結果
問題 | No.2603 Tone Correction |
ユーザー |
👑 |
提出日時 | 2024-01-12 22:16:49 |
言語 | D (dmd 2.109.1) |
結果 |
AC
|
実行時間 | 105 ms / 2,000 ms |
コード長 | 2,113 bytes |
コンパイル時間 | 2,307 ms |
コンパイル使用メモリ | 123,248 KB |
実行使用メモリ | 25,460 KB |
最終ジャッジ日時 | 2024-09-27 22:45:05 |
合計ジャッジ時間 | 6,060 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 33 |
ソースコード
import std.conv, std.functional, std.range, std.stdio, std.string;import std.algorithm, std.array, std.bigint, std.bitmanip, std.complex, std.container, std.math, std.mathspecial, std.numeric, std.regex, std.typecons;import core.bitop;class EOFException : Throwable { this() { super("EOF"); } }string[] tokens;string readToken() { for (; tokens.empty; ) { if (stdin.eof) { throw new EOFException; } tokens = readln.split; } auto token = tokens.front; tokens.popFront; return token; }int readInt() { return readToken.to!int; }long readLong() { return readToken.to!long; }string COLOR(string s = "") { return "\x1b[" ~ s ~ "m"; }bool chmin(T)(ref T t, in T f) { if (t > f) { t = f; return true; } else { return false; } }bool chmax(T)(ref T t, in T f) { if (t < f) { t = f; return true; } else { return false; } }int binarySearch(alias pred, T)(in T[] as) { int lo = -1, hi = cast(int)(as.length); for (; lo + 1 < hi; ) { const mid = (lo + hi) >> 1;(unaryFun!pred(as[mid]) ? hi : lo) = mid; } return hi; }int lowerBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a >= val)); }int upperBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a > val)); }void main() {try {for (; ; ) {const N = readInt;const M = readLong;auto A = new long[N + 2]; foreach (i; 1 .. N + 1) A[i] = readLong;auto B = new long[N + 2]; foreach (i; 1 .. N + 1) B[i] = readLong;auto C = new long[N + 2];foreach (i; 1 .. N + 1) {C[i] = (A[i] - B[i]) % M;if (C[i] < 0) C[i] += M;}auto D = new long[N + 1];foreach (i; 0 .. N + 1) {D[i] = C[i + 1] - C[i];if (D[i] < 0) D[i] += M;}const sumD = D.sum;debug {writeln("D = ", D);writeln("sumD = ", sumD);}auto costs = new long[N + 1];foreach (i; 0 .. N + 1) {costs[i] = (M - D[i]) - D[i];}costs.sort;long ans;ans += sumD;ans += costs[0 .. sumD / M].sum;ans /= 2;writeln(ans);}} catch (EOFException e) {}}