>#include<queue>#include<ciso646>#include<random>#include<map>#include<set>#include<bitset>#include<stack>#include<unordered_map>#include<unordered_set>#include<utility>#include<cassert>#include<complex>#include<numeric>#include<array>#include<chrono>using namespace std;//#define int long longtypedef long long ll;typedef unsigned long long ul;typedef unsigned int ui;//ll mod = 1;constexpr ll mod = 998244353;//constexpr ll mod = 1000000007;const int mod17 = 1000000007;const ll INF = (ll)mod17 * mod17;typedef pair<int, int>P;#define rep(i,n) for(int i=0;i<n;i++)#define per(i,n) for(int i=n-1;i>=0;i--)#define Rep(i,sta,n) for(int i=sta;i<n;i++)#define rep1(i,n) for(int i=1;i<=n;i++)#define per1(i,n) for(int i=n;i>=1;i--)#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)#define all(v) (v).begin(),(v).end()typedef pair<ll, ll> LP;using ld = double;typedef pair<ld, ld> LDP;const ld eps = 1e-10;const ld pi = acosl(-1.0);template<typename T>void chmin(T& a, T b) {a = min(a, b);}template<typename T>void chmax(T& a, T b) {a = max(a, b);}template<typename T>vector<T> vmerge(vector<T>& a, vector<T>& b) {vector<T> res;int ida = 0, idb = 0;while (ida < a.size() || idb < b.size()) {if (idb == b.size()) {res.push_back(a[ida]); ida++;}else if (ida == a.size()) {res.push_back(b[idb]); idb++;}else {if (a[ida] < b[idb]) {res.push_back(a[ida]); ida++;}else {res.push_back(b[idb]); idb++;}}}return res;}template<typename T>void cinarray(vector<T>& v) {rep(i, v.size())cin >> v[i];}template<typename T>void coutarray(vector<T>& v) {rep(i, v.size()) {if (i > 0)cout << " "; cout << v[i];}cout << "\n";}ll mod_pow(ll x, ll n, ll m = mod) {if (n < 0) {ll res = mod_pow(x, -n, m);return mod_pow(res, m - 2, m);}if (abs(x) >= m)x %= m;if (x < 0)x += m;//if (x == 0)return 0;ll res = 1;while (n) {if (n & 1)res = res * x % m;x = x * x % m; n >>= 1;}return res;}//mod should be <2^31struct modint {int n;modint() :n(0) { ; }modint(ll m) {if (m < 0 || mod <= m) {m %= mod; if (m < 0)m += mod;}n = m;}operator int() { return n; }};bool operator==(modint a, modint b) { return a.n == b.n; }bool operator<(modint a, modint b) { return a.n < b.n; }modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= (int)mod; return a; }modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += (int)mod; return a; }modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }modint operator+(modint a, modint b) { return a += b; }modint operator-(modint a, modint b) { return a -= b; }modint operator*(modint a, modint b) { return a *= b; }modint operator^(modint a, ll n) {if (n == 0)return modint(1);modint res = (a * a) ^ (n / 2);if (n % 2)res = res * a;return res;}ll inv(ll a, ll p) {return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);}modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }modint operator/=(modint& a, modint b) { a = a / b; return a; }const int max_n = 1 << 20;modint fact[max_n], factinv[max_n];void init_f() {fact[0] = modint(1);for (int i = 0; i < max_n - 1; i++) {fact[i + 1] = fact[i] * modint(i + 1);}factinv[max_n - 1] = modint(1) / fact[max_n - 1];for (int i = max_n - 2; i >= 0; i--) {factinv[i] = factinv[i + 1] * modint(i + 1);}}modint comb(int a, int b) {if (a < 0 || b < 0 || a < b)return 0;return fact[a] * factinv[b] * factinv[a - b];}modint combP(int a, int b) {if (a < 0 || b < 0 || a < b)return 0;return fact[a] * factinv[a - b];}ll gcd(ll a, ll b) {a = abs(a); b = abs(b);if (a < b)swap(a, b);while (b) {ll r = a % b; a = b; b = r;}return a;}template<typename T>void addv(vector<T>& v, int loc, T val) {if (loc >= v.size())v.resize(loc + 1, 0);v[loc] += val;}/*const int mn = 2000005;bool isp[mn];vector<int> ps;void init() {fill(isp + 2, isp + mn, true);for (int i = 2; i < mn; i++) {if (!isp[i])continue;ps.push_back(i);for (int j = 2 * i; j < mn; j += i) {isp[j] = false;}}}*///[,val)template<typename T>auto prev_itr(set<T>& st, T val) {auto res = st.lower_bound(val);if (res == st.begin())return st.end();res--; return res;}//[val,)template<typename T>auto next_itr(set<T>& st, T val) {auto res = st.lower_bound(val);return res;}using mP = pair<modint, modint>;mP operator+(mP a, mP b) {return { a.first + b.first,a.second + b.second };}mP operator+=(mP& a, mP b) {a = a + b; return a;}mP operator-(mP a, mP b) {return { a.first - b.first,a.second - b.second };}mP operator-=(mP& a, mP b) {a = a - b; return a;}LP operator+(LP a, LP b) {return { a.first + b.first,a.second + b.second };}LP operator+=(LP& a, LP b) {a = a + b; return a;}LP operator-(LP a, LP b) {return { a.first - b.first,a.second - b.second };}LP operator-=(LP& a, LP b) {a = a - b; return a;}mt19937 mt(time(0));const string drul = "DRUL";string senw = "SENW";//DRUL,or SENW//int dx[4] = { 1,0,-1,0 };//int dy[4] = { 0,1,0,-1 };//------------------------------------void solve() {int n, k; cin >> n >> k;vector<vector<int>> G(n);rep(i, n) {int a, b; cin >> a >> b; a--; b--;G[a].push_back(b);G[b].push_back(a);}vector<bool> used(n);vector<int> road;int las = -1;function<bool(int, int)> dfs = [&](int id, int fr) {used[id] = true;for (int to : G[id])if (to != fr) {if (used[to]) {las = to;road.push_back(id); return true;}else {if (dfs(to, id)) {road.push_back(id); return true;}}}return false;};dfs(0, -1);assert(las >= 0);//coutarray(road);//cout << las << "\n";rep(i, road.size())if (road[i] == las) {road.resize(i + 1);//road.erase(road.begin(), road.begin() + i);break;}vector<modint> dp = { k,0 };int m = road.size();rep(i, m - 1) {vector<modint> ndp = { 0,0 };rep(x, 2)rep(y, 2) {modint coef;if (x == 0 && y == 0)coef = 0;else if (x == 0 && y == 1)coef = k - 1;else if (x == 1 && y == 0)coef = 1;else coef = k - 2;ndp[y] += dp[x] * coef;}swap(dp, ndp);//coutarray(dp);}modint ans = dp[1];rep(i, n - m)ans *= k - 1;cout << ans << "\n";}signed main() {ios::sync_with_stdio(false);cin.tie(0);//cout << fixed<<setprecision(10);//init_f();//init();//init2();//while(true)//expr();//int t; cin >> t; rep(i, t)solve();return 0;}