結果
問題 | No.2645 Sum of Divisors? |
ユーザー | tokusakurai |
提出日時 | 2024-02-19 22:55:36 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 136 ms / 2,000 ms |
コード長 | 5,125 bytes |
コンパイル時間 | 1,987 ms |
コンパイル使用メモリ | 209,872 KB |
実行使用メモリ | 85,484 KB |
最終ジャッジ日時 | 2024-09-29 02:41:04 |
合計ジャッジ時間 | 4,493 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 23 ms
34,584 KB |
testcase_01 | AC | 20 ms
34,816 KB |
testcase_02 | AC | 86 ms
84,252 KB |
testcase_03 | AC | 21 ms
34,684 KB |
testcase_04 | AC | 20 ms
34,580 KB |
testcase_05 | AC | 20 ms
34,912 KB |
testcase_06 | AC | 133 ms
84,864 KB |
testcase_07 | AC | 136 ms
84,632 KB |
testcase_08 | AC | 22 ms
34,680 KB |
testcase_09 | AC | 20 ms
34,848 KB |
testcase_10 | AC | 21 ms
34,684 KB |
testcase_11 | AC | 20 ms
34,644 KB |
testcase_12 | AC | 20 ms
34,844 KB |
testcase_13 | AC | 20 ms
34,760 KB |
testcase_14 | AC | 19 ms
34,644 KB |
testcase_15 | AC | 20 ms
34,852 KB |
testcase_16 | AC | 19 ms
35,052 KB |
testcase_17 | AC | 21 ms
34,816 KB |
testcase_18 | AC | 20 ms
34,964 KB |
testcase_19 | AC | 20 ms
35,092 KB |
testcase_20 | AC | 21 ms
35,180 KB |
testcase_21 | AC | 20 ms
35,128 KB |
testcase_22 | AC | 21 ms
35,448 KB |
testcase_23 | AC | 24 ms
36,088 KB |
testcase_24 | AC | 33 ms
41,212 KB |
testcase_25 | AC | 32 ms
42,016 KB |
testcase_26 | AC | 37 ms
40,844 KB |
testcase_27 | AC | 42 ms
47,300 KB |
testcase_28 | AC | 62 ms
60,200 KB |
testcase_29 | AC | 134 ms
85,484 KB |
testcase_30 | AC | 65 ms
59,560 KB |
testcase_31 | AC | 92 ms
84,604 KB |
testcase_32 | AC | 112 ms
85,328 KB |
testcase_33 | AC | 68 ms
60,244 KB |
testcase_34 | AC | 108 ms
84,344 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #define rep(i, n) for (int i = 0; i < (n); i++) #define per(i, n) for (int i = (n)-1; i >= 0; i--) #define rep2(i, l, r) for (int i = (l); i < (r); i++) #define per2(i, l, r) for (int i = (r)-1; i >= (l); i--) #define each(e, v) for (auto &e : v) #define MM << " " << #define pb push_back #define eb emplace_back #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define sz(x) (int)x.size() using ll = long long; using pii = pair<int, int>; using pil = pair<int, ll>; using pli = pair<ll, int>; using pll = pair<ll, ll>; template <typename T> using minheap = priority_queue<T, vector<T>, greater<T>>; template <typename T> using maxheap = priority_queue<T>; template <typename T> bool chmax(T &x, const T &y) { return (x < y) ? (x = y, true) : false; } template <typename T> bool chmin(T &x, const T &y) { return (x > y) ? (x = y, true) : false; } template <typename T> int flg(T x, int i) { return (x >> i) & 1; } int pct(int x) { return __builtin_popcount(x); } int pct(ll x) { return __builtin_popcountll(x); } int topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); } int topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); } int botbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); } int botbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); } template <typename T> void print(const vector<T> &v, T x = 0) { int n = v.size(); for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' '); if (v.empty()) cout << '\n'; } template <typename T> void printn(const vector<T> &v, T x = 0) { int n = v.size(); for (int i = 0; i < n; i++) cout << v[i] + x << '\n'; } template <typename T> int lb(const vector<T> &v, T x) { return lower_bound(begin(v), end(v), x) - begin(v); } template <typename T> int ub(const vector<T> &v, T x) { return upper_bound(begin(v), end(v), x) - begin(v); } template <typename T> void rearrange(vector<T> &v) { sort(begin(v), end(v)); v.erase(unique(begin(v), end(v)), end(v)); } template <typename T> vector<int> id_sort(const vector<T> &v, bool greater = false) { int n = v.size(); vector<int> ret(n); iota(begin(ret), end(ret), 0); sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; }); return ret; } template <typename T> void reorder(vector<T> &a, const vector<int> &ord) { int n = a.size(); vector<T> b(n); for (int i = 0; i < n; i++) b[i] = a[ord[i]]; swap(a, b); } template <typename T> T floor(T x, T y) { assert(y != 0); if (y < 0) x = -x, y = -y; return (x >= 0 ? x / y : (x - y + 1) / y); } template <typename T> T ceil(T x, T y) { assert(y != 0); if (y < 0) x = -x, y = -y; return (x >= 0 ? (x + y - 1) / y : x / y); } template <typename S, typename T> pair<S, T> operator+(const pair<S, T> &p, const pair<S, T> &q) { return make_pair(p.first + q.first, p.second + q.second); } template <typename S, typename T> pair<S, T> operator-(const pair<S, T> &p, const pair<S, T> &q) { return make_pair(p.first - q.first, p.second - q.second); } template <typename S, typename T> istream &operator>>(istream &is, pair<S, T> &p) { S a; T b; is >> a >> b; p = make_pair(a, b); return is; } template <typename S, typename T> ostream &operator<<(ostream &os, const pair<S, T> &p) { return os << p.first << ' ' << p.second; } struct io_setup { io_setup() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout << fixed << setprecision(15); cerr << fixed << setprecision(15); } } io_setup; constexpr int inf = (1 << 30) - 1; constexpr ll INF = (1LL << 60) - 1; // constexpr int MOD = 1000000007; constexpr int MOD = 998244353; // (x,l,r) template <typename T> vector<tuple<T, T, T>> quotient_floor_enumerate(T n) { vector<tuple<T, T, T>> ret; for (T l = 1; l <= n;) { T x = n / l; T r = n / x + 1; ret.emplace_back(x, l, r); l = r; } return ret; } // (x,l,r) template <typename T> vector<tuple<T, T, T>> quotient_ceil_enumerate(T n) { vector<tuple<T, T, T>> ret; for (T l = 1; l <= n;) { T x = (n + l - 1) / l; T r = (x == 1 ? n + 1 : (n + x - 2) / (x - 1)); ret.emplace_back(x, l, r); l = r; } return ret; } void solve() { using ld = long double; ll N; cin >> N; int MAX = 2000000; vector<ld> a(MAX + 1); rep2(i, 1, MAX + 1) a[i] = ld(1.0) / ld(i); rep2(i, 1, MAX + 1) a[i] += a[i - 1]; // a.resize(10); // print(a); const ld gamma = 0.57721566490153286060; auto get = [&](ll n) { if (n <= MAX) return a[n]; return log(n + 1) + ld(n) / ld(2 * (n + 1)) + gamma - 0.5; }; ld ans = 0; for (auto [x, l, r] : quotient_floor_enumerate(N)) { ld p = get(x); ld q = get(r - 1) - get(l - 1); ans += p * q; // cout << x MM l MM r MM p MM q << endl; } cout << ans << '\n'; } int main() { int T = 1; // cin >> T; while (T--) solve(); }