結果
| 問題 |
No.2584 The University of Tree
|
| コンテスト | |
| ユーザー |
apricity
|
| 提出日時 | 2023-12-14 09:04:33 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 5,219 bytes |
| コンパイル時間 | 1,516 ms |
| コンパイル使用メモリ | 136,508 KB |
| 最終ジャッジ日時 | 2025-02-18 10:52:59 |
|
ジャッジサーバーID (参考情報) |
judge2 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 23 TLE * 1 -- * 29 |
ソースコード
#include<iostream>
#include<string>
#include<vector>
#include<algorithm>
#include<numeric>
#include<cmath>
#include<utility>
#include<tuple>
#include<cstdint>
#include<cstdio>
#include<iomanip>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<deque>
#include<unordered_map>
#include<unordered_set>
#include<bitset>
#include<cctype>
#include<chrono>
#include<random>
#include<cassert>
#include<cstddef>
#include<iterator>
#include<string_view>
#include<type_traits>
#ifdef LOCAL
# include "debug_print.hpp"
# define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)
#else
# define debug(...) (static_cast<void>(0))
#endif
using namespace std;
#define rep(i,n) for(int i=0; i<(n); i++)
#define rrep(i,n) for(int i=(n)-1; i>=0; i--)
#define FOR(i,a,b) for(int i=(a); i<(b); i++)
#define RFOR(i,a,b) for(int i=(b-1); i>=(a); i--)
#define ALL(v) v.begin(), v.end()
#define RALL(v) v.rbegin(), v.rend()
#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );
#define pb push_back
using ll = long long;
using D = double;
using LD = long double;
using P = pair<int, int>;
template<typename T> using PQ = priority_queue<T,vector<T>>;
template<typename T> using minPQ = priority_queue<T, vector<T>, greater<T>>;
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
void yesno(bool flag) {cout << (flag?"Yes":"No") << "\n";}
template<typename T, typename U>
ostream &operator<<(ostream &os, const pair<T, U> &p) {
os << p.first << " " << p.second;
return os;
}
template<typename T, typename U>
istream &operator>>(istream &is, pair<T, U> &p) {
is >> p.first >> p.second;
return is;
}
template<typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
int s = (int)v.size();
for (int i = 0; i < s; i++) os << (i ? " " : "") << v[i];
return os;
}
template<typename T>
istream &operator>>(istream &is, vector<T> &v) {
for (auto &x : v) is >> x;
return is;
}
void in() {}
template<typename T, class... U>
void in(T &t, U &...u) {
cin >> t;
in(u...);
}
void out() { cout << "\n"; }
template<typename T, class... U, char sep = ' '>
void out(const T &t, const U &...u) {
cout << t;
if (sizeof...(u)) cout << sep;
out(u...);
}
void outr() {}
template<typename T, class... U, char sep = ' '>
void outr(const T &t, const U &...u) {
cout << t;
outr(u...);
}
#include "atcoder/modint.hpp"
using mint = atcoder::modint998244353;
const int MAX_N = 200005;
int c[MAX_N];
mint ci[MAX_N];
struct edge{
int from;
int to;
int fi;
int ti;
};
edge rd[MAX_N*2];
struct var {
mint dp;
var(mint dp=0) : dp(dp){}
var merge (const var& a, const mint d, const int v, const int vi, const int vo) const {
mint delta = d * a.dp;
if (vi != -1 and vo != -1 and vi <= vo){
delta *= ci[v];
}
return {dp + delta};
}
var addRoot() const {
return {dp+1};
}
};
vector<tuple<int,int,mint>> g[MAX_N];
vector<var> dp[MAX_N];
var ans[MAX_N];
var dfs1(int v, int pv = -1, int pi = -1) {
var dpsum;
dp[v] = vector<var> (g[v].size());
rep(i, g[v].size()) {
auto [u, ei, d] = g[v][i];
if(u == pv) continue;
dp[v][i] = dfs1(u, v, ei);
dpsum = dpsum.merge(dp[v][i], d, v, pi, i);
}
return dpsum.addRoot();
}
void dfs2(int v, const var& dpParent = var(), int pv = -1, int pi = -1) {
int deg = g[v].size();
rep(i, deg) {
auto [u, ei, d] = g[v][i];
if (u == pv) {
auto tmp = var{0};
rep(j, g[u].size()){
auto [w, ej, dj] = g[u][j];
if(w == v) continue;
tmp = tmp.merge(dp[u][j], dj, u, ei, j);
}
dp[v][i] = var{tmp}.addRoot();
}
}
vector<var> dpSum_Left(deg+1), dpSum_Right(deg+1);
rep(i,deg) {
auto [u, ei, d] = g[v][i];
dpSum_Left[i+1] = dpSum_Left[i].merge(dp[v][i], d, v,-1,-1);
}
rrep(i, deg) {
auto [u, ei, d] = g[v][i];
dpSum_Right[i] = dpSum_Right[i+1].merge(dp[v][i], d, v,-1,-1);
}
ans[v] = dpSum_Left[deg].addRoot();
rep(i,deg) {
auto [u, ei, d] = g[v][i];
if(u == pv) continue;
var np{dpSum_Left[i].dp + dpSum_Right[i+1].dp};
dfs2(u, np.addRoot(), v, -1);
}
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int n; in(n);
rep(i,2*n-2) rd[i] = {-1,-1,-1,-1};
rep(i,n){
in(c[i]);
rep(j,c[i]){
int eij; in(eij); eij--;
if(rd[2*eij].from == -1) rd[2*eij].from = i, rd[2*eij].fi = j;
else rd[2*eij].to = i, rd[2*eij].ti = j;
}
c[i]++;
}
rep(i,n-1){
auto [x,y,z,w] = rd[2*i];
rd[2*i+1] = {y,x,w,z};
}
rep(i,n) g[i].assign(c[i]-1,{0,0,0});
rep(i,2*n-2){
auto [x,y,z,w] = rd[i];
mint d = mint(x+1).pow(z+1) * mint(y+1).pow(c[y]-w-1);
g[x][z] = {y,w,d};
}
rep(i,n) ci[i] = mint(i+1).inv().pow(c[i]);
dfs1(0);
dfs2(0);
rep(i,n) out((ans[i].dp-1).val());
}
apricity