結果
| 問題 |
No.2664 Prime Sum
|
| コンテスト | |
| ユーザー |
soto800
|
| 提出日時 | 2024-03-08 21:14:20 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 3 ms / 2,000 ms |
| コード長 | 6,007 bytes |
| コンパイル時間 | 1,866 ms |
| コンパイル使用メモリ | 205,668 KB |
| 最終ジャッジ日時 | 2025-02-20 02:01:33 |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 37 |
ソースコード
#include <bits/stdc++.h>
//#include <atcoder/all>
using namespace std;
#define lli long long int
#define REP(i, s, n) for (lli i = s; i < n; i++)
#define INF (1LL << 62)
#define mp(a, b) make_pair(a, b)
#define SORT(V) sort(V.begin(), V.end())
#define PI (3.141592653589794)
#define TO_STRING(VariableName) #VariableName
#define LOG1(x) \
if (DEBUG) \
cout << TO_STRING(x) << "=" << x << " " << endl;
#define LOG2(x, y) \
if (DEBUG) \
cout << TO_STRING(x) << "=" << x << " " << TO_STRING(y) << "=" << y << endl;
#define LOG3(x, y, z) \
if (DEBUG) \
cout << TO_STRING(x) << "=" << x << " " << TO_STRING(y) << "=" << y << " " \
<< TO_STRING(z) << "=" << z << endl;
#define LOG4(w, x, y, z) \
if (DEBUG) \
cout << TO_STRING(w) << "=" << w << " " << TO_STRING(x) << "=" << x << " " \
<< TO_STRING(y) << "=" << y << " " << TO_STRING(z) << "=" << z \
<< endl;
#define LOG5(w, x, y, z, a) \
if (DEBUG) \
cout << TO_STRING(w) << "=" << w << " " << TO_STRING(x) << "=" << x << " " \
<< TO_STRING(y) << "=" << y << " " << TO_STRING(z) << "=" << z << " " \
<< TO_STRING(a) << "=" << a << endl;
#define LOG6(w, x, y, z, a, b) \
if (DEBUG) \
cout << TO_STRING(w) << "=" << w << " " << TO_STRING(x) << "=" << x << " " \
<< TO_STRING(y) << "=" << y << " " << TO_STRING(z) << "=" << z << " " \
<< TO_STRING(a) << "=" << a << " " << TO_STRING(b) << "=" << b \
<< endl;
#define overload6(a, b, c, d, e, f, g, ...) g
#define LOG(...) \
overload6(__VA_ARGS__, LOG6, LOG5, LOG4, LOG3, LOG2, LOG1)(__VA_ARGS__)
template <class T> bool chmax(T &a, const T &b) {
if (a < b) {
a = b;
return 1;
}
return 0;
}
template <class T> bool chmin(T &a, const T &b) {
if (b < a) {
a = b;
return 1;
}
return 0;
}
mt19937 engine;
std::chrono::system_clock::time_point start, endTime;
std::ostream &operator<<(std::ostream &dest, __int128_t value) {
std::ostream::sentry s(dest);
if (s) {
__uint128_t tmp = value < 0 ? -value : value;
char buffer[128];
char *d = std::end(buffer);
do {
--d;
*d = "0123456789"[tmp % 10];
tmp /= 10;
} while (tmp != 0);
if (value < 0) {
--d;
*d = '-';
}
int len = std::end(buffer) - d;
if (dest.rdbuf()->sputn(d, len) != len) {
dest.setstate(std::ios_base::badbit);
}
}
return dest;
}
__int128 parse(string &s) {
__int128 ret = 0;
for (int i = 0; i < s.length(); i++) {
if ('0' <= s[i] && s[i] <= '9') {
ret = 10 * ret + s[i] - '0';
}
}
return ret;
}
#define DEBUG 0
// checker https://atcoder.jp/contests/abc264/tasks/abc264_e
struct UnionFind {
vector<int> par; // par[i]:iの親の番号 (例) par[3] = 2 : 3の親が2
vector<bool> isOk;
vector<lli> siz; // 素集合のサイズを表す配列(1 で初期化)
lli N;
UnionFind(int N)
: par(N), isOk(N), siz(N) { //最初は全てが根であるとして初期化
for (int i = 0; i < N; i++) {
par[i] = i;
isOk[i] = false;
siz[i] = 1;
}
this->N = N;
}
int root(int x) { // データxが属する木の根を再帰で得る:root(x) = {xの木の根}
if (par[x] == x)
return x;
return par[x] = root(par[x]);
}
void setOk(lli i) { isOk[i] = isOk[root(i)] = true; }
bool isCheckOk(lli i) { return isOk[root(i)]; }
void unite(int x, int y) { // xとyの木を併合
int rx = root(x); // xの根をrx
int ry = root(y); // yの根をry
if (rx == ry)
return; // xとyの根が同じ(=同じ木にある)時はそのまま
if (siz[rx] < siz[ry])
swap(rx, ry);
siz[rx] += siz[ry];
par[ry] =
rx; // xとyの根が同じでない(=同じ木にない)時:xの根rxをyの根ryにつける
if (isOk[rx] || isOk[ry]) {
isOk[ry] = true;
isOk[rx] = true;
}
}
bool same(int x, int y) { // 2つのデータx, yが属する木が同じならtrueを返す
int rx = root(x);
int ry = root(y);
return rx == ry;
}
lli size(lli x) { return siz[root(x)]; }
};
lli color[110];
void solve() {
// write your code here
lli N, M;
cin >> N >> M;
vector<lli> A(M), B(M);
vector<vector<lli>> G(N);
REP(i, 0, M) {
cin >> A[i] >> B[i];
A[i]--;
B[i]--;
G[A[i]].push_back(B[i]);
G[B[i]].push_back(A[i]);
}
REP(i, 0, N) color[i] = -1;
REP(i, 0, N) {
if (color[i] != -1)
continue;
queue<lli> q;
q.push(i);
color[i] = 0;
while (q.size()) {
lli now = q.front();
q.pop();
for (auto next : G[now]) {
if (color[next] == -1) {
color[next] = 1 - color[now];
q.push(next);
} else {
if (color[next] == color[now]) {
cout << "No" << endl;
return;
}
}
}
}
}
cout << "Yes" << endl;
}
// Generated by 2.13.0 https://github.com/kyuridenamida/atcoder-tools (tips:
// You use the default template now. You can remove this line by using your
// custom template)
int main() {
// Failed to predict input format
lli N = 1;
// cin >> N;
while (N--)
solve();
return 0;
}
soto800