結果
問題 | No.2625 Bouns Ai |
ユーザー |
|
提出日時 | 2024-02-09 22:54:19 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 232 ms / 2,000 ms |
コード長 | 4,926 bytes |
コンパイル時間 | 1,618 ms |
コンパイル使用メモリ | 175,424 KB |
実行使用メモリ | 160,876 KB |
最終ジャッジ日時 | 2024-09-28 16:05:19 |
合計ジャッジ時間 | 7,298 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 23 |
ソースコード
#include <bits/stdc++.h>using namespace std;#define double long doubleusing ll = long long;using ull = unsigned long long;using VB = vector<bool>;using VVB = vector<VB>;using VVVB = vector<VVB>;using VC = vector<char>;using VVC = vector<VC>;using VI = vector<int>;using VVI = vector<VI>;using VVVI = vector<VVI>;using VVVVI = vector<VVVI>;using VL = vector<ll>;using VVL = vector<VL>;using VVVL = vector<VVL>;using VVVVL = vector<VVVL>;using VVVVVL = vector<VVVVL>;using VD = vector<double>;using VVD = vector<VD>;using VVVD = vector<VVD>;//using P = pair<int, int>;#define REP(i, n) for (ll i = 0; i < (int)(n); i++)#define FOR(i, a, b) for (ll i = a; i < (ll)(b); i++)#define ALL(a) (a).begin(),(a).end()constexpr int INF = 1001001001;constexpr ll LINF = 1001001001001001001ll;constexpr int DX[] = {1, 0, -1, 0};constexpr int DY[] = {0, 1, 0, -1};template< typename T1, typename T2>inline bool chmax(T1 &a, T2 b) {return a < b && (a = b, true); }template< typename T1, typename T2>inline bool chmin(T1 &a, T2 b) {return a > b && (a = b, true); }const ll MOD = 998244353;//const ll MOD = 1000000007;/*const int MAX_N = 1000000;int par[MAX_N];int rnk[MAX_N];int siz[MAX_N];void init(int n) {REP(i,n) {par[i] = i;rnk[i] = 0;siz[i] = 1;}}int find(int x) {if (par[x] == x) {return x;} else {return par[x] = find(par[x]);}}void unite(int x, int y) {x = find(x);y = find(y);if (x == y) return;int s = siz[x] + siz[y];if (rnk[x] < rnk[y]) {par[x] = y;} else {par[y] = x;if (rnk[x] == rnk[y]) rnk[x]++;}siz[find(x)] = s;}bool same(int x, int y) {return find(x) == find(y);}int size(int x) {return siz[find(x)];}*/ll mod_pow(ll x, ll n, ll mod) {ll res = 1;x %= mod;while (n > 0) {if (n & 1) res = res * x % mod;x = x * x % mod;n >>= 1;}return res;}ll gcd(ll x, ll y) {if (y == 0) return x;return gcd(y, x % y);}/*typedef pair<ll, int> P0;struct edge { int to; ll cost; };const int MAX_V = 12960001;//const ll LINF = 1LL<<60;int V;vector<edge> G[MAX_V];ll D[MAX_V];void dijkstra(ll s) {priority_queue<P0, vector<P0>, greater<P0> > que;fill(D, D + V, LINF);D[s] = 0;que.push(P0(0, s));while (!que.empty()) {P0 p = que.top(); que.pop();int v = p.second;if (D[v] < p.first) continue;for (edge e : G[v]) {if (D[e.to] > D[v] + e.cost) {D[e.to] = D[v] + e.cost;que.push(P0(D[e.to], e.to));}}}}*//*double EPS = 1e-10;double add(double a, double b) {if (abs(a + b) < EPS * (abs(a) + abs(b))) return 0;return a + b;}struct P {double x, y;P() {}P(double x, double y) : x(x), y(y) {}P operator + (P p) {return P(add(x, p.x), add(y, p.y));}P operator - (P p) {return P(add(x, -p.x), add(y, -p.y));}P operator * (double d) {return P(x * d, y * d);}double dot(P p) {return add(x * p.x, y * p.y);}double det(P p) {return add(x * p.y, -y * p.x);}};bool on_seg(P p1, P p2, P q) {return ()}P intersection(P p1, P p2, P q1, P q2) {return p1 + (p2 - p1) * ((q2 - q1).det(q1 - p1) / (q2 - q1).det(p2 - p1));}*//*VL f(400010, 1);ll C(ll n, ll k) {return f[n] * mod_pow(f[k], MOD - 2, MOD) % MOD * mod_pow(f[n - k], MOD - 2, MOD) % MOD;}*/bool fcomp(const VL& a, const VL& b) {if (a[0] * (b[0] + b[1]) > b[0] * (a[0] + a[1])) return true;if (a[0] * (b[0] + b[1]) < b[0] * (a[0] + a[1])) return false;return a[2] < b[2];}int main() {ios::sync_with_stdio(false);std::cin.tie(nullptr);// dp[i][j] i人目の真のスコアがjである場合の数// dp[i][j + 1] = dp[i][j] + d[j];int n;cin >> n;VI a(n);REP(i, n) cin >> a[i];//cout << a[0] << endl;VVL dp(n, VL(100001, 0));VL d(100000, 0);//cout << a[0] << endl;if (a[0] == 0) dp[0][0] = 1;else d[a[0] - 1] = 1;REP(i, n) {REP(j, 100000) {dp[i][j + 1] = (dp[i][j] + d[j]) % MOD;}if (i == n - 1) break;REP(j, 100000) d[j] = 0;FOR(j, a[i], 1000000) {int b = j - a[i];int x = max(b + a[i + 1], int(j));if (x > 100000) break;if (x == 0) dp[i + 1][0] = (dp[i + 1][0] + dp[i][j]) % MOD;else d[x - 1] = (d[x - 1] + dp[i][j]) % MOD;}}ll ans = 0;REP(i, 100001) ans = (ans + dp[n - 1][i]) % MOD;cout << ans << endl;/*REP(i, n) {REP(j, 3) cout << dp[i][j] << " ";FOR(j, 99997, 100001) cout << dp[i][j] << " ";cout << endl;}*/}